这是我的解决方案。它也适用于COM对象，并允许从COM对象访问集合/数组项。

public static object GetPropValue(this object obj, string name)
{
    foreach (string part in name.Split('.'))
    {
        if (obj == null) { return null; }

        Type type = obj.GetType();
        if (type.Name == "__ComObject")
        {
            if (part.Contains('['))
            {
                string partWithoundIndex = part;
                int index = ParseIndexFromPropertyName(ref partWithoundIndex);
                obj = Versioned.CallByName(obj, partWithoundIndex, CallType.Get, index);
            }
            else
            {
                obj = Versioned.CallByName(obj, part, CallType.Get);
            }
        }
        else
        {
            PropertyInfo info = type.GetProperty(part);
            if (info == null) { return null; }
            obj = info.GetValue(obj, null);
        }
    }
    return obj;
}

private static int ParseIndexFromPropertyName(ref string name)
{
    int index = -1;
    int s = name.IndexOf('[') + 1;
    int e = name.IndexOf(']');
    if (e < s)
    {
        throw new ArgumentException();
    }
    string tmp = name.Substring(s, e - s);
    index = Convert.ToInt32(tmp);
    name = name.Substring(0, s - 1);
    return index;
}

jheddings和AlexD都写了关于如何解析属性字符串的出色答案。我想把我的库也加入其中，因为我专门为此编写了一个库。

路径。CSharp的主类是Resolver。默认情况下，它可以解析属性、数组和字典条目。

举个例子，如果你有一个这样的物体

var o = new { Property1 = new { Property2 = "value" } };

想要获得Property2，你可以这样做:

IResolver resolver = new Resolver();
var path = "Property1.Property2";
object result = r.Resolve(o, path); 
//=> "value"

这是它可以解析的路径的最基本示例。如果你想看看它还能做什么，或者你可以如何扩展它，只需前往它的Github页面。

jheddings的回答很好。我想通过允许引用聚集的数组或对象的集合来改进它，这样propertyName可以是property1.property2[X].property3:

    public static object GetPropertyValue(object srcobj, string propertyName)
    {
        if (srcobj == null)
            return null;

        object obj = srcobj;

        // Split property name to parts (propertyName could be hierarchical, like obj.subobj.subobj.property
        string[] propertyNameParts = propertyName.Split('.');

        foreach (string propertyNamePart in propertyNameParts)
        {
            if (obj == null)    return null;

            // propertyNamePart could contain reference to specific 
            // element (by index) inside a collection
            if (!propertyNamePart.Contains("["))
            {
                PropertyInfo pi = obj.GetType().GetProperty(propertyNamePart);
                if (pi == null) return null;
                obj = pi.GetValue(obj, null);
            }
            else
            {   // propertyNamePart is areference to specific element 
                // (by index) inside a collection
                // like AggregatedCollection[123]
                //   get collection name and element index
                int indexStart = propertyNamePart.IndexOf("[")+1;
                string collectionPropertyName = propertyNamePart.Substring(0, indexStart-1);
                int collectionElementIndex = Int32.Parse(propertyNamePart.Substring(indexStart, propertyNamePart.Length-indexStart-1));
                //   get collection object
                PropertyInfo pi = obj.GetType().GetProperty(collectionPropertyName);
                if (pi == null) return null;
                object unknownCollection = pi.GetValue(obj, null);
                //   try to process the collection as array
                if (unknownCollection.GetType().IsArray)
                {
                    object[] collectionAsArray = unknownCollection as object[];
                    obj = collectionAsArray[collectionElementIndex];
                }
                else
                {
                    //   try to process the collection as IList
                    System.Collections.IList collectionAsList = unknownCollection as System.Collections.IList;
                    if (collectionAsList != null)
                    {
                        obj = collectionAsList[collectionElementIndex];
                    }
                    else
                    {
                        // ??? Unsupported collection type
                    }
                }
            }
        }

        return obj;
    }

看看Heleonix。反映图书馆。你可以通过路径获取/设置/调用成员，或者创建一个getter/setter (lambda编译成委托)，这比反射更快。例如:

var success = Reflector.Get(DateTime.Now, null, "Date.Year", out int value);

或者只创建一个getter并缓存以供重用(这样性能更好，但如果中间成员为空可能会抛出NullReferenceException):

var getter = Reflector.CreateGetter<DateTime, int>("Date.Year", typeof(DateTime));
getter(DateTime.Now);

或者如果你想创建一个List<Action<object, object>>的不同getter，只需要为已编译的委托指定基本类型(类型转换将被添加到已编译的lambdas中):

var getter = Reflector.CreateGetter<object, object>("Date.Year", typeof(DateTime));
getter(DateTime.Now);

捷径....

var a = new Test { Id = 1 , Name = "A" , date = DateTime.Now};
var b = new Test { Id = 1 , Name = "AXXX", date = DateTime.Now };

var compare = string.Join("",a.GetType().GetProperties().Select(x => x.GetValue(a)).ToArray())==
              string.Join("",b.GetType().GetProperties().Select(x => x.GetValue(b)).ToArray());

虽然最初的问题是关于如何仅使用一个字符串作为参数来获取属性的值，但是在这里使用Expression而不是简单的字符串来确保调用者永远不会使用硬编码的属性名是很有意义的。下面是一行的用法:

public static class Utils
...
    public static TVal GetPropertyValue<T, TVal>(T t, Expression<Func<T, TVal>> x)
        => (TVal)((x.Body as MemberExpression)?.Member as PropertyInfo)!.GetValue(t);

...
    var val = Utils.GetPropertyValue(foo,  p => p.Bar);

下面是一个在可读性方面稍微好一点的错误处理版本:

public static TVal GetPropertyValue<T, TVal>(T t, Expression<Func<T, TVal>> x)
{
    var m = (x.Body as MemberExpression)?.Member;
    var p = m as PropertyInfo;

    if (null == p)
        throw new ArgumentException($"Unknown property: {typeof(T).Name}.{(m?.Name??"???")}");

    return (TVal)p.GetValue(t);
}

简而言之，您传递了一个读取属性的lambda表达式。lambda的主体(胖箭头右边的部分)是一个成员表达式，您可以从中获取成员名称并将其转换为PropertyInfo，前提是该成员实际上是一个Property，而不是(例如)一个方法。

在简短的版本中，null宽恕操作符——the !-告诉编译器PropertyInfo不会为空。这是一个很大的谎言，你将在运行时得到一个NullReferenceException。较长的版本提供了属性的名称(如果它设法获得该属性的话)。

PS:感谢Oleg G.为这段代码的初始版本:)