我的应用程序有一个特定的功能,只能在根可用的设备上工作。与其让这个特性在使用时失败(然后向用户显示适当的错误消息),我更希望能够先静默地检查根目录是否可用,如果不可用,则首先隐藏相应的选项。
有办法做到这一点吗?
我的应用程序有一个特定的功能,只能在根可用的设备上工作。与其让这个特性在使用时失败(然后向用户显示适当的错误消息),我更希望能够先静默地检查根目录是否可用,如果不可用,则首先隐藏相应的选项。
有办法做到这一点吗?
当前回答
RootTools库提供了简单的方法来检查根:
RootTools.isRootAvailable()
参考
其他回答
Java级别的根检查不是一个安全的解决方案。如果您的应用程序在root设备上运行有安全问题,那么请使用此解决方案。
凯文的答案是有效的,除非手机也有像RootCloak这样的应用程序。这样的应用程序有一个对Java api的句柄,一旦手机是根的,他们模仿这些api来返回手机不是根的。
我已经写了一个原生级别的代码基于凯文的答案,它甚至与RootCloak !此外,它不会导致任何内存泄漏问题。
#include <string.h>
#include <jni.h>
#include <time.h>
#include <sys/stat.h>
#include <stdio.h>
#include "android_log.h"
#include <errno.h>
#include <unistd.h>
#include <sys/system_properties.h>
JNIEXPORT int JNICALL Java_com_test_RootUtils_checkRootAccessMethod1(
JNIEnv* env, jobject thiz) {
//Access function checks whether a particular file can be accessed
int result = access("/system/app/Superuser.apk",F_OK);
ANDROID_LOGV( "File Access Result %d\n", result);
int len;
char build_tags[PROP_VALUE_MAX]; // PROP_VALUE_MAX from <sys/system_properties.h>.
len = __system_property_get(ANDROID_OS_BUILD_TAGS, build_tags); // On return, len will equal (int)strlen(model_id).
if(strcmp(build_tags,"test-keys") == 0){
ANDROID_LOGV( "Device has test keys\n", build_tags);
result = 0;
}
ANDROID_LOGV( "File Access Result %s\n", build_tags);
return result;
}
JNIEXPORT int JNICALL Java_com_test_RootUtils_checkRootAccessMethod2(
JNIEnv* env, jobject thiz) {
//which command is enabled only after Busy box is installed on a rooted device
//Outpput of which command is the path to su file. On a non rooted device , we will get a null/ empty path
//char* cmd = const_cast<char *>"which su";
FILE* pipe = popen("which su", "r");
if (!pipe) return -1;
char buffer[128];
std::string resultCmd = "";
while(!feof(pipe)) {
if(fgets(buffer, 128, pipe) != NULL)
resultCmd += buffer;
}
pclose(pipe);
const char *cstr = resultCmd.c_str();
int result = -1;
if(cstr == NULL || (strlen(cstr) == 0)){
ANDROID_LOGV( "Result of Which command is Null");
}else{
result = 0;
ANDROID_LOGV( "Result of Which command %s\n", cstr);
}
return result;
}
JNIEXPORT int JNICALL Java_com_test_RootUtils_checkRootAccessMethod3(
JNIEnv* env, jobject thiz) {
int len;
char build_tags[PROP_VALUE_MAX]; // PROP_VALUE_MAX from <sys/system_properties.h>.
int result = -1;
len = __system_property_get(ANDROID_OS_BUILD_TAGS, build_tags); // On return, len will equal (int)strlen(model_id).
if(len >0 && strstr(build_tags,"test-keys") != NULL){
ANDROID_LOGV( "Device has test keys\n", build_tags);
result = 0;
}
return result;
}
在Java代码中,需要创建包装器类RootUtils来进行本机调用
public boolean checkRooted() {
if( rootUtils.checkRootAccessMethod3() == 0 || rootUtils.checkRootAccessMethod1() == 0 || rootUtils.checkRootAccessMethod2() == 0 )
return true;
return false;
}
http://code.google.com/p/roottools/
如果你不想使用jar文件,请使用下面的代码:
public static boolean findBinary(String binaryName) {
boolean found = false;
if (!found) {
String[] places = { "/sbin/", "/system/bin/", "/system/xbin/",
"/data/local/xbin/", "/data/local/bin/",
"/system/sd/xbin/", "/system/bin/failsafe/", "/data/local/" };
for (String where : places) {
if (new File(where + binaryName).exists()) {
found = true;
break;
}
}
}
return found;
}
程序将尝试查找su文件夹:
private static boolean isRooted() {
return findBinary("su");
}
例子:
if (isRooted()) {
textView.setText("Device Rooted");
} else {
textView.setText("Device Unrooted");
}
下面是一个类,它将以三种方式之一检查Root。
/** @author Kevin Kowalewski */
public class RootUtil {
public static boolean isDeviceRooted() {
return checkRootMethod1() || checkRootMethod2() || checkRootMethod3();
}
private static boolean checkRootMethod1() {
String buildTags = android.os.Build.TAGS;
return buildTags != null && buildTags.contains("test-keys");
}
private static boolean checkRootMethod2() {
String[] paths = { "/system/app/Superuser.apk", "/sbin/su", "/system/bin/su", "/system/xbin/su", "/data/local/xbin/su", "/data/local/bin/su", "/system/sd/xbin/su",
"/system/bin/failsafe/su", "/data/local/su", "/su/bin/su"};
for (String path : paths) {
if (new File(path).exists()) return true;
}
return false;
}
private static boolean checkRootMethod3() {
Process process = null;
try {
process = Runtime.getRuntime().exec(new String[] { "/system/xbin/which", "su" });
BufferedReader in = new BufferedReader(new InputStreamReader(process.getInputStream()));
if (in.readLine() != null) return true;
return false;
} catch (Throwable t) {
return false;
} finally {
if (process != null) process.destroy();
}
}
}
在rootbox中使用我的库非常简单。检查所需的代码如下:
//Pass true to <Shell>.start(...) call to run as superuser
Shell shell = null;
try {
shell = Shell.start(true);
} catch (IOException exception) {
exception.printStackTrace();
}
if (shell == null)
// We failed to execute su binary
return;
if (shell.isRoot()) {
// Verified running as uid 0 (root), can continue with commands
...
} else
throw Exception("Unable to gain root access. Make sure you pressed Allow/Grant in superuser prompt.");
根据这里的一些答案,我合并了它们,并添加了一个检查是否安装了一些已知的根管理器应用程序:
fun isProbablyRooted(context: Context, alsoIncludeCheckingRootManagerApp: Boolean = false): Boolean {
return hasRootManagerSystemApp(context) || (alsoIncludeCheckingRootManagerApp && hasRootManagerSystemApp(context))
}
fun hasRootManagerSystemApp(context: Context): Boolean {
val rootAppsPackageNames = arrayOf("com.topjohnwu.magisk", "eu.chainfire.supersu", "com.koushikdutta.superuser", "com.noshufou.android.su", "me.phh.superuser")
rootAppsPackageNames.forEach { rootAppPackageName ->
try {
context.packageManager.getApplicationInfo(rootAppPackageName, 0)
return true
} catch (e: Exception) {
}
}
return false
}
fun hasSuBinary(): Boolean {
return try {
findBinary("su")
} catch (e: Exception) {
e.printStackTrace()
false
}
}
private fun findBinary(binaryName: String): Boolean {
val paths = System.getenv("PATH")
if (!paths.isNullOrBlank()) {
val systemPlaces: List<String> = paths.split(":")
return systemPlaces.firstOrNull { File(it, binaryName).exists() } != null
}
val places = arrayOf("/sbin/", "/system/bin/", "/system/xbin/", "/data/local/xbin/", "/data/local/bin/",
"/system/sd/xbin/", "/system/bin/failsafe/", "/data/local/")
return places.firstOrNull { File(it, binaryName).exists() } != null
}
清单:
<queries>
<package android:name="com.topjohnwu.magisk" />
<package android:name="eu.chainfire.supersu" />
<package android:name="com.koushikdutta.superuser" />
<package android:name="com.noshufou.android.su" />
<package android:name="me.phh.superuser" />
</queries>
当然,这仍然是一个猜测,就像所有其他解一样。 例如,用户可以安装Magisk,而无需对设备进行root操作。