使用其中一种有什么好处吗?在Python 2中,它们似乎都返回相同的结果:

>>> 6/3
2
>>> 6//3
2

当前回答

方程的答案四舍五入到下一个较小的整数或以。0作为小数点的浮点数。

>>>print 5//2
2
>>> print 5.0//2
2.0
>>>print 5//2.0
2.0
>>>print 5.0//2.0
2.0

其他回答

总结

x//y:精确的整数除法 int(x/y) OR math.floor(x/y):不精确的整数除法(但几乎正确) X /y:浮点除法(没有意义)

显著计算结果

import math
N = 1004291331219602346 # huge number 

print(N//100) #=> 10042913312196023 is correct answer
print(math.floor(N/100)) #=> 10042913312196024 is wrong answer
print(math.ceil(N/100)) #=> 10042913312196024 is wrong answer
print(int(N/100)) #=> 10042913312196024 is wrong answer

考虑

考虑int(x/y)的取值。 首先,Python计算表达式x/y并得到不精确的浮点数z。 其次,Python计算表达式int(z)。 当意义的丧失不可忽视时,我们会得到错误的结果。

双斜杠//是层划分:

>>> 7//3
2

方程的答案四舍五入到下一个较小的整数或以。0作为小数点的浮点数。

>>>print 5//2
2
>>> print 5.0//2
2.0
>>>print 5//2.0
2.0
>>>print 5.0//2.0
2.0

//是楼层划分。它总是会给你结果的整数底。另一种是“常规”除法。

Python 3

操作 结果 笔记 X / y x和y的商 X // y x和y的底商 (1) 注: 也称为整数除法。结果值是一个整型,尽管结果的类型不一定是int。结果总是趋近于负无穷:1//2等于0,(-1)//2等于-1,1//(-2)等于-1,(-1)//(-2)等于0。

Python 2

Operation Result Notes x / y quotient of x and y (1) x // y (floored) quotient of x and y (4)(5) Notes: 1. For (plain or long) integer division, the result is an integer. The result is always rounded towards minus infinity: 1/2 is 0, (-1)/2 is -1, 1/(-2) is -1, and (-1)/(-2) is 0. Note that the result is a long integer if either operand is a long integer, regardless of the numeric value. 4. Deprecated since version 2.3: The floor division operator, the modulo operator, and the divmod() function are no longer defined for complex numbers. Instead, convert to a floating point number using the abs() function if appropriate. 5. Also referred to as integer division. The resultant value is a whole integer, though the result’s type is not necessarily int.