尝试json_encode对数据进行编码，并设置带有header的content-type (' content-type: application/json');

<?php
$data = /** whatever you're serializing **/;
header("Content-type: application/json; charset=utf-8");
echo json_encode($data);
?>

您可以使用这个小型PHP库。它发送头文件并给你一个容易使用它的对象。

它看起来是这样的:

<?php
// Include the json class
include('includes/json.php');

// Then create the PHP-Json Object to suits your needs

// Set a variable ; var name = {}
$Json = new json('var', 'name'); 
// Fire a callback ; callback({});
$Json = new json('callback', 'name'); 
// Just send a raw JSON ; {}
$Json = new json();

// Build data
$object = new stdClass();
$object->test = 'OK';
$arraytest = array('1','2','3');
$jsonOnly = '{"Hello" : "darling"}';

// Add some content
$Json->add('width', '565px');
$Json->add('You are logged IN');
$Json->add('An_Object', $object);
$Json->add("An_Array",$arraytest);
$Json->add("A_Json",$jsonOnly);

// Finally, send the JSON.

$Json->send();
?>

如果你想要js对象，使用头content-type:

<?php
$data = /** whatever you're serializing **/;
header('Content-Type: application/json; charset=utf-8');
echo json_encode($data);

如果你只想要json: remove header content-type属性，只需要encode和echo。

<?php
$data = /** whatever you're serializing **/;
echo json_encode($data);

返回JSON的完整的PHP代码如下:

$option = $_GET['option'];

if ( $option == 1 ) {
    $data = [ 'a', 'b', 'c' ];
    // will encode to JSON array: ["a","b","c"]
    // accessed as example in JavaScript like: result[1] (returns "b")
} else {
    $data = [ 'name' => 'God', 'age' => -1 ];
    // will encode to JSON object: {"name":"God","age":-1}  
    // accessed as example in JavaScript like: result.name or result['name'] (returns "God")
}

header('Content-type: application/json');
echo json_encode( $data );

虽然你通常没有它也没问题，但你可以也应该设置Content-Type头文件:

<?php
$data = /** whatever you're serializing **/;
header('Content-Type: application/json; charset=utf-8');
echo json_encode($data);

如果我没有使用特定的框架，我通常允许一些请求参数修改输出行为。通常对于快速故障排除，不发送报头或有时print_r数据有效负载来观察它(尽管在大多数情况下，这应该是不必要的)是很有用的。