我正在寻找在我的. net核心Web API控制器中返回带有HTTP状态代码的JSON的正确方法。我以前是这样用的:
public IHttpActionResult GetResourceData()
{
return this.Content(HttpStatusCode.OK, new { response = "Hello"});
}
这是在一个4.6 MVC应用程序，但现在与。net核心，我似乎没有这个IHttpActionResult，我有ActionResult和使用像这样:
public ActionResult IsAuthenticated()
{
return Ok(Json("123"));
}
但是服务器的反应很奇怪，如下图所示:
我只是想让Web API控制器返回带有HTTP状态码的JSON，就像我在Web API 2中所做的那样。
当前回答
我要用这个。我的大问题是我的json是一个字符串(在我的数据库…而不是特定的/已知的类型)。
好吧，我终于把它弄好了。
////[Route("api/[controller]")]
////[ApiController]
////public class MyController: Microsoft.AspNetCore.Mvc.ControllerBase
////{
//// public IActionResult MyMethod(string myParam) {
string hardCodedJson = "{}";
int hardCodedStatusCode = 200;
Newtonsoft.Json.Linq.JObject job = Newtonsoft.Json.Linq.JObject.Parse(hardCodedJson);
/* "this" comes from your class being a subclass of Microsoft.AspNetCore.Mvc.ControllerBase */
Microsoft.AspNetCore.Mvc.ContentResult contRes = this.Content(job.ToString());
contRes.StatusCode = hardCodedStatusCode;
return contRes;
//// } ////end MyMethod
//// } ////end class
我恰巧用的是asp.net core 3.1
#region Assembly Microsoft.AspNetCore.Mvc.Core, Version=3.1.0.0, Culture=neutral, PublicKeyToken=adb9793829ddae60
//C:\Program Files\dotnet\packs\Microsoft.AspNetCore.App.Ref\3.1.0\ref\netcoreapp3.1\Microsoft.AspNetCore.Mvc.Core.dll
我从这里得到了提示::https://www.jianshu.com/p/7b3e92c42b61
其他回答
我发现的最干净的解决方案是在Startup.cs中的ConfigureServices方法中设置以下内容(在我的情况下，我希望剥离TZ信息。我总是希望看到用户看到的日期时间)。
services.AddControllers()
.AddNewtonsoftJson(o =>
{
o.SerializerSettings.DateTimeZoneHandling = DateTimeZoneHandling.Unspecified;
});
DateTimeZoneHandling选项有Utc、Unspecified、Local或RoundtripKind
我仍然想找到一种方法，能够在每个呼叫的基础上请求这一点。
类似的
static readonly JsonMediaTypeFormatter _jsonFormatter = new JsonMediaTypeFormatter();
_jsonFormatter.SerializerSettings = new JsonSerializerSettings()
{DateTimeZoneHandling = DateTimeZoneHandling.Unspecified};
return Ok("Hello World", _jsonFormatter );
我从ASP转换。NET，在那里我使用了下面的helper方法
public static ActionResult<T> Ok<T>(T result, HttpContext context)
{
var responseMessage = context.GetHttpRequestMessage().CreateResponse(HttpStatusCode.OK, result, _jsonFormatter);
return new ResponseMessageResult(responseMessage);
}
我要用这个。我的大问题是我的json是一个字符串(在我的数据库…而不是特定的/已知的类型)。
好吧，我终于把它弄好了。
////[Route("api/[controller]")]
////[ApiController]
////public class MyController: Microsoft.AspNetCore.Mvc.ControllerBase
////{
//// public IActionResult MyMethod(string myParam) {
string hardCodedJson = "{}";
int hardCodedStatusCode = 200;
Newtonsoft.Json.Linq.JObject job = Newtonsoft.Json.Linq.JObject.Parse(hardCodedJson);
/* "this" comes from your class being a subclass of Microsoft.AspNetCore.Mvc.ControllerBase */
Microsoft.AspNetCore.Mvc.ContentResult contRes = this.Content(job.ToString());
contRes.StatusCode = hardCodedStatusCode;
return contRes;
//// } ////end MyMethod
//// } ////end class
我恰巧用的是asp.net core 3.1
#region Assembly Microsoft.AspNetCore.Mvc.Core, Version=3.1.0.0, Culture=neutral, PublicKeyToken=adb9793829ddae60
//C:\Program Files\dotnet\packs\Microsoft.AspNetCore.App.Ref\3.1.0\ref\netcoreapp3.1\Microsoft.AspNetCore.Mvc.Core.dll
我从这里得到了提示::https://www.jianshu.com/p/7b3e92c42b61
请参考以下代码，您可以管理多个状态代码与不同类型的JSON
public async Task<HttpResponseMessage> GetAsync()
{
try
{
using (var entities = new DbEntities())
{
var resourceModelList = entities.Resources.Select(r=> new ResourceModel{Build Your Resource Model}).ToList();
if (resourceModelList.Count == 0)
{
return this.Request.CreateResponse<string>(HttpStatusCode.NotFound, "No resources found.");
}
return this.Request.CreateResponse<List<ResourceModel>>(HttpStatusCode.OK, resourceModelList, "application/json");
}
}
catch (Exception ex)
{
return this.Request.CreateResponse<string>(HttpStatusCode.InternalServerError, "Something went wrong.");
}
}
我想到的最简单的方法是:
var result = new Item { Id = 123, Name = "Hero" };
return new JsonResult(result)
{
StatusCode = StatusCodes.Status201Created // Status code here
};
而不是使用404/201状态代码使用enum
public async Task<IActionResult> Login(string email, string password)
{
if (string.IsNullOrWhiteSpace(email) || string.IsNullOrWhiteSpace(password))
{
return StatusCode((int)HttpStatusCode.BadRequest, Json("email or password is null"));
}
var user = await _userManager.FindByEmailAsync(email);
if (user == null)
{
return StatusCode((int)HttpStatusCode.BadRequest, Json("Invalid Login and/or password"));
}
var passwordSignInResult = await _signInManager.PasswordSignInAsync(user, password, isPersistent: true, lockoutOnFailure: false);
if (!passwordSignInResult.Succeeded)
{
return StatusCode((int)HttpStatusCode.BadRequest, Json("Invalid Login and/or password"));
}
return StatusCode((int)HttpStatusCode.OK, Json("Sucess !!!"));
}
