什么是最有效的方式来克隆一个JavaScript对象?我已经看到obj = eval(uneval(o));被使用,但它是非标准的,仅支持Firefox.我做了事情,如obj = JSON.parse(JSON.stringify(o));但质疑效率。
当前回答
如下图所示,John Resig的jQuery克隆器将非数字属性的<unk>转化为非数字属性的对象,而RegDwight的JSON克隆器将非数字属性放下。
function jQueryClone(obj) {
return jQuery.extend(true, {}, obj)
}
function JSONClone(obj) {
return JSON.parse(JSON.stringify(obj))
}
var arrayLikeObj = [[1, "a", "b"], [2, "b", "a"]];
arrayLikeObj.names = ["m", "n", "o"];
var JSONCopy = JSONClone(arrayLikeObj);
var jQueryCopy = jQueryClone(arrayLikeObj);
alert("Is arrayLikeObj an array instance?" + (arrayLikeObj instanceof Array) +
"\nIs the jQueryClone an array instance? " + (jQueryCopy instanceof Array) +
"\nWhat are the arrayLikeObj names? " + arrayLikeObj.names +
"\nAnd what are the JSONClone names? " + JSONCopy.names)
其他回答
Lodash 有一个可爱的 _.cloneDeep(值) 方法:
var objects = [{ 'a': 1 }, { 'b': 2 }];
var deep = _.cloneDeep(objects);
console.log(deep[0] === objects[0]);
// => false
因为回归只是太昂贵的JavaScript,我发现的大多数答案是使用回归,而JSON方法将错过非JSON转换部分(功能等)。所以我做了一些研究,并发现这个拖拉机技术避免它。
/*
* Trampoline to avoid recursion in JavaScript, see:
* https://www.integralist.co.uk/posts/functional-recursive-javascript-programming/
*/
function trampoline() {
var func = arguments[0];
var args = [];
for (var i = 1; i < arguments.length; i++) {
args[i - 1] = arguments[i];
}
var currentBatch = func.apply(this, args);
var nextBatch = [];
while (currentBatch && currentBatch.length > 0) {
currentBatch.forEach(function(eachFunc) {
var ret = eachFunc();
if (ret && ret.length > 0) {
nextBatch = nextBatch.concat(ret);
}
});
currentBatch = nextBatch;
nextBatch = [];
}
};
/*
* Deep clone an object using the trampoline technique.
*
* @param target {Object} Object to clone
* @return {Object} Cloned object.
*/
function clone(target) {
if (typeof target !== 'object') {
return target;
}
if (target == null || Object.keys(target).length == 0) {
return target;
}
function _clone(b, a) {
var nextBatch = [];
for (var key in b) {
if (typeof b[key] === 'object' && b[key] !== null) {
if (b[key] instanceof Array) {
a[key] = [];
}
else {
a[key] = {};
}
nextBatch.push(_clone.bind(null, b[key], a[key]));
}
else {
a[key] = b[key];
}
}
return nextBatch;
};
var ret = target instanceof Array ? [] : {};
(trampoline.bind(null, _clone))(target, ret);
return ret;
};
只是因为我没有看到AngularJS提到并认为人们可能想知道......
angular.copy 还提供深复制对象和序列的方法。
A Recursive Deep Clone 比 JSON.parse(JSON.stringify(obj)) 提到的更快。
Jsperf 在这里排名第一: https://jsperf.com/deep-copy-vs-json-stringify-json-parse/5 Jsben 从上面的答案更新显示,一个重复的深度克隆打击所有其他提到的: http://jsben.ch/13YKQ
下面是快速参考的功能:
function cloneDeep (o) {
let newO
let i
if (typeof o !== 'object') return o
if (!o) return o
if (Object.prototype.toString.apply(o) === '[object Array]') {
newO = []
for (i = 0; i < o.length; i += 1) {
newO[i] = cloneDeep(o[i])
}
return newO
}
newO = {}
for (i in o) {
if (o.hasOwnProperty(i)) {
newO[i] = cloneDeep(o[i])
}
}
return newO
}
Object.assign({},sourceObj)只有在其属性没有参考类型密钥时才会克隆对象。
obj={a:"lol",b:["yes","no","maybe"]}
clonedObj = Object.assign({},obj);
clonedObj.b.push("skip")// changes will reflected to the actual obj as well because of its reference type.
obj.b //will also console => yes,no,maybe,skip
因此,对于深度克隆,不可能以这种方式实现。
最有效的解决方案是
var obj = Json.stringify(yourSourceObj)
var cloned = Json.parse(obj);