是否有一种简单的单行方式来获取表单的数据,就像以经典的仅html方式提交表单一样?

例如:

<form>
    <input type="radio" name="foo" value="1" checked="checked" />
    <input type="radio" name="foo" value="0" />
    <input name="bar" value="xxx" />
    <select name="this">
        <option value="hi" selected="selected">Hi</option>
        <option value="ho">Ho</option>
</form>

输出:

{
    "foo": "1",
    "bar": "xxx",
    "this": "hi"
}

像这样的东西太简单了,因为它没有(正确地)包括文本区域,选择,单选按钮和复选框:

$("#form input").each(function () {
    data[theFieldName] = theFieldValue;
});

当前回答

var formData = new FormData($('#form-id'));
params   = $('#form-id').serializeArray();

$.each(params, function(i, val) {
    formData.append(val.name, val.value);
});

其他回答

这是我的香草JS版本(在Chrome上测试)

适用于:

name = "输入" Name ="form[Name]"(创建一个对象) Name ="checkbox[]"(创建一个数组对象) Name ="form[checkbox][]"(创建一个数组) Name ="form[select][Name]"(创建一个只包含所选值的对象)

/**
 * Get the values from a form
 * @param formId ( ID without the # )
 * @returns {object}
 */
function getFormValues( formId )
{
    let postData = {};
    let form = document.forms[formId];
    let formData = new FormData( form );

    for ( const value of formData.entries() )
    {
        let container = postData;
        let key = value[0];
        let arrayKeys = key.match( /\[[\w\-]*\]/g ); // Check for any arrays

        if ( arrayKeys !== null )
        {
            arrayKeys.unshift( key.substr( 0, key.search( /\[/ ) ) );  // prepend the first key to the list
            for ( let i = 0, count = arrayKeys.length, lastRun = count - 1; i < count; i++ )
            {
                let _key = arrayKeys[i];
                _key = _key.replace( "[", '' ).replace( "]", '' ); // Remove the brackets []
                if ( _key === '' )
                {
                    if ( ! Array.isArray( container ) )
                    {
                        container = [];
                    }

                    _key = container.length;
                }

                if ( ! (_key in container) ) // Create an object for the key if it doesn't exist
                {
                    if ( i !== lastRun && arrayKeys[i + 1] === '[]' )
                    {
                        container[_key] = [];
                    }
                    else
                    {
                        container[_key] = {};
                    }
                }

                if ( i !== lastRun ) // Until we're the last item, swap container with it's child
                {
                    container = container[_key];
                }

                key = _key;
            }
        }
        container[key] = value[1]; // finally assign the value
    }

    return postData;
}
$("#form input, #form select, #form textarea").each(function() {
 data[theFieldName] = theFieldValue;
});

除此之外,你可能想看看serialize();

function getFormData($form){
    var unindexed_array = $form.serializeArray();
    var indexed_array = {};

    $.map(unindexed_array, function(n, i){
        if(indexed_array[n['name']] == undefined){
            indexed_array[n['name']] = [n['value']];
        }else{
            indexed_array[n['name']].push(n['value']);
        }
    });

    return indexed_array;
}

这个方法应该可以做到。它序列化表单数据,然后将它们转换为对象。还可以处理复选框组。

function getFormObj(formId) {
  var formParams = {};
  $('#' + formId)
    .serializeArray()
    .forEach(function(item) {
      if (formParams[item.name]) {
        formParams[item.name] = [formParams[item.name]];
        formParams[item.name].push(item.value)
      } else {
        formParams[item.name] = item.value
      }
    });
  return formParams;
}

2014年的最新答案:HTML5 FormData做到了这一点

var formData = new FormData(document.querySelector('form'))

然后,您可以准确地发布formData——它包含表单中使用的所有名称和值。