其他答案充分回答了这个问题，但我想分享一些额外的信息。其他人描述“describe table”语法以获取表信息。如果你想获得相同格式的信息，但不使用DESCRIBE，你可以这样做:

SELECT column_name as COLUMN_NAME, nullable || '       ' as BE_NULL,
  SUBSTR(data_type || '(' || data_length || ')', 0, 10) as TYPE
 FROM all_tab_columns WHERE table_name = 'TABLENAME';

可能不太重要，但我之前写过，它似乎是合适的。

对于SQL Server 2008，我们可以使用information_schema。列用于获取列信息

SELECT *
FROM   information_schema.columns
WHERE  table_name = 'Table_Name'
ORDER  BY ordinal_position  

试试这个

select * from sys.all_columns c join sys.objects o on c.object_id=o.object_id where o.name = 'TABLENAME' and c.name like '%COLUMN NAME%'

SELECT COLUMN_NAME 'all_columns' 
FROM INFORMATION_SCHEMA.COLUMNS 
WHERE TABLE_NAME='user';

SELECT A.COLUMN_NAME, A.* FROM all_tab_columns a 
WHERE table_name = 'Your Table Name'
AND A.COLUMN_NAME = 'COLUMN NAME' AND a.owner = 'Schema'

在SQL Server中…

SELECT [name] AS [Column Name]
FROM syscolumns
WHERE id = (SELECT id FROM sysobjects WHERE type = 'V' AND [Name] = 'Your table name')

Type = 'V'表示视图 Type = 'U'表示表