是否有一种简单的单行方式来获取表单的数据,就像以经典的仅html方式提交表单一样?

例如:

<form>
    <input type="radio" name="foo" value="1" checked="checked" />
    <input type="radio" name="foo" value="0" />
    <input name="bar" value="xxx" />
    <select name="this">
        <option value="hi" selected="selected">Hi</option>
        <option value="ho">Ho</option>
</form>

输出:

{
    "foo": "1",
    "bar": "xxx",
    "this": "hi"
}

像这样的东西太简单了,因为它没有(正确地)包括文本区域,选择,单选按钮和复选框:

$("#form input").each(function () {
    data[theFieldName] = theFieldValue;
});

当前回答

$( "form" ).bind( "submit", function(e) { e.preventDefault(); console.log( $(this).serializeObject() ); //console.log( $(this).serialize() ); //console.log( $(this).serializeArray() ); }); $.fn.serializeObject = function() { var o = {}; var a = this.serializeArray(); $.each( a, function() { if ( o[this.name] !== undefined) { if ( ! o[this.name].push ) { o[this.name] = [o[this.name]]; } o[this.name].push(this.value || ''); } else { o[this.name] = this.value || ''; } }); return o; }; <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script> <form> <input type="radio" name="foo" value="1" checked="checked" /> <input type="radio" name="foo" value="0" /> <input name="bar" value="xxx" /> <select name="this"> <option value="hi" selected="selected">Hi</option> <option value="ho">Ho</option> </select> <input type="submit" value="Submit" /> </form>

Codepen

其他回答

你可以使用这个函数从表单中获取一个对象或JSON。

使用它:

var object = formService.getObjectFormFields(“#idform”);

function getObjectFormFields(formSelector) { /// <summary>Função que retorna objeto com base nas propriedades name dos elementos do formulário.</summary> /// <param name="formSelector" type="String">Seletor do formulário</param> var form = $(formSelector); var result = {}; var arrayAuxiliar = []; form.find(":input:text").each(function (index, element) { var name = $(element).attr('name'); var value = $(element).val(); result[name] = value; }); form.find(":input[type=hidden]").each(function (index, element) { var name = $(element).attr('name'); var value = $(element).val(); result[name] = value; }); form.find(":input:checked").each(function (index, element) { var name; var value; if ($(this).attr("type") == "radio") { name = $(element).attr('name'); value = $(element).val(); result[name] = value; } else if ($(this).attr("type") == "checkbox") { name = $(element).attr('name'); value = $(element).val(); if (result[name]) { if (Array.isArray(result[name])) { result[name].push(value); } else { var aux = result[name]; result[name] = []; result[name].push(aux); result[name].push(value); } } else { result[name] = []; result[name].push(value); } } }); form.find("select option:selected").each(function (index, element) { var name = $(element).parent().attr('name'); var value = $(element).val(); result[name] = value; }); arrayAuxiliar = []; form.find("checkbox:checked").each(function (index, element) { var name = $(element).attr('name'); var value = $(element).val(); result[name] = arrayAuxiliar.push(value); }); form.find("textarea").each(function (index, element) { var name = $(element).attr('name'); var value = $(element).val(); result[name] = value; }); return result; }

使用.serializeArray()获取数组格式的数据,然后将其转换为对象:

function getFormObj(formId) {
    var formObj = {};
    var inputs = $('#'+formId).serializeArray();
    $.each(inputs, function (i, input) {
        formObj[input.name] = input.value;
    });
    return formObj;
}

我写了一个函数来处理多个复选框和多个选择。在这些情况下,它返回一个数组。

function getFormData(formId) {
    return $('#' + formId).serializeArray().reduce(function (obj, item) {
        var name = item.name,
            value = item.value;

        if (obj.hasOwnProperty(name)) {
            if (typeof obj[name] == "string") {
                obj[name] = [obj[name]];
                obj[name].push(value);
            } else {
                obj[name].push(value);
            }
        } else {
            obj[name] = value;
        }
        return obj;
    }, {});
}

我编写了一个库来解决这个问题:JSONForms。它采用一个表单,遍历每个输入并构建一个易于阅读的JSON对象。

假设你有以下表单:

<form enctype='application/json'>
  <input name='places[0][city]' value='New York City'>
  <input type='number' name='places[0][population]' value='8175133'>
  <input name='places[1][city]' value='Los Angeles'>
  <input type='number' name='places[1][population]' value='3792621'>
  <input name='places[2][city]' value='Chicago'>
  <input type='number' name='places[2][population]' value='2695598'>
</form>

将表单传递给JSONForms的encode方法将返回以下对象:

{
  "places": [
    {
      "city": "New York City",
      "population": 8175133
    },
    {
      "city": "Los Angeles",
      "population": 3792621
    },
    {
      "city": "Chicago",
      "population": 2695598
    }
  ]
}

下面是表单的演示。

我用这个:

jQuery插件

(function($){
  $.fn.getFormData = function(){
    var data = {};
    var dataArray = $(this).serializeArray();
    for(var i=0;i<dataArray.length;i++){
      data[dataArray[i].name] = dataArray[i].value;
    }
    return data;
  }
})(jQuery);

HTML表单

<form id='myform'>
  <input name='myVar1' />
  <input name='myVar2' />
</form>

获取数据

var myData = $("#myForm").getFormData();