下面这个更简单的shell脚本适合我。

#!/bin/bash
for i in  `psql -U $1  -qt -c  "select tablename from pg_tables where schemaname='$2'"`
do
psql -U $1 -c  "alter table $2.$i set schema $3"
done

其中输入$1 -用户名(数据库) $2 =现有模式 $3 =新模式。

在PostgreSQL中没有这样的命令。但是您可以使用我之前为GRANTs描述的方法来解决它。

如果当前所有者不是postgres，你可以使用这个:

REASSIGN OWNED BY old_role [, ...] TO new_role

但如果当前的所有者是postgres，你肯定会得到错误，所以你必须使用@dvanrensburg回答，但如果你想在相同的sql中执行命令，可以根据需要使用这些命令:

数据库

ALTER DATABASE target_database OWNER TO new_onwer;

表

DO
LANGUAGE plpgsql
$$
DECLARE
  stmt text;
BEGIN
  FOR stmt IN
    WITH temp as (
    SELECT 'ALTER TABLE '|| schemaname || '."' || tablename ||'" OWNER TO newuser' as command
    FROM pg_tables WHERE NOT schemaname IN ('pg_catalog', 'information_schema')
    ORDER BY schemaname, tablename )
    SELECT command from temp
  LOOP
    EXECUTE stmt;
  END LOOP;
END;
$$;

序列

DO
LANGUAGE plpgsql
$$
DECLARE
  stmt text;
BEGIN
  FOR stmt IN
    WITH temp as (
    SELECT 'ALTER SEQUENCE '|| sequence_schema || '."' || sequence_name ||'" OWNER TO newuser;' as command
    FROM information_schema.sequences WHERE NOT sequence_schema IN ('pg_catalog', 'information_schema')
    ORDER BY sequence_schema, sequence_name)
    select command from temp
  LOOP
    EXECUTE stmt;
  END LOOP;
END;
$$;

的观点

DO
LANGUAGE plpgsql
$$
DECLARE
  stmt text;
BEGIN
  FOR stmt IN
    WITH temp as (
    SELECT 'ALTER VIEW '|| table_schema || '."' || table_name ||'" OWNER TO newuser;' as command
    FROM information_schema.views WHERE NOT table_schema IN ('pg_catalog', 'information_schema')
    ORDER BY table_schema, table_name)
    select command from temp
  LOOP
    EXECUTE stmt;
  END LOOP;
END;
$$;

模式

DO
LANGUAGE plpgsql
$$
DECLARE
  stmt text;
BEGIN
  FOR stmt IN
    WITH schema_names as(
    SELECT distinct(schemaname) FROM pg_tables WHERE NOT schemaname IN ('pg_catalog', 'information_schema')
    ORDER BY schemaname)
    SELECT 'ALTER SCHEMA '|| schemaname ||' OWNER TO newuser;' as command
    FROM schema_names
  LOOP
    EXECUTE stmt;
  END LOOP;
END;
$$;

还要注意数据库中可能需要更改成员关系的函数和其他组件

函数和触发函数

    DO
    LANGUAGE plpgsql
    $$
    DECLARE
      stmt text;
    BEGIN
      FOR stmt IN
        WITH temp as(
        SELECT 'alter function '||nsp.nspname||'.'||p.proname||'('||pg_get_function_identity_arguments(p.oid)||') owner to newuser;' as command
        FROM pg_proc p
        JOIN pg_namespace nsp ON p.pronamespace = nsp.oid
        WHERE NOT  nsp.nspname IN ('pg_catalog', 'information_schema'))
        SELECT command FROM temp
      LOOP
        EXECUTE stmt;
      END LOOP;
    END;
    $$;

可以使用REASSIGN OWNED命令。

剧情简介:

重新分配old_role[，…]到new_role

这将把old_role拥有的所有对象更改为新角色。你不需要考虑用户拥有什么样的对象，它们都会被改变。注意，它只应用于单个数据库中的对象。它也不会改变数据库本身的所有者。

它至少可以在8.2版本中使用。他们的网上资料只能追溯到这段时间。

与@AlexSoto的函数方法相同:

IFS=$'\n'  
for fnc in `psql -qAt -c "SELECT  '\"' || p.proname||'\"' || '(' || pg_catalog.pg_get_function_identity_arguments(p.oid) || ')' FROM pg_catalog.pg_namespace n JOIN pg_catalog.pg_proc p ON p.pronamespace = n.oid WHERE n.nspname = 'public';" YOUR_DB` ; do  psql -c "alter function $fnc owner to NEW_OWNER" YOUR_DB; done

参见REASSIGN OWNED命令

注意:正如@trygvis在下面的回答中提到的，REASSIGN OWNED命令至少在8.2版本中就可用了，而且是一个更简单的方法。

因为要更改所有表的所有权，所以可能还需要视图和序列。以下是我所做的:

表:

for tbl in `psql -qAt -c "select tablename from pg_tables where schemaname = 'public';" YOUR_DB` ; do  psql -c "alter table \"$tbl\" owner to NEW_OWNER" YOUR_DB ; done

序列:

for tbl in `psql -qAt -c "select sequence_name from information_schema.sequences where sequence_schema = 'public';" YOUR_DB` ; do  psql -c "alter sequence \"$tbl\" owner to NEW_OWNER" YOUR_DB ; done

视图:

for tbl in `psql -qAt -c "select table_name from information_schema.views where table_schema = 'public';" YOUR_DB` ; do  psql -c "alter view \"$tbl\" owner to NEW_OWNER" YOUR_DB ; done

您可能会DRY它一点，因为alter语句对所有三个都是相同的。