/****** Script for SelectTopNRows command from SSMS  ******/
SELECT TOP 10 [Id]
  ,[Id_parvandeh]
  ,[FirstName]
  ,[LastName]
  ,[RegDate]
  ,[Gilder]
  ,[Nationality]
  ,[Educ]
  ,[PhoneNumber]
  ,[DueInMashhad]

  ,[EzdevajDate]


  ,[MarriageStatus]
  ,[Gender]
  ,[Photo]

  ,[ModifiedOn]
  ,[CreatorIp]
   From
  [dbo].[Socials] where educ >= 3 or EzdevajDate  >= '1992/03/31' and EzdevajDate <= '2019/03/09' and MarriageStatus = 1

我喜欢使用1 MonthName 2015语法来表示日期:

   WHERE aa.AuditDate>='1 September 2015'
     AND aa.AuditDate<='30 September 2015'

对日期

/****** Script for SelectTopNRows command from SSMS  ******/
SELECT TOP 10 [Id]
  ,[Id_parvandeh]
  ,[FirstName]
  ,[LastName]
  ,[RegDate]
  ,[Gilder]
  ,[Nationality]
  ,[Educ]
  ,[PhoneNumber]
  ,[DueInMashhad]

  ,[EzdevajDate]


  ,[MarriageStatus]
  ,[Gender]
  ,[Photo]

  ,[ModifiedOn]
  ,[CreatorIp]
   From
  [dbo].[Socials] where educ >= 3 or EzdevajDate  >= '1992/03/31' and EzdevajDate <= '2019/03/09' and MarriageStatus = 1

SELECT Date, TotalAllowance  
FROM Calculation  
WHERE EmployeeId = 1 
  AND Date BETWEEN to_date('2011/02/25','yyyy-mm-dd') 
               AND to_date ('2011/02/27','yyyy-mm-dd');

SELECT CITY, COUNT(EID) OCCURENCES FROM EMP 
WHERE DOB BETWEEN '31-JAN-1900' AND '31-JAN-2900' 
GROUP BY CITY 
HAVING COUNT(EID) > 2;

该查询将查找DOB位于员工指定时间范围内的次数超过2次的城市。

我们可以使用between来显示两个日期数据，但这将搜索整个数据并进行比较，因此对于巨大的数据，它会使我们的过程变慢，所以我建议每个人都使用datediff:

qry = "SELECT * FROM [calender] WHERE datediff(day,'" & dt & "',[date])>=0 and datediff(day,'" & dt2 & "',[date])<=0 "

这里的日历是表，dt作为开始日期变量，dt2是结束日期变量。