使用c++和ndk是最好的方法来检测根，即使用户使用的应用程序隐藏了他的根，如RootCloak。我用RootCloak测试了这段代码，即使用户试图隐藏它，我也能够检测到根。 所以你的cpp文件是这样的:

#include <jni.h>
#include <string>


/**
 *
 * function that checks for the su binary files and operates even if 
 * root cloak is installed
 * @return integer 1: device is rooted, 0: device is not 
 *rooted
*/
extern "C"
JNIEXPORT int JNICALL


Java_com_example_user_root_1native_rootFunction(JNIEnv *env,jobject thiz){
const char *paths[] ={"/system/app/Superuser.apk", "/sbin/su", "/system/bin/su",
                      "/system/xbin/su", "/data/local/xbin/su", "/data/local/bin/su", "/system/sd/xbin/su",
                      "/system/bin/failsafe/su", "/data/local/su", "/su/bin/su"};

int counter =0;
while (counter<9){
    if(FILE *file = fopen(paths[counter],"r")){
        fclose(file);
        return 1;
    }
    counter++;
}
return 0;
}

您将从java代码中调用该函数，如下所示

public class Root_detect {



   /**
    *
    * function that calls a native function to check if the device is 
    *rooted or not
    * @return boolean: true if the device is rooted, false if the 
    *device is not rooted
   */
   public boolean check_rooted(){

        int checker = rootFunction();

        if(checker==1){
           return true;
        }else {
           return false;
        }
   }
   static {
    System.loadLibrary("cpp-root-lib");//name of your cpp file
   }

   public native int rootFunction();
}

在2021年最后一个季度的今天，我试图使用SafetyNet来回答@HimanshiThakur的答案。但我有个问题，在这里提出了一个问题。还是没有回答。

所以我决定使用RootBeer。它工作得很好，但当Magisk隐藏根时，它就不起作用了。

如果你不在乎这种情况(许多银行应用程序也不能解决这个问题)，你可以使用以下步骤:

添加到Gradle:

implementation 'com.scottyab:rootbeer-lib:0.1.0'

用这些句子:

RootBeer rootBeer = new RootBeer(context);
if (rootBeer.isRooted()) {
    //we found indication of root
} else {
    //we didn't find indication of root
}

Java级别的根检查不是一个安全的解决方案。如果您的应用程序在root设备上运行有安全问题，那么请使用此解决方案。

凯文的答案是有效的，除非手机也有像RootCloak这样的应用程序。这样的应用程序有一个对Java api的句柄，一旦手机是根的，他们模仿这些api来返回手机不是根的。

我已经写了一个原生级别的代码基于凯文的答案，它甚至与RootCloak !此外，它不会导致任何内存泄漏问题。

#include <string.h>
#include <jni.h>
#include <time.h>
#include <sys/stat.h>
#include <stdio.h>
#include "android_log.h"
#include <errno.h>
#include <unistd.h>
#include <sys/system_properties.h>

JNIEXPORT int JNICALL Java_com_test_RootUtils_checkRootAccessMethod1(
        JNIEnv* env, jobject thiz) {


    //Access function checks whether a particular file can be accessed
    int result = access("/system/app/Superuser.apk",F_OK);

    ANDROID_LOGV( "File Access Result %d\n", result);

    int len;
    char build_tags[PROP_VALUE_MAX]; // PROP_VALUE_MAX from <sys/system_properties.h>.
    len = __system_property_get(ANDROID_OS_BUILD_TAGS, build_tags); // On return, len will equal (int)strlen(model_id).
    if(strcmp(build_tags,"test-keys") == 0){
        ANDROID_LOGV( "Device has test keys\n", build_tags);
        result = 0;
    }
    ANDROID_LOGV( "File Access Result %s\n", build_tags);
    return result;

}

JNIEXPORT int JNICALL Java_com_test_RootUtils_checkRootAccessMethod2(
        JNIEnv* env, jobject thiz) {
    //which command is enabled only after Busy box is installed on a rooted device
    //Outpput of which command is the path to su file. On a non rooted device , we will get a null/ empty path
    //char* cmd = const_cast<char *>"which su";
    FILE* pipe = popen("which su", "r");
    if (!pipe) return -1;
    char buffer[128];
    std::string resultCmd = "";
    while(!feof(pipe)) {
        if(fgets(buffer, 128, pipe) != NULL)
            resultCmd += buffer;
    }
    pclose(pipe);

    const char *cstr = resultCmd.c_str();
    int result = -1;
    if(cstr == NULL || (strlen(cstr) == 0)){
        ANDROID_LOGV( "Result of Which command is Null");
    }else{
        result = 0;
        ANDROID_LOGV( "Result of Which command %s\n", cstr);
        }
    return result;

}

JNIEXPORT int JNICALL Java_com_test_RootUtils_checkRootAccessMethod3(
        JNIEnv* env, jobject thiz) {


    int len;
    char build_tags[PROP_VALUE_MAX]; // PROP_VALUE_MAX from <sys/system_properties.h>.
    int result = -1;
    len = __system_property_get(ANDROID_OS_BUILD_TAGS, build_tags); // On return, len will equal (int)strlen(model_id).
    if(len >0 && strstr(build_tags,"test-keys") != NULL){
        ANDROID_LOGV( "Device has test keys\n", build_tags);
        result = 0;
    }

    return result;

}

在Java代码中，需要创建包装器类RootUtils来进行本机调用

    public boolean checkRooted() {

       if( rootUtils.checkRootAccessMethod3()  == 0 || rootUtils.checkRootAccessMethod1()  == 0 || rootUtils.checkRootAccessMethod2()  == 0 )
           return true;
      return false;
     }

在我的应用程序中，我通过执行“su”命令检查设备是否根。但是今天我删除了这部分代码。为什么?

因为我的应用程序成了内存杀手。怎么做?让我告诉你我的故事。

There were some complaints that my application was slowing down devices(Of course I thought that can not be true). I tried to figure out why. So I used MAT to get heap dumps and analyze, and everything seemed perfect. But after relaunching my app many times I realized that device is really getting slower and stopping my application didn't make it faster (unless I restart device). I analyzed dump files again while device is very slow. But everything was still perfect for dump file. Then I did what must be done at first. I listed processes.

$ adb shell ps

使震惊;我的应用程序有许多进程(应用程序的进程标签在manifest上)。有些是僵尸，有些不是。

对于一个只有一个Activity并只执行“su”命令的示例应用程序，我意识到在每次启动应用程序时都会创建一个僵尸进程。起初，这些僵尸进程分配0KB，但后来发生了一些事情，僵尸进程与我的应用程序的主进程占用了几乎相同的kb，它们成为了标准进程。

在bugs.sun.com: http://bugs.sun.com/view_bug.do?bug_id=6474073上有一个关于相同问题的错误报告，这解释了如果命令没有找到，将使用exec()方法创建僵尸。但我仍然不明白它们为什么以及如何成为标准流程并保持重要的kb。(这并不是一直都在发生)

你可以尝试如果你想下面的代码示例;

String commandToExecute = "su";
executeShellCommand(commandToExecute);

简单的命令执行方法;

private boolean executeShellCommand(String command){
    Process process = null;            
    try{
        process = Runtime.getRuntime().exec(command);
        return true;
    } catch (Exception e) {
        return false;
    } finally{
        if(process != null){
            try{
                process.destroy();
            }catch (Exception e) {
            }
        }
    }
}

总结:总结;我没有建议你确定设备是否扎根。但如果我是你，我不会使用Runtime.getRuntime().exec()。

顺便说一下;RootTools.isRootAvailable()也会引起同样的问题。

RootTools库提供了简单的方法来检查根:

RootTools.isRootAvailable()

参考

在rootbox中使用我的库非常简单。检查所需的代码如下:

    //Pass true to <Shell>.start(...) call to run as superuser
    Shell shell = null;
    try {
            shell = Shell.start(true);
    } catch (IOException exception) {
            exception.printStackTrace();
    }
    if (shell == null)
            // We failed to execute su binary
            return;
    if (shell.isRoot()) {
            // Verified running as uid 0 (root), can continue with commands
            ...
    } else
            throw Exception("Unable to gain root access. Make sure you pressed Allow/Grant in superuser prompt.");