在数组中返回最大数字的解。

const largestOfFour = arr => {
    let arr2 = [];
    arr.map(e => {
        let numStart = -Infinity;
        e.forEach(num => {
            if (num > numStart) {
                numStart = num;

            }
        })
        arr2.push(numStart);
    })
    return arr2;
}

运行这个:

Array.prototype.max = function(){
    return Math.max.apply( Math, this );
};

现在尝试[3,10,2].max()返回10

Use:

var arr = [1, 2, 3, 4];

var largest = arr.reduce(function(x,y) {
    return (x > y) ? x : y;
});

console.log(largest);

不要忘记，wrap可以用Function.prototype来完成。Bind，为您提供一个“全本地”函数。

var aMax = Math.max.apply.bind(Math.max, Math);
aMax([1, 2, 3, 4, 5]); // 5

应该很简单:

var countArray = [1,2,3,4,5,1,3,51,35,1,357,2,34,1,3,5,6];

var highestCount = 0;
for(var i=0; i<=countArray.length; i++){    
    if(countArray[i]>=highestCount){
    highestCount = countArray[i]
  }
}

console.log("Highest Count is " + highestCount);

要找到数组中最大的数字，您只需要使用Math.max(…arrayName);。它是这样工作的:

let myArr = [1, 2, 3, 4, 5, 6];
console.log(Math.max(...myArr));

要了解更多关于Math.max的信息: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Math/max