如何发送POST请求?

我在网上找到了这个脚本:

import httplib, urllib
params = urllib.urlencode({'number': 12524, 'type': 'issue', 'action': 'show'})
headers = {"Content-type": "application/x-www-form-urlencoded",
            "Accept": "text/plain"}
conn = httplib.HTTPConnection("bugs.python.org")
conn.request("POST", "", params, headers)
response = conn.getresponse()
print response.status, response.reason
302 Found
data = response.read()
data
'Redirecting to <a href="http://bugs.python.org/issue12524">http://bugs.python.org/issue12524</a>'
conn.close()

但我不明白如何用PHP使用它，params变量里面的所有东西是什么，或者如何使用它。你能帮我把这个弄起来吗?

当前回答

这是一个没有任何外部pip依赖的解决方案，但只在Python 3+中工作(Python 2不起作用):

from urllib.parse import urlencode
from urllib.request import Request, urlopen

url = 'https://httpbin.org/post' # Set destination URL here
post_fields = {'foo': 'bar'}     # Set POST fields here

request = Request(url, urlencode(post_fields).encode())
json = urlopen(request).read().decode()
print(json)

样例输出:

{
  "args": {}, 
  "data": "", 
  "files": {}, 
  "form": {
    "foo": "bar"
  }, 
  "headers": {
    "Accept-Encoding": "identity", 
    "Content-Length": "7", 
    "Content-Type": "application/x-www-form-urlencoded", 
    "Host": "httpbin.org", 
    "User-Agent": "Python-urllib/3.3"
  }, 
  "json": null, 
  "origin": "127.0.0.1", 
  "url": "https://httpbin.org/post"
}

2016-04-17 15:30:20

其他回答

您的数据字典包含表单输入字段的名称，您只需保持它们的值以查找结果。表格视图报头配置浏览器检索您声明的数据类型。使用请求库可以很容易地发送POST:

import requests

url = "https://bugs.python.org"
data = {'@number': 12524, '@type': 'issue', '@action': 'show'}
headers = {"Content-type": "application/x-www-form-urlencoded", "Accept":"text/plain"}
response = requests.post(url, data=data, headers=headers)

print(response.text)

关于请求对象的更多信息:https://requests.readthedocs.io/en/master/api/

2020-01-20 14:28:08

如果您不想使用必须像请求那样安装的模块，并且您的用例非常基本，那么您可以使用urllib2

urllib2.urlopen(url, body)

在这里查看urllib2的文档:https://docs.python.org/2/library/urllib2.html。

2019-01-17 20:17:48

您可以使用请求库来发出post请求。如果有效负载中有JSON字符串，则可以使用JSON .dumps(payload)，这是预期的有效负载形式。


    import requests, json
    url = "http://bugs.python.org/test"
    payload={
        "data1":1234,'data2':'test'
    }
    headers = {
        'Content-Type': 'application/json'
    }
    response = requests.post(url, headers=headers, data=json.dumps(payload))
    print(response.text , response.status_code)

2021-09-10 02:38:16

使用请求库GET, POST, PUT或DELETE通过击中REST API端点。在url中传递剩下的api端点url，在数据中传递有效载荷(dict)，在头中传递头/元数据

import requests, json

url = "bugs.python.org"

payload = {"number": 12524, 
           "type": "issue", 
           "action": "show"}

header = {"Content-type": "application/x-www-form-urlencoded",
          "Accept": "text/plain"} 

response_decoded_json = requests.post(url, data=payload, headers=header)
response_json = response_decoded_json.json()
 
print(response_json)

2018-12-05 08:38:38

如果你真的想用Python处理HTTP，我强烈推荐Requests: HTTP for Humans。针对你的问题，POST快速入门如下:

>>> import requests
>>> r = requests.post("http://bugs.python.org", data={'number': '12524', 'type': 'issue', 'action': 'show'})
>>> print(r.status_code, r.reason)
200 OK
>>> print(r.text[:300] + '...')

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<title>
Issue 12524: change httplib docs POST example - Python tracker

</title>
<link rel="shortcut i...
>>>

2012-07-04 08:08:46

如何发送POST请求?

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