我们可以使用between来显示两个日期数据，但这将搜索整个数据并进行比较，因此对于巨大的数据，它会使我们的过程变慢，所以我建议每个人都使用datediff:

qry = "SELECT * FROM [calender] WHERE datediff(day,'" & dt & "',[date])>=0 and datediff(day,'" & dt2 & "',[date])<=0 "

这里的日历是表，dt作为开始日期变量，dt2是结束日期变量。

这对我很有效

SELECT 
  * 
FROM 
  `request_logs` 
WHERE 
  created_at >= "2022-11-30 00:00:00" 
  AND created_at <= "2022-11-30 20:04:50" 
ORDER BY 
  `request_logs`.`id` DESC

试着把日期放在# #之间 例如:

#2013/4/4# and #2013/4/20#

这对我很管用。

SELECT Date, TotalAllowance  
FROM Calculation  
WHERE EmployeeId = 1 
  AND Date BETWEEN to_date('2011/02/25','yyyy-mm-dd') 
               AND to_date ('2011/02/27','yyyy-mm-dd');

对当前日期和前三天之间的选择日期的最佳查询:

  select Date,TotalAllowance from Calculation where EmployeeId=1 and Date BETWEEN       
DATE_SUB(CURDATE(), INTERVAL 3 DAY)  AND CURDATE() 

当前日期和未来三天之间的选择日期的最佳查询:

  select Date,TotalAllowance from Calculation where EmployeeId=1 and Date BETWEEN   
   CURDATE()  AND DATE_ADD(CURDATE(), INTERVAL 3 DAY)   

SELECT CITY, COUNT(EID) OCCURENCES FROM EMP 
WHERE DOB BETWEEN '31-JAN-1900' AND '31-JAN-2900' 
GROUP BY CITY 
HAVING COUNT(EID) > 2;

该查询将查找DOB位于员工指定时间范围内的次数超过2次的城市。