如何以12小时格式(AM/PM)显示JavaScript datetime对象?
当前回答
或者只是简单地执行以下代码:
<script>
time = function() {
var today = new Date();
var h = today.getHours();
var m = today.getMinutes();
var s = today.getSeconds();
m = checkTime(m);
s = checkTime(s);
document.getElementById('txt_clock').innerHTML = h + ":" + m + ":" + s;
var t = setTimeout(function(){time()}, 0);
}
time2 = function() {
var today = new Date();
var h = today.getHours();
var m = today.getMinutes();
var s = today.getSeconds();
m = checkTime(m);
s = checkTime(s);
if (h>12) {
document.getElementById('txt_clock_stan').innerHTML = h-12 + ":" + m + ":" + s;
}
var t = setTimeout(function(){time2()}, 0);
}
time3 = function() {
var today = new Date();
var h = today.getHours();
var m = today.getMinutes();
var s = today.getSeconds();
if (h>12) {
document.getElementById('hour_line').style.width = h-12 + 'em';
}
document.getElementById('minute_line').style.width = m + 'em';
document.getElementById('second_line').style.width = s + 'em';
var t = setTimeout(function(){time3()}, 0);
}
checkTime = function(i) {
if (i<10) {i = "0" + i}; // add zero in front of numbers < 10
return i;
}
</script>
其他回答
这里有另一种简单有效的方法:
var d = new Date();
var weekday = new Array(7);
weekday[0] = "Sunday";
weekday[1] = "Monday";
weekday[2] = "Tuesday";
weekday[3] = "Wednesday";
weekday[4] = "Thursday";
weekday[5] = "Friday";
weekday[6] = "Saturday";
var month = new Array(11);
month[0] = "January";
month[1] = "February";
month[2] = "March";
month[3] = "April";
month[4] = "May";
month[5] = "June";
month[6] = "July";
month[7] = "August";
month[8] = "September";
month[9] = "October";
month[10] = "November";
month[11] = "December";
var t = d.toLocaleTimeString().replace(/:\d+ /, ' ');
document.write(weekday[d.getDay()] + ',' + " " + month[d.getMonth()] + " " + d.getDate() + ',' + " " + d.getFullYear() + '<br>' + d.toLocaleTimeString());
</script></div><!-- #time -->
var d = new Date(); var hours = d.getHours() % 12; hours = hours ? hours : 12; var test = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec'][(d.getMonth() + 1)] + " " + ("00" + d.getDate()).slice(-2) + " " + d.getFullYear() + " " + ("00" + hours).slice(-2) + ":" + ("00" + d.getMinutes()).slice(-2) + ":" + ("00" + d.getSeconds()).slice(-2) + ' ' + (d.getHours() >= 12 ? 'PM' : 'AM'); document.getElementById("demo").innerHTML = test; <p id="demo" ></p>
const formatAMPM = (date) => {
try {
let time = date.split(" ");
let hours = time[4].split(":")[0];
let minutes = time[4].split(":")[1];
hours = hours || 12;
const ampm = hours >= 12 ? " PM" : " AM";
minutes = minutes < 10 ? `${minutes}` : minutes;
hours %= 12;
const strTime = `${hours}:${minutes} ${ampm}`;
return strTime;
} catch (e) {
return "";
}
};
const startTime = "2021-12-07T17:00:00.073Z"
formatAMPM(new Date(startTime).toUTCString())
function formatTime( d = new Date(), ampm = true ) { var hour = d.getHours(); if ( ampm ) { var a = ( hour >= 12 ) ? 'PM' : 'AM'; hour = hour % 12; hour = hour ? hour : 12; // the hour '0' should be '12' } var hour = checkDigit(hour); var minute = checkDigit(d.getMinutes()); var second = checkDigit(d.getSeconds()); // https://stackoverflow.com/questions/1408289/how-can-i-do-string-interpolation-in-javascript return ( ampm ) ? `${hour}:${minute}:${second} ${a}` : `${hour}:${minute}:${second}`; } function checkDigit(t) { return ( t < 10 ) ? `0${t}` : t; } document.querySelector("#time1").innerHTML = formatTime(); document.querySelector("#time2").innerHTML = formatTime( new Date(), false ); <p>ampm true: <span id="time1"></span> (default)</p> <p>ampm false: <span id="time2"></span></p>
这是我的解决方案
function getTime() {
var systemDate = new Date();
var hours = systemDate.getHours();
var minutes = systemDate.getMinutes();
var strampm;
if (hours >= 12) {
strampm= "PM";
} else {
strampm= "AM";
}
hours = hours % 12;
if (hours == 0) {
hours = 12;
}
_hours = checkTimeAddZero(hours);
_minutes = checkTimeAddZero(minutes);
console.log(_hours + ":" + _minutes + " " + strampm);
}
function checkTimeAddZero(i) {
if (i < 10) {
i = "0" + i
}
return i;
}
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