我知道下面是不可能的,因为枚举的类型必须是int

enum GroupTypes
{
    TheGroup = "OEM",
    TheOtherGroup = "CMB"
}

从我的数据库中,我得到了一个不全面的代码字段(OEM和CMBs)。我想让这个字段成为一个枚举或其他可以理解的东西。因为如果目标是可读性,解决方案就应该简洁。

我还有其他选择吗?


当前回答

使用类。

编辑:更好的例子

class StarshipType
{
    private string _Name;
    private static List<StarshipType> _StarshipTypes = new List<StarshipType>();

    public static readonly StarshipType Ultralight = new StarshipType("Ultralight");
    public static readonly StarshipType Light = new StarshipType("Light");
    public static readonly StarshipType Mediumweight = new StarshipType("Mediumweight");
    public static readonly StarshipType Heavy = new StarshipType("Heavy");
    public static readonly StarshipType Superheavy = new StarshipType("Superheavy");

    public string Name
    {
        get { return _Name; }
        private set { _Name = value; }
    }

    public static IList<StarshipType> StarshipTypes
    {
        get { return _StarshipTypes; }
    }

    private StarshipType(string name, int systemRatio)
    {
        Name = name;
        _StarshipTypes.Add(this);
    }

    public static StarshipType Parse(string toParse)
    {
        foreach (StarshipType s in StarshipTypes)
        {
            if (toParse == s.Name)
                return s;
        }
        throw new FormatException("Could not parse string.");
    }
}

其他回答

我只需创建一个字典,并使用代码作为键。

编辑:为了解决关于执行反向查找(查找键)的注释,这将不是非常有效。如果有必要,我将编写一个新类来处理它。

这里是扩展方法,我用来获得枚举值作为字符串。首先是枚举。

public enum DatabaseEnvironment
{
    [Description("AzamSharpBlogDevDatabase")]
    Development = 1, 
    [Description("AzamSharpBlogQADatabase")]
    QualityAssurance = 2, 
    [Description("AzamSharpBlogTestDatabase")] 
    Test = 3
}

Description属性来自System.ComponentModel。

这是我的扩展方法:

public static string GetValueAsString(this DatabaseEnvironment environment) 
{
    // get the field 
    var field = environment.GetType().GetField(environment.ToString());
    var customAttributes = field.GetCustomAttributes(typeof (DescriptionAttribute), false);

    if(customAttributes.Length > 0)
    {
        return (customAttributes[0] as DescriptionAttribute).Description;  
    }
    else
    {
        return environment.ToString(); 
    }
}

现在,你可以使用下面的代码访问枚举字符串值:

[TestFixture]
public class when_getting_value_of_enum
{
    [Test]
    public void should_get_the_value_as_string()
    {
        Assert.AreEqual("AzamSharpBlogTestDatabase",DatabaseEnvironment.Test.GetValueAsString());  
    }
}

如果不是你的枚举的所有值都有一个字符串,如果你想稍后设置这些值,我使用如下类:

 public class SessionResoult
{
    public enum SessionResoultType
    {
        Success,
        Error,
    }
    public SessionResoult(SessionResoultType sesionResoultType, string value = null)
    {
        Type = sesionResoultType;
        Value = value;
       
    }

    public SessionResoultType Type { get; set; }

    public string Value { get; private set; }
  

    public sealed class Success : SessionResoult
    {
        public Success() : base(SessionResoultType.Success) { }
    }

    public sealed class Error : SessionResoult
    {
        public Error(string value) : base(SessionResoultType.Error, value) { }
    }

    public override string ToString()
    {
        if(this is Success)
        {
            return (SessionResoultType.Success.ToString());
        }else if(this is Error)
        {
            return $"{SessionResoultType.Error}:{this.Value}";
        }
        else { return base.ToString(); }
    }

}

使用的例子:

private SessionResoult ok = new SessionResoult. success ();private SessionResoult错误=新的SessionResoult。错误(“没有可用的网络”);

摘自@EvenMien,并添加了一些评论。(也适用于我自己的用例)

public struct AgentAction
{
    private AgentAction(string value) { Value = value; }

    public string Value { get; private set; }

    public override string ToString() { return this.Value; }
    
    public static AgentAction Login = new AgentAction("Login");
    public static AgentAction Logout = new AgentAction("Logout");

    public static implicit operator string(AgentAction action) { return action.ToString(); }
}

我想完全避免使用字符串字面量,而且我也不需要在项目描述中有空间。更重要的是,我想要有一种机制来检查所提供的字符串是否是一个有效的项目,所以我想出了这个解决方案:

public class Seasons
{
    public static string Spring { get; }
    public static string Summer { get; }
    public static string Fall { get; }
    public static string Winter { get; }

    public static bool IsValid(string propertyName)
    {
        if (string.IsNullOrEmpty(propertyName))
        {
            return false;
        }

        try
        {           
            return typeof(Seasons).GetProperty(propertyName) != null;
        }
        catch
        {
            return false;
        }       
    }
}

它是这样工作的:

void Main()
{
    string s = nameof(Seasons.Fall);
    Console.WriteLine($"Fall is valid: {Seasons.IsValid(s)}"); // true

    s = "WrongSeason";
    Console.WriteLine($"WrongSeason is valid: {Seasons.IsValid(s)}"); // false
}

我尝试将IsValid()重构为基类并使用反射来读取类型(MethodBase.GetCurrentMethod(). declaringtype),但由于我希望它是静态的,所以它返回基类类型,而不是继承的类型。你的补救措施将是非常欢迎的!这就是我想要达到的目标:

public  class Seasons : ConstantStringsBase
{
    // ... same
}

public  class ConstantStringsBase
{
    public static bool IsValid(string propertyName)
    {       
        return MethodBase.GetCurrentMethod().DeclaringType.GetProperty(propertyName) != null;
    }
}