在java中输入链接描述hereService Manager将获得J中接口的所有实现类

将它们添加到父类构造函数(this. getclass (). getname())内部的静态映射(或创建一个默认映射)，但这将在运行时更新。如果可以选择延迟初始化，可以尝试这种方法。

还要注意的是，这当然只能找到当前类路径中存在的所有子类。想必这对于你目前所看到的是可以的，而且你也有可能考虑过这一点，但如果你在任何时候发布了一个非最终类(对于不同程度的“狂野”)，那么其他人已经编写了他们自己的子类，而你不知道这是完全可行的。

Thus if you happened to be wanting to see all subclasses because you want to make a change and are going to see how it affects subclasses' behaviour - then bear in mind the subclasses that you can't see. Ideally all of your non-private methods, and the class itself should be well-documented; make changes according to this documentation without changing the semantics of methods/non-private fields and your changes should be backwards-compatible, for any subclass that followed your definition of the superclass at least.

我只是写了一个简单的演示来使用org.reflections.Reflections来获取抽象类的子类:

https://github.com/xmeng1/ReflectionsDemo

我需要将此作为一个测试用例，以查看是否向代码中添加了新的类。这就是我所做的

final static File rootFolder = new File(SuperClass.class.getProtectionDomain().getCodeSource().getLocation().getPath());
private static ArrayList<String> files = new ArrayList<String>();
listFilesForFolder(rootFolder); 

@Test(timeout = 1000)
public void testNumberOfSubclasses(){
    ArrayList<String> listSubclasses = new ArrayList<>(files);
    listSubclasses.removeIf(s -> !s.contains("Superclass.class"));
    for(String subclass : listSubclasses){
        System.out.println(subclass);
    }
    assertTrue("You did not create a new subclass!", listSubclasses.size() >1);     
}

public static void listFilesForFolder(final File folder) {
    for (final File fileEntry : folder.listFiles()) {
        if (fileEntry.isDirectory()) {
            listFilesForFolder(fileEntry);
        } else {
            files.add(fileEntry.getName().toString());
        }
    }
}

我知道我在这个派对上晚了几年，但我遇到这个问题是为了解决同样的问题。如果您正在编写Eclipse Plugin(从而利用它们的缓存等)，您可以通过编程方式使用Eclipse的内部搜索来查找实现接口的类。这是我(非常粗糙的)第一次剪:

  protected void listImplementingClasses( String iface ) throws CoreException
  {
    final IJavaProject project = <get your project here>;
    try
    {
      final IType ifaceType = project.findType( iface );
      final SearchPattern ifacePattern = SearchPattern.createPattern( ifaceType, IJavaSearchConstants.IMPLEMENTORS );
      final IJavaSearchScope scope = SearchEngine.createWorkspaceScope();
      final SearchEngine searchEngine = new SearchEngine();
      final LinkedList<SearchMatch> results = new LinkedList<SearchMatch>();
      searchEngine.search( ifacePattern, 
      new SearchParticipant[]{ SearchEngine.getDefaultSearchParticipant() }, scope, new SearchRequestor() {

        @Override
        public void acceptSearchMatch( SearchMatch match ) throws CoreException
        {
          results.add( match );
        }

      }, new IProgressMonitor() {

        @Override
        public void beginTask( String name, int totalWork )
        {
        }

        @Override
        public void done()
        {
          System.out.println( results );
        }

        @Override
        public void internalWorked( double work )
        {
        }

        @Override
        public boolean isCanceled()
        {
          return false;
        }

        @Override
        public void setCanceled( boolean value )
        {
        }

        @Override
        public void setTaskName( String name )
        {
        }

        @Override
        public void subTask( String name )
        {
        }

        @Override
        public void worked( int work )
        {
        }

      });

    } catch( JavaModelException e )
    {
      e.printStackTrace();
    }
  }

到目前为止，我看到的第一个问题是，我只捕获直接实现接口的类，而不是它们的所有子类——但一点递归不会伤害任何人。