是否有一种简单的单行方式来获取表单的数据,就像以经典的仅html方式提交表单一样?

例如:

<form>
    <input type="radio" name="foo" value="1" checked="checked" />
    <input type="radio" name="foo" value="0" />
    <input name="bar" value="xxx" />
    <select name="this">
        <option value="hi" selected="selected">Hi</option>
        <option value="ho">Ho</option>
</form>

输出:

{
    "foo": "1",
    "bar": "xxx",
    "this": "hi"
}

像这样的东西太简单了,因为它没有(正确地)包括文本区域,选择,单选按钮和复选框:

$("#form input").each(function () {
    data[theFieldName] = theFieldValue;
});

当前回答

基于neuront的响应,我创建了一个简单的JQuery方法,在键值对中获取表单数据,但它适用于多选择和name='example[]'的数组输入。

下面是它的用法:

var form_data = $("#form").getFormObject();

您可以在下面找到它的定义及其工作方式的示例。

// Function start $.fn.getFormObject = function() { var object = $(this).serializeArray().reduce(function(obj, item) { var name = item.name.replace("[]", ""); if ( typeof obj[name] !== "undefined" ) { if ( !Array.isArray(obj[name]) ) { obj[name] = [ obj[name], item.value ]; } else { obj[name].push(item.value); } } else { obj[name] = item.value; } return obj; }, {}); return object; } // Function ends // This is how it's used $("#getObject").click( function() { var form_data = $("#form").getFormObject(); console.log(form_data); }); /* Only to make view better ;) */ #getObject { padding: 10px; cursor:pointer; background:#0098EE; color:white; display:inline-block; } <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script> <form id="form"> <input type="text" name="text" value="Hola amigo" /> <input type="text" name="text_array[]" value="Array 1" /> <input type="text" name="text_array[]" value="Array 2" /> <input type="text" name="text_array[]" value="Array 3" /> <select name="multiselect" multiple> <option name="option1" selected> option 1 </option> <option name="option2" selected> option 2 </option> </select> <input type="checkbox" name="checkbox" value="checkbox1" checked/> <input type="checkbox" name="checkbox" value="checkbox2" checked/> <input type="radio" name="radio" value="radio1" checked/> <input type="radio" name="radio" value="radio2"/> </form> <div id="getObject"> Get object (check the console!) </div>

其他回答

这是一个很好的香草JS函数,我写来提取表单数据作为一个对象。它还具有向对象中插入附加内容和清除表单输入字段的选项。

const extractFormData = ({ form, clear, add }) => {
  return [].slice.call(form.children).filter(node => node.nodeName === 'INPUT')
  .reduce((formData, input) => {
    const value = input.value
    if (clear) { input.value = '' }
    return {
      ...formData,
      [input.name]: value
    }
  }, add)
}

下面是一个使用post请求的例子:

submitGrudge(e) {
  e.preventDefault()

  const form = e.target
  const add = { id: Date.now(), forgiven: false }
  const grudge = extractFormData({ form, add, clear: true })

  // grudge = {
  //  "name": "Example name",
  //  "offense": "Example string",
  //  "date": "2017-02-16",
  //  "id": 1487877281983,
  //  "forgiven": false
  // }

  fetch('http://localhost:3001/api/grudge', {
    method: 'post',
    headers: { 'Content-Type': 'application/json' },
    body: JSON.stringify(grudge)
  })
    .then(response => response.json())
    .then(grudges => this.setState({ grudges }))
    .catch(err => console.log('error: ', err))
}

我编写了一个库来解决这个问题:JSONForms。它采用一个表单,遍历每个输入并构建一个易于阅读的JSON对象。

假设你有以下表单:

<form enctype='application/json'>
  <input name='places[0][city]' value='New York City'>
  <input type='number' name='places[0][population]' value='8175133'>
  <input name='places[1][city]' value='Los Angeles'>
  <input type='number' name='places[1][population]' value='3792621'>
  <input name='places[2][city]' value='Chicago'>
  <input type='number' name='places[2][population]' value='2695598'>
</form>

将表单传递给JSONForms的encode方法将返回以下对象:

{
  "places": [
    {
      "city": "New York City",
      "population": 8175133
    },
    {
      "city": "Los Angeles",
      "population": 3792621
    },
    {
      "city": "Chicago",
      "population": 2695598
    }
  ]
}

下面是表单的演示。

使用$('form').serializeArray(),它返回一个数组:

[
  {"name":"foo","value":"1"},
  {"name":"bar","value":"xxx"},
  {"name":"this","value":"hi"}
]

另一个选项是$('form').serialize(),它返回一个字符串:

"foo=1&bar=xxx&this=hi"

看看这个jsfiddle演示

你可以使用这个函数从表单中获取一个对象或JSON。

使用它:

var object = formService.getObjectFormFields(“#idform”);

function getObjectFormFields(formSelector) { /// <summary>Função que retorna objeto com base nas propriedades name dos elementos do formulário.</summary> /// <param name="formSelector" type="String">Seletor do formulário</param> var form = $(formSelector); var result = {}; var arrayAuxiliar = []; form.find(":input:text").each(function (index, element) { var name = $(element).attr('name'); var value = $(element).val(); result[name] = value; }); form.find(":input[type=hidden]").each(function (index, element) { var name = $(element).attr('name'); var value = $(element).val(); result[name] = value; }); form.find(":input:checked").each(function (index, element) { var name; var value; if ($(this).attr("type") == "radio") { name = $(element).attr('name'); value = $(element).val(); result[name] = value; } else if ($(this).attr("type") == "checkbox") { name = $(element).attr('name'); value = $(element).val(); if (result[name]) { if (Array.isArray(result[name])) { result[name].push(value); } else { var aux = result[name]; result[name] = []; result[name].push(aux); result[name].push(value); } } else { result[name] = []; result[name].push(value); } } }); form.find("select option:selected").each(function (index, element) { var name = $(element).parent().attr('name'); var value = $(element).val(); result[name] = value; }); arrayAuxiliar = []; form.find("checkbox:checked").each(function (index, element) { var name = $(element).attr('name'); var value = $(element).val(); result[name] = arrayAuxiliar.push(value); }); form.find("textarea").each(function (index, element) { var name = $(element).attr('name'); var value = $(element).val(); result[name] = value; }); return result; }

基于jQuery。serializeArray,返回键值对。

var data = $('#form').serializeArray().reduce(function(obj, item) {
    obj[item.name] = item.value;
    return obj;
}, {});