只使用内置的sys:

import sys

def print_progress_bar(index, total, label):
    n_bar = 50  # Progress bar width
    progress = index / total
    sys.stdout.write('\r')
    sys.stdout.write(f"[{'=' * int(n_bar * progress):{n_bar}s}] {int(100 * progress)}%  {label}")
    sys.stdout.flush()

用法:

foo_list = ["a", "b", "c", "d"]
total = len(foo_list)

for index, item in enumerate(foo_list):
    print_progress_bar(index, total, "foo bar")
    sleep(0.5)

Enumerate (foo_list)使您可以在循环期间访问索引值。

输出:

[================================================  ] 96%  foo bar  

正如Mark Rushakoff的解决方案中所描述的，您可以输出回车符sys.stdout.write('\r')来将光标重置到行首。要泛化该解决方案，同时实现Python 3的f- string，您可以使用

from time import sleep
import sys

n_bar = 50
iterable = range(33)  # for demo purposes
n_iter = len(iterable)
for i, item in enumerate(iterable):
    j = (i + 1) / n_iter

    sys.stdout.write('\r')
    sys.stdout.write(f"[{'=' * int(n_bar * j):{n_bar}s}] {int(100 * j)}%")
    sys.stdout.flush()

    sleep(0.05)  
    # do something with <item> here

要成为纯python并且不进行系统调用:

from time import sleep

for i in range(21):
    spaces = " " * (20 - i)
    percentage = 5*i
    print(f"\r[{'='*i}{spaces}]{percentage}%", flush=True, end="")
    sleep(0.25)

下面是我使用@Mark-Rushakoff的解决方案制作的一些东西。自适应调整到终端宽度。

from time import sleep
import os
import sys
from math import ceil

l = list(map(int,os.popen('stty size','r').read().split()))
col = l[1]
col = col - 6

for i in range(col):
    sys.stdout.write('\r')
    getStr = "[%s " % ('='*i)
    sys.stdout.write(getStr.ljust(col)+"]"+"%d%%" % (ceil((100/col)*i)))
    sys.stdout.flush()
    sleep(0.25)
print("")

使用@Mark-Rushakoff的答案，我想出了一个更简单的方法，不需要调用sys库。它适用于Python 3。Windows测试:

from time import sleep
for i in range(21):
    # the exact output you're looking for:
    print ("\r[%-20s] %d%%" % ('='*i, 5*i), end='')
    sleep(0.25)

你可以使用\r(回车)。演示:

import sys
total = 10000000
point = total / 100
increment = total / 20
for i in xrange(total):
    if(i % (5 * point) == 0):
        sys.stdout.write("\r[" + "=" * (i / increment) +  " " * ((total - i)/ increment) + "]" +  str(i / point) + "%")
        sys.stdout.flush()