大多数给出的答案都很慢或很慢，或者对负数不适用。

试试这个:

}
    //
    //
    ///<summary>Format a value with a fixed number of digits.</summary>
    public static string Pad( this long v, int digits ) {
        int negative = 0;
        if ( v < 0 ) {
            negative = 1;
            v = Math.Abs( v );
        }
        var source = v.ToString();
        var length = source.Length;
        int max = length;
        if ( max < digits ) {
            max = digits;
        }
        max += negative;
        var ca = new char[ max ];
        for ( int i = 0; i < max; i++ ) {
            ca[ i ] = '0';
        }
        while ( length > 0 ) {
            ca[ --max ] = source[ --length ];
        }
        if ( 0 != negative ) ca[ 0 ] = '-';
        return new string( ca );
    }

i.ToString("0000");

. net在String类中有一个简单的函数可以做到这一点。 只使用:

.ToString().PadLeft(4, '0')  // that will fill your number with 0 on the left, up to 4 length

int i = 1; 
i.toString().PadLeft(4,'0')  // will return "0001"  

public static string ToLeadZeros(this int strNum, int num)
{
    var str = strNum.ToString();
    return str.PadLeft(str.Length + num, '0');
}

// var i = 1;
// string num = i.ToLeadZeros(5);

你可以使用:

int x = 1;
x.ToString("0000");

这里有一个很好的例子:

int number = 1;
//D4 = pad with 0000
string outputValue = String.Format("{0:D4}", number);
Console.WriteLine(outputValue);//Prints 0001
//OR
outputValue = number.ToString().PadLeft(4, '0');
Console.WriteLine(outputValue);//Prints 0001 as well