我有一个名为theImageView的UIImageView, UIImage是单色的(透明背景),就像下面左边的黑色心形。我如何在iOS 7或更高的系统中,根据iOS 7+导航栏图标中使用的色调方法,以编程方式更改此图像的色调颜色?

这个方法也适用于WatchKit的Apple Watch应用程序吗?


当前回答

子类,也可以从代码和接口生成器中使用:

@implementation TintedImageView

- (instancetype)initWithFrame:(CGRect)frame {
    self = [super initWithFrame:frame];
    if (self) {
        [self setup];
    }
    return self;
}

- (instancetype)initWithCoder:(NSCoder *)aDecoder {
    self = [super initWithCoder:aDecoder];
    if (self) {
        [self setup];
    }
    return self;
}

-(void)setup {
    self.image = [self.image imageWithRenderingMode:UIImageRenderingModeAlwaysTemplate];
}

@end

其他回答

子类,也可以从代码和接口生成器中使用:

@implementation TintedImageView

- (instancetype)initWithFrame:(CGRect)frame {
    self = [super initWithFrame:frame];
    if (self) {
        [self setup];
    }
    return self;
}

- (instancetype)initWithCoder:(NSCoder *)aDecoder {
    self = [super initWithCoder:aDecoder];
    if (self) {
        [self setup];
    }
    return self;
}

-(void)setup {
    self.image = [self.image imageWithRenderingMode:UIImageRenderingModeAlwaysTemplate];
}

@end
let navHeight = self.navigationController?.navigationBar.frame.height;
let menuBtn = UIButton(type: .custom)
menuBtn.frame = CGRect(x: 0, y: 0, width: 45, height: navHeight!)     
menuBtn.setImage(UIImage(named:"image_name")!.withRenderingMode(.alwaysTemplate), for: .normal)        
menuBtn.tintColor = .black

利用Swift中的扩展:-

extension UIImageView {
    func changeImageColor( color:UIColor) -> UIImage
    {
        image = image!.withRenderingMode(.alwaysTemplate)
        tintColor = color
        return image!
    }
}

   //Change color of logo 
   logoImage.image =  logoImage.changeImageColor(color: .red)

在故事板和图像资产中。你也可以改变这两个:

更新渲染模式为模板图像

更新视图中的色调颜色。

与迅速

let commentImageView = UIImageView(frame: CGRectMake(100, 100, 100, 100))
commentImageView.image = UIImage(named: "myimage.png")!.imageWithRenderingMode(UIImageRenderingMode.AlwaysTemplate)
commentImageView.tintColor = UIColor.blackColor()
addSubview(commentImageView)