我只是使用XmlWriter创建了一些XML,以便在HTTP响应中发回。如何创建JSON字符串?我猜你会使用stringbuilder来构建JSON字符串,然后将响应格式化为JSON?


当前回答

这个代码片段使用了。net 3.5中System.Runtime.Serialization.Json中的DataContractJsonSerializer。

public static string ToJson<T>(/* this */ T value, Encoding encoding)
{
    var serializer = new DataContractJsonSerializer(typeof(T));

    using (var stream = new MemoryStream())
    {
        using (var writer = JsonReaderWriterFactory.CreateJsonWriter(stream, encoding))
        {
            serializer.WriteObject(writer, value);
        }

        return encoding.GetString(stream.ToArray());
    }
}

其他回答

看看http://www.codeplex.com/json/上的json-net。aspx项目。为什么要重新发明轮子?

如果你需要复杂的结果(嵌入),创建你自己的结构:

class templateRequest
{
    public String[] registration_ids;
    public Data data;
    public class Data
    {
        public String message;
        public String tickerText;
        public String contentTitle;
        public Data(String message, String tickerText, string contentTitle)
        {
            this.message = message;
            this.tickerText = tickerText;
            this.contentTitle = contentTitle;
        }                
    };
}

然后通过调用获取JSON字符串

List<String> ids = new List<string>() { "id1", "id2" };
templateRequest request = new templeteRequest();
request.registration_ids = ids.ToArray();
request.data = new templateRequest.Data("Your message", "Your ticker", "Your content");

string json = new JavaScriptSerializer().Serialize(request);

结果是这样的:

json = "{\"registration_ids\":[\"id1\",\"id2\"],\"data\":{\"message\":\"Your message\",\"tickerText\":\"Your ticket\",\"contentTitle\":\"Your content\"}}"

希望能有所帮助!

编码使用

JSON数组的简单对象EncodeJsObjectArray()

public class dummyObject
{
    public string fake { get; set; }
    public int id { get; set; }

    public dummyObject()
    {
        fake = "dummy";
        id = 5;
    }

    public override string ToString()
    {
        StringBuilder sb = new StringBuilder();
        sb.Append('[');
        sb.Append(id);
        sb.Append(',');
        sb.Append(JSONEncoders.EncodeJsString(fake));
        sb.Append(']');

        return sb.ToString();
    }
}

dummyObject[] dummys = new dummyObject[2];
dummys[0] = new dummyObject();
dummys[1] = new dummyObject();

dummys[0].fake = "mike";
dummys[0].id = 29;

string result = JSONEncoders.EncodeJsObjectArray(dummys);

论点: [29,“迈克”[5],“笨蛋”]

漂亮的用法

Pretty print JSON数组PrettyPrintJson()字符串扩展方法

string input = "[14,4,[14,\"data\"],[[5,\"10.186.122.15\"],[6,\"10.186.122.16\"]]]";
string result = input.PrettyPrintJson();

结果是:

[
   14,
   4,
   [
      14,
      "data"
   ],
   [
      [
         5,
         "10.186.122.15"
      ],
      [
         6,
         "10.186.122.16"
      ]
   ]
]

DataContractJSONSerializer将像XMLSerializer一样简单地为您做所有事情。在web应用程序中使用它很简单。如果你正在使用WCF,你可以用一个属性指定它的用途。DataContractSerializer系列也非常快。

包括:

使用System.Text.Json;

然后像这样序列化你的object_to_serialize: JsonSerializer.Serialize (object_to_serialize)