有一些简单的方法来填充字符串在Java?
似乎是一些应该在一些stringutil类API,但我找不到任何东西,这样做。
有一些简单的方法来填充字符串在Java?
似乎是一些应该在一些stringutil类API,但我找不到任何东西,这样做。
当前回答
这是一个高效的实用工具类,用于Java中的左填充,右填充,中心填充和零填充字符串。
package com.example;
/**
* Utility class for left pad, right pad, center pad and zero fill.
*/
public final class StringPadding {
public static String left(String string, int length, char fill) {
if (string.length() < length) {
char[] chars = string.toCharArray();
char[] output = new char[length];
int delta = length - chars.length;
for (int i = 0; i < length; i++) {
if (i < delta) {
output[i] = fill;
} else {
output[i] = chars[i - delta];
}
}
return new String(output);
}
return string;
}
public static String right(String string, int length, char fill) {
if (string.length() < length) {
char[] chars = string.toCharArray();
char[] output = new char[length];
for (int i = 0; i < length; i++) {
if (i < chars.length) {
output[i] = chars[i];
} else {
output[i] = fill;
}
}
return new String(output);
}
return string;
}
public static String center(String string, int length, char fill) {
if (string.length() < length) {
char[] chars = string.toCharArray();
int delta = length - chars.length;
int a = (delta % 2 == 0) ? delta / 2 : delta / 2 + 1;
int b = a + chars.length;
char[] output = new char[length];
for (int i = 0; i < length; i++) {
if (i < a) {
output[i] = fill;
} else if (i < b) {
output[i] = chars[i - a];
} else {
output[i] = fill;
}
}
return new String(output);
}
return string;
}
public static String zerofill(String string, int length) {
return left(string, length, '0');
}
private StringPadding() {
}
/**
* For tests!
*/
public static void main(String[] args) {
String string = "123";
char blank = ' ';
System.out.println("left pad: [" + StringPadding.left(string, 10, blank) + "]");
System.out.println("right pad: [" + StringPadding.right(string, 10, blank) + "]");
System.out.println("center pad: [" + StringPadding.center(string, 10, blank) + "]");
System.out.println("zero fill: [" + StringPadding.zerofill(string, 10) + "]");
}
}
输出如下:
left pad: [ 123]
right pad: [123 ]
center pad: [ 123 ]
zero fill: [0000000123]
其他回答
我花了一点时间才想明白。 真正的关键是阅读Formatter文档。
// Get your data from wherever.
final byte[] data = getData();
// Get the digest engine.
final MessageDigest md5= MessageDigest.getInstance("MD5");
// Send your data through it.
md5.update(data);
// Parse the data as a positive BigInteger.
final BigInteger digest = new BigInteger(1,md5.digest());
// Pad the digest with blanks, 32 wide.
String hex = String.format(
// See: http://download.oracle.com/javase/1.5.0/docs/api/java/util/Formatter.html
// Format: %[argument_index$][flags][width]conversion
// Conversion: 'x', 'X' integral The result is formatted as a hexadecimal integer
"%1$32x",
digest
);
// Replace the blank padding with 0s.
hex = hex.replace(" ","0");
System.out.println(hex);
填充到10个字符:
String.format("%10s", "foo").replace(' ', '*');
String.format("%-10s", "bar").replace(' ', '*');
String.format("%10s", "longer than 10 chars").replace(' ', '*');
输出:
*******foo
bar*******
longer*than*10*chars
密码字符显示“*”:
String password = "secret123";
String padded = String.format("%"+password.length()+"s", "").replace(' ', '*');
输出与密码字符串长度相同:
secret123
*********
如此:
"".format("%1$-" + 9 + "s", "XXX").replaceAll(" ", "0")
它会用空白填充你的字符串XXX,最多9个字符。在此之后,所有空格将被替换为0。你可以把空格和0改为任何你想要的…
下面是另一种向右填充的方法:
// put the number of spaces, or any character you like, in your paddedString
String paddedString = "--------------------";
String myStringToBePadded = "I like donuts";
myStringToBePadded = myStringToBePadded + paddedString.substring(myStringToBePadded.length());
//result:
myStringToBePadded = "I like donuts-------";
另一种利用递归的解决方案。
这与所有JDK版本兼容,不需要外部库:
private static String addPadding(final String str, final int desiredLength, final String padBy) {
String result = str;
if (str.length() >= desiredLength) {
return result;
} else {
result += padBy;
return addPadding(result, desiredLength, padBy);
}
}
注意:这个解决方案将附加填充,与一个小调整,你可以前缀填充值。