我在网上找到了这个脚本:
import httplib, urllib
params = urllib.urlencode({'number': 12524, 'type': 'issue', 'action': 'show'})
headers = {"Content-type": "application/x-www-form-urlencoded",
"Accept": "text/plain"}
conn = httplib.HTTPConnection("bugs.python.org")
conn.request("POST", "", params, headers)
response = conn.getresponse()
print response.status, response.reason
302 Found
data = response.read()
data
'Redirecting to <a href="http://bugs.python.org/issue12524">http://bugs.python.org/issue12524</a>'
conn.close()
但我不明白如何用PHP使用它，params变量里面的所有东西是什么，或者如何使用它。你能帮我把这个弄起来吗?
这是一个没有任何外部pip依赖的解决方案，但只在Python 3+中工作(Python 2不起作用):
from urllib.parse import urlencode
from urllib.request import Request, urlopen
url = 'https://httpbin.org/post' # Set destination URL here
post_fields = {'foo': 'bar'} # Set POST fields here
request = Request(url, urlencode(post_fields).encode())
json = urlopen(request).read().decode()
print(json)
样例输出:
{
"args": {},
"data": "",
"files": {},
"form": {
"foo": "bar"
},
"headers": {
"Accept-Encoding": "identity",
"Content-Length": "7",
"Content-Type": "application/x-www-form-urlencoded",
"Host": "httpbin.org",
"User-Agent": "Python-urllib/3.3"
},
"json": null,
"origin": "127.0.0.1",
"url": "https://httpbin.org/post"
}
您的数据字典包含表单输入字段的名称，您只需保持它们的值以查找结果。
表格视图
报头配置浏览器检索您声明的数据类型。
使用请求库可以很容易地发送POST:
import requests
url = "https://bugs.python.org"
data = {'@number': 12524, '@type': 'issue', '@action': 'show'}
headers = {"Content-type": "application/x-www-form-urlencoded", "Accept":"text/plain"}
response = requests.post(url, data=data, headers=headers)
print(response.text)
关于请求对象的更多信息:https://requests.readthedocs.io/en/master/api/
您可以使用请求库来发出post请求。
如果有效负载中有JSON字符串，则可以使用JSON .dumps(payload)，这是预期的有效负载形式。
import requests, json
url = "http://bugs.python.org/test"
payload={
"data1":1234,'data2':'test'
}
headers = {
'Content-Type': 'application/json'
}
response = requests.post(url, headers=headers, data=json.dumps(payload))
print(response.text , response.status_code)
使用请求库GET, POST, PUT或DELETE通过击中REST API端点。在url中传递剩下的api端点url，在数据中传递有效载荷(dict)，在头中传递头/元数据
import requests, json
url = "bugs.python.org"
payload = {"number": 12524,
"type": "issue",
"action": "show"}
header = {"Content-type": "application/x-www-form-urlencoded",
"Accept": "text/plain"}
response_decoded_json = requests.post(url, data=payload, headers=header)
response_json = response_decoded_json.json()
print(response_json)
这是一个没有任何外部pip依赖的解决方案，但只在Python 3+中工作(Python 2不起作用):
from urllib.parse import urlencode
from urllib.request import Request, urlopen
url = 'https://httpbin.org/post' # Set destination URL here
post_fields = {'foo': 'bar'} # Set POST fields here
request = Request(url, urlencode(post_fields).encode())
json = urlopen(request).read().decode()
print(json)
样例输出:
{
"args": {},
"data": "",
"files": {},
"form": {
"foo": "bar"
},
"headers": {
"Accept-Encoding": "identity",
"Content-Length": "7",
"Content-Type": "application/x-www-form-urlencoded",
"Host": "httpbin.org",
"User-Agent": "Python-urllib/3.3"
},
"json": null,
"origin": "127.0.0.1",
"url": "https://httpbin.org/post"
}
