我有一个带有文本框的DetailsView 我希望输入的数据总是以大写的第一个字母保存。

例子:

"red" --> "Red"
"red house" --> " Red house"

我怎样才能实现性能最大化呢?


注意:

Based on the answers and the comments under the answers, many people think this is asking about capitalizing all words in the string. E.g. => Red House It isn't, but if that is what you seek, look for one of the answers that uses TextInfo's ToTitleCase method. (Note: Those answers are incorrect for the question actually asked.) See TextInfo.ToTitleCase documentation for caveats (doesn't touch all-caps words - they are considered acronyms; may lowercase letters in middle of words that "shouldn't" be lowered, e.g., "McDonald" → "Mcdonald"; not guaranteed to handle all culture-specific subtleties re capitalization rules.)


注意:

第一个字母之后的字母是否必须小写,这个问题很模糊。公认的答案假定只有第一个字母需要修改。如果要强制字符串中除第一个字母外的所有字母都小写,请查找包含ToLower且不包含ToTitleCase的答案。


当前回答

我在c#大写首字母- Dot Net Perls中找到了一些东西:

static string UppercaseFirst(string s)
{
    // Check for empty string.
    if (string.IsNullOrEmpty(s))
    {
        return string.Empty;
    }

    // Return char and concat substring.
    return char.ToUpper(s[0]) + s.Substring(1);
}

其他回答

下面的函数对所有方式都是正确的:

static string UppercaseWords(string value)
{
    char[] array = value.ToCharArray();
    // Handle the first letter in the string.
    if (array.Length >= 1)
    {
        if (char.IsLower(array[0]))
        {
            array[0] = char.ToUpper(array[0]);
        }
    }
    // Scan through the letters, checking for spaces.
    // ... Uppercase the lowercase letters following spaces.
    for (int i = 1; i < array.Length; i++)
    {
        if (array[i - 1] == ' ')
        {
            if (char.IsLower(array[i]))
            {
                array[i] = char.ToUpper(array[i]);
            }
        }
    }
    return new string(array);
}

我在这里找到的。

由于这个问题是关于最大化性能的,我采用了Darren的版本来使用跨度,这减少了垃圾,并提高了大约10%的速度。

/// <summary>
/// Returns the input string with the first character converted to uppercase
/// </summary>
public static string ToUpperFirst(this string s)
{
    if (string.IsNullOrEmpty(s))
        throw new ArgumentException("There is no first letter");

    Span<char> a = stackalloc char[s.Length];
    s.AsSpan(1).CopyTo(a.Slice(1));
    a[0] = char.ToUpper(s[0]);
    return new string(a);
}

性能

Method Data Mean Error StdDev
Carlos red 107.29 ns 2.2401 ns 3.9234 ns
Darren red 30.93 ns 0.9228 ns 0.8632 ns
Marcell red 26.99 ns 0.3902 ns 0.3459 ns
Carlos red house 106.78 ns 1.9713 ns 1.8439 ns
Darren red house 32.49 ns 0.4253 ns 0.3978 ns
Marcell red house 27.37 ns 0.3888 ns 0.3637 ns

完整的测试代码

using System;
using System.Linq;

using BenchmarkDotNet.Attributes;

namespace CorePerformanceTest
{
    public class StringUpperTest
    {
        [Params("red", "red house")]
        public string Data;

        [Benchmark]
        public string Carlos() => Data.Carlos();

        [Benchmark]
        public string Darren() => Data.Darren();

        [Benchmark]
        public string Marcell() => Data.Marcell();
    }

    internal static class StringExtensions
    {
        public static string Carlos(this string input) =>
            input switch
            {
                null => throw new ArgumentNullException(nameof(input)),
                "" => throw new ArgumentException($"{nameof(input)} cannot be empty", nameof(input)),
                _ => input.First().ToString().ToUpper() + input.Substring(1)
            };

        public static string Darren(this string s)
        {
            if (string.IsNullOrEmpty(s))
                throw new ArgumentException("There is no first letter");

            char[] a = s.ToCharArray();
            a[0] = char.ToUpper(a[0]);
            return new string(a);
        }

        public static string Marcell(this string s)
        {
            if (string.IsNullOrEmpty(s))
                throw new ArgumentException("There is no first letter");

            Span<char> a = stackalloc char[s.Length];
            s.AsSpan(1).CopyTo(a.Slice(1));
            a[0] = char.ToUpper(s[0]);
            return new string(a);
        }
    }

}
string s_Val = "test";
if (s_Val != "")
{
   s_Val  = char.ToUpper(s_Val[0]);
   if (s_Val.Length > 1)
   {
      s_Val += s_Val.Substring(1);
   }
 }

我认为下面的方法是最好的解决方案。

class Program
{
    static string UppercaseWords(string value)
    {
        char[] array = value.ToCharArray();
        // Handle the first letter in the string.
        if (array.Length >= 1)
        {
            if (char.IsLower(array[0]))
            {
                array[0] = char.ToUpper(array[0]);
            }
        }
        // Scan through the letters, checking for spaces.
        // ... Uppercase the lowercase letters following spaces.
        for (int i = 1; i < array.Length; i++)
        {
            if (array[i - 1] == ' ')
            {
                if (char.IsLower(array[i]))
                {
                    array[i] = char.ToUpper(array[i]);
                }
            }
        }
        return new string(array);
    }

    static void Main()
    {
        // Uppercase words in these strings.
        const string value1 = "something in the way";
        const string value2 = "dot net PERLS";
        const string value3 = "String_two;three";
        const string value4 = " sam";
        // ... Compute the uppercase strings.
        Console.WriteLine(UppercaseWords(value1));
        Console.WriteLine(UppercaseWords(value2));
        Console.WriteLine(UppercaseWords(value3));
        Console.WriteLine(UppercaseWords(value4));
    }
}

Output

Something In The Way
Dot Net PERLS
String_two;three
 Sam

参考

最简单和最快的方法是将字符串的第一个字符替换为大写字符:

string str = "test";<br>
str = str.Replace(str[0], char.ToUpper(str[0]));