import re

def is_ascii(s):
    return bool(re.match(r'[\x00-\x7F]+$', s))

要包含一个空字符串作为ASCII，将+改为*。

def is_ascii(s):
    return all(ord(c) < 128 for c in s)

我使用以下方法来确定字符串是ascii还是unicode:

>> print 'test string'.__class__.__name__
str
>>> print u'test string'.__class__.__name__
unicode
>>> 

然后使用一个条件块来定义函数:

def is_ascii(input):
    if input.__class__.__name__ == "str":
        return True
    return False

要从Python 2.6(以及Python 3.x)改进Alexander的解决方案，您可以使用helper模块curses。ASCII和使用curses.ascii.isascii()函数或其他各种:https://docs.python.org/2.6/library/curses.ascii.html

from curses import ascii

def isascii(s):
    return all(ascii.isascii(c) for c in s)

为了防止代码崩溃，可能需要使用try-except来捕获TypeErrors

>>> ord("¶")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: ord() expected a character, but string of length 2 found

例如

def is_ascii(s):
    try:
        return all(ord(c) < 128 for c in s)
    except TypeError:
        return False

这样做怎么样?

import string

def isAscii(s):
    for c in s:
        if c not in string.ascii_letters:
            return False
    return True