我在网上找到了这个脚本:
import httplib, urllib
params = urllib.urlencode({'number': 12524, 'type': 'issue', 'action': 'show'})
headers = {"Content-type": "application/x-www-form-urlencoded",
"Accept": "text/plain"}
conn = httplib.HTTPConnection("bugs.python.org")
conn.request("POST", "", params, headers)
response = conn.getresponse()
print response.status, response.reason
302 Found
data = response.read()
data
'Redirecting to <a href="http://bugs.python.org/issue12524">http://bugs.python.org/issue12524</a>'
conn.close()
但我不明白如何用PHP使用它，params变量里面的所有东西是什么，或者如何使用它。你能帮我把这个弄起来吗?
使用请求库GET, POST, PUT或DELETE通过击中REST API端点。在url中传递剩下的api端点url，在数据中传递有效载荷(dict)，在头中传递头/元数据
import requests, json
url = "bugs.python.org"
payload = {"number": 12524,
"type": "issue",
"action": "show"}
header = {"Content-type": "application/x-www-form-urlencoded",
"Accept": "text/plain"}
response_decoded_json = requests.post(url, data=payload, headers=header)
response_json = response_decoded_json.json()
print(response_json)
您可以使用请求库来发出post请求。
如果有效负载中有JSON字符串，则可以使用JSON .dumps(payload)，这是预期的有效负载形式。
import requests, json
url = "http://bugs.python.org/test"
payload={
"data1":1234,'data2':'test'
}
headers = {
'Content-Type': 'application/json'
}
response = requests.post(url, headers=headers, data=json.dumps(payload))
print(response.text , response.status_code)
使用请求库GET, POST, PUT或DELETE通过击中REST API端点。在url中传递剩下的api端点url，在数据中传递有效载荷(dict)，在头中传递头/元数据
import requests, json
url = "bugs.python.org"
payload = {"number": 12524,
"type": "issue",
"action": "show"}
header = {"Content-type": "application/x-www-form-urlencoded",
"Accept": "text/plain"}
response_decoded_json = requests.post(url, data=payload, headers=header)
response_json = response_decoded_json.json()
print(response_json)
如果你真的想用Python处理HTTP，我强烈推荐Requests: HTTP for Humans。针对你的问题，POST快速入门如下:
>>> import requests
>>> r = requests.post("http://bugs.python.org", data={'number': '12524', 'type': 'issue', 'action': 'show'})
>>> print(r.status_code, r.reason)
200 OK
>>> print(r.text[:300] + '...')
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<title>
Issue 12524: change httplib docs POST example - Python tracker
</title>
<link rel="shortcut i...
>>>
您的数据字典包含表单输入字段的名称，您只需保持它们的值以查找结果。
表格视图
报头配置浏览器检索您声明的数据类型。
使用请求库可以很容易地发送POST:
import requests
url = "https://bugs.python.org"
data = {'@number': 12524, '@type': 'issue', '@action': 'show'}
headers = {"Content-type": "application/x-www-form-urlencoded", "Accept":"text/plain"}
response = requests.post(url, data=data, headers=headers)
print(response.text)
关于请求对象的更多信息:https://requests.readthedocs.io/en/master/api/
你不能使用urllib实现POST请求(仅用于GET)，而是尝试使用请求模块，例如:
例1.0:
import requests
base_url="www.server.com"
final_url="/{0}/friendly/{1}/url".format(base_url,any_value_here)
payload = {'number': 2, 'value': 1}
response = requests.post(final_url, data=payload)
print(response.text) #TEXT/HTML
print(response.status_code, response.reason) #HTTP
例1.2:
>>> import requests
>>> payload = {'key1': 'value1', 'key2': 'value2'}
>>> r = requests.post("http://httpbin.org/post", data=payload)
>>> print(r.text)
{
...
"form": {
"key2": "value2",
"key1": "value1"
},
...
}
例1.3:
>>> import json
>>> url = 'https://api.github.com/some/endpoint'
>>> payload = {'some': 'data'}
>>> r = requests.post(url, data=json.dumps(payload))
