命名空间通常通过以下方式实现:

stack_push(thing *)

而不是

stack::push(thing *)

要将C结构体变成类似c++类的东西，您可以转向:

class stack {
     public:
        stack();
        void push(thing *);
        thing * pop();
        static int this_is_here_as_an_example_only;
     private:
        ...
};

Into

struct stack {
     struct stack_type * my_type;
     // Put the stuff that you put after private: here
};
struct stack_type {
     void (* construct)(struct stack * this); // This takes uninitialized memory
     struct stack * (* operator_new)(); // This allocates a new struct, passes it to construct, and then returns it
     void (*push)(struct stack * this, thing * t); // Pushing t onto this stack
     thing * (*pop)(struct stack * this); // Pops the top thing off the stack and returns it
     int this_is_here_as_an_example_only;
}Stack = {
    .construct = stack_construct,
    .operator_new = stack_operator_new,
    .push = stack_push,
    .pop = stack_pop
};
// All of these functions are assumed to be defined somewhere else

和做的事:

struct stack * st = Stack.operator_new(); // Make a new stack
if (!st) {
   // Do something about it
} else {
   // You can use the stack
   stack_push(st, thing0); // This is a non-virtual call
   Stack.push(st, thing1); // This is like casting *st to a Stack (which it already is) and doing the push
   st->my_type.push(st, thing2); // This is a virtual call
}

我没有做析构函数或删除，但它遵循相同的模式。

This_is_here_as_an_example_only类似于一个静态类变量——在一个类型的所有实例之间共享。所有的方法都是静态的，除了一些采用this *

在Jim Larson 1996年在312节编程午餐研讨会上的演讲中有一个使用C进行继承的例子:高级和低级C。

命名空间通常通过以下方式实现:

stack_push(thing *)

而不是

stack::push(thing *)

要将C结构体变成类似c++类的东西，您可以转向:

class stack {
     public:
        stack();
        void push(thing *);
        thing * pop();
        static int this_is_here_as_an_example_only;
     private:
        ...
};

Into

struct stack {
     struct stack_type * my_type;
     // Put the stuff that you put after private: here
};
struct stack_type {
     void (* construct)(struct stack * this); // This takes uninitialized memory
     struct stack * (* operator_new)(); // This allocates a new struct, passes it to construct, and then returns it
     void (*push)(struct stack * this, thing * t); // Pushing t onto this stack
     thing * (*pop)(struct stack * this); // Pops the top thing off the stack and returns it
     int this_is_here_as_an_example_only;
}Stack = {
    .construct = stack_construct,
    .operator_new = stack_operator_new,
    .push = stack_push,
    .pop = stack_pop
};
// All of these functions are assumed to be defined somewhere else

和做的事:

struct stack * st = Stack.operator_new(); // Make a new stack
if (!st) {
   // Do something about it
} else {
   // You can use the stack
   stack_push(st, thing0); // This is a non-virtual call
   Stack.push(st, thing1); // This is like casting *st to a Stack (which it already is) and doing the push
   st->my_type.push(st, thing2); // This is a virtual call
}

我没有做析构函数或删除，但它遵循相同的模式。

This_is_here_as_an_example_only类似于一个静态类变量——在一个类型的所有实例之间共享。所有的方法都是静态的，除了一些采用this *

C的stdio FILE子库是如何在纯C中创建抽象、封装和模块化的极好示例。

继承和多态性——通常被认为是OOP必不可少的其他方面——不一定能提供它们所承诺的生产率提高，而且有合理的理由认为它们实际上会阻碍开发和对问题域的思考。

添加一点OOC代码:

#include <stdio.h>

struct Node {
    int somevar;
};

void print() {
    printf("Hello from an object-oriented C method!");
};

struct Tree {
    struct Node * NIL;
    void (*FPprint)(void);
    struct Node *root;
    struct Node NIL_t;
} TreeA = {&TreeA.NIL_t,print};

int main()
{
    struct Tree TreeB;
    TreeB = TreeA;
    TreeB.FPprint();
    return 0;
}

我相信，用C语言实现OOP除了本身很有用外，还是学习OOP和理解其内部工作原理的好方法。许多程序员的经验表明，要有效和自信地使用一项技术，程序员必须理解底层概念最终是如何实现的。在C语言中模拟类、继承和多态性就教会了我们这一点。

为了回答最初的问题，这里有一些资源，教如何在C中进行OOP:

embeddegurus.com博客文章“C中基于对象的编程”展示了如何在可移植C中实现类和单继承: http://embeddedgurus.com/state-space/2008/01/object-based-programming-in-c/

应用笔记“C+ - C面向对象编程”展示了如何使用预处理器宏在C中实现类、单继承和后期绑定(多态性): http://www.state-machine.com/resources/cplus_3.0_manual.pdf，示例代码可从http://www.state-machine.com/resources/cplus_3.0.zip获得