是否有一种简单的单行方式来获取表单的数据,就像以经典的仅html方式提交表单一样?

例如:

<form>
    <input type="radio" name="foo" value="1" checked="checked" />
    <input type="radio" name="foo" value="0" />
    <input name="bar" value="xxx" />
    <select name="this">
        <option value="hi" selected="selected">Hi</option>
        <option value="ho">Ho</option>
</form>

输出:

{
    "foo": "1",
    "bar": "xxx",
    "this": "hi"
}

像这样的东西太简单了,因为它没有(正确地)包括文本区域,选择,单选按钮和复选框:

$("#form input").each(function () {
    data[theFieldName] = theFieldValue;
});

当前回答

这里有一个非常简单和简短的解决方案,甚至不需要Jquery。

var formElements=document.getElementById("myForm").elements;    
var postData={};
for (var i=0; i<formElements.length; i++)
    if (formElements[i].type!="submit")//we dont want to include the submit-buttom
        postData[formElements[i].name]=formElements[i].value;

其他回答

$("#form input, #form select, #form textarea").each(function() {
 data[theFieldName] = theFieldValue;
});

除此之外,你可能想看看serialize();

这里有一个非常简单和简短的解决方案,甚至不需要Jquery。

var formElements=document.getElementById("myForm").elements;    
var postData={};
for (var i=0; i<formElements.length; i++)
    if (formElements[i].type!="submit")//we dont want to include the submit-buttom
        postData[formElements[i].name]=formElements[i].value;
$('form').serialize() //this produces: "foo=1&bar=xxx&this=hi"

demo

我编写了一个库来解决这个问题:JSONForms。它采用一个表单,遍历每个输入并构建一个易于阅读的JSON对象。

假设你有以下表单:

<form enctype='application/json'>
  <input name='places[0][city]' value='New York City'>
  <input type='number' name='places[0][population]' value='8175133'>
  <input name='places[1][city]' value='Los Angeles'>
  <input type='number' name='places[1][population]' value='3792621'>
  <input name='places[2][city]' value='Chicago'>
  <input type='number' name='places[2][population]' value='2695598'>
</form>

将表单传递给JSONForms的encode方法将返回以下对象:

{
  "places": [
    {
      "city": "New York City",
      "population": 8175133
    },
    {
      "city": "Los Angeles",
      "population": 3792621
    },
    {
      "city": "Chicago",
      "population": 2695598
    }
  ]
}

下面是表单的演示。

你可以使用这个函数从表单中获取一个对象或JSON。

使用它:

var object = formService.getObjectFormFields(“#idform”);

function getObjectFormFields(formSelector) { /// <summary>Função que retorna objeto com base nas propriedades name dos elementos do formulário.</summary> /// <param name="formSelector" type="String">Seletor do formulário</param> var form = $(formSelector); var result = {}; var arrayAuxiliar = []; form.find(":input:text").each(function (index, element) { var name = $(element).attr('name'); var value = $(element).val(); result[name] = value; }); form.find(":input[type=hidden]").each(function (index, element) { var name = $(element).attr('name'); var value = $(element).val(); result[name] = value; }); form.find(":input:checked").each(function (index, element) { var name; var value; if ($(this).attr("type") == "radio") { name = $(element).attr('name'); value = $(element).val(); result[name] = value; } else if ($(this).attr("type") == "checkbox") { name = $(element).attr('name'); value = $(element).val(); if (result[name]) { if (Array.isArray(result[name])) { result[name].push(value); } else { var aux = result[name]; result[name] = []; result[name].push(aux); result[name].push(value); } } else { result[name] = []; result[name].push(value); } } }); form.find("select option:selected").each(function (index, element) { var name = $(element).parent().attr('name'); var value = $(element).val(); result[name] = value; }); arrayAuxiliar = []; form.find("checkbox:checked").each(function (index, element) { var name = $(element).attr('name'); var value = $(element).val(); result[name] = arrayAuxiliar.push(value); }); form.find("textarea").each(function (index, element) { var name = $(element).attr('name'); var value = $(element).val(); result[name] = value; }); return result; }