是否有一种简单的单行方式来获取表单的数据,就像以经典的仅html方式提交表单一样?

例如:

<form>
    <input type="radio" name="foo" value="1" checked="checked" />
    <input type="radio" name="foo" value="0" />
    <input name="bar" value="xxx" />
    <select name="this">
        <option value="hi" selected="selected">Hi</option>
        <option value="ho">Ho</option>
</form>

输出:

{
    "foo": "1",
    "bar": "xxx",
    "this": "hi"
}

像这样的东西太简单了,因为它没有(正确地)包括文本区域,选择,单选按钮和复选框:

$("#form input").each(function () {
    data[theFieldName] = theFieldValue;
});

当前回答

$('form').serialize() //this produces: "foo=1&bar=xxx&this=hi"

demo

其他回答

你们都不完全正确。你不能写:

formObj[input.name] = input.value;

因为这样,如果你有一个多选列表,它的值将被最后一个覆盖,因为它被传输为:"param1": "value1", "param1": "value2"。

所以,正确的方法是:

if (formData[input.name] === undefined) {
    formData[input.name] = input.value;
}
else {
    var inputFieldArray = $.merge([], $.isArray(formData[input.name]) ? formData[input.name] : [formData[input.name]]);
    $.merge(inputFieldArray, [input.value]);
    formData[input.name] = $.merge([], inputFieldArray);
}

基于jQuery。serializeArray,返回键值对。

var data = $('#form').serializeArray().reduce(function(obj, item) {
    obj[item.name] = item.value;
    return obj;
}, {});

这是我的香草JS版本(在Chrome上测试)

适用于:

name = "输入" Name ="form[Name]"(创建一个对象) Name ="checkbox[]"(创建一个数组对象) Name ="form[checkbox][]"(创建一个数组) Name ="form[select][Name]"(创建一个只包含所选值的对象)

/**
 * Get the values from a form
 * @param formId ( ID without the # )
 * @returns {object}
 */
function getFormValues( formId )
{
    let postData = {};
    let form = document.forms[formId];
    let formData = new FormData( form );

    for ( const value of formData.entries() )
    {
        let container = postData;
        let key = value[0];
        let arrayKeys = key.match( /\[[\w\-]*\]/g ); // Check for any arrays

        if ( arrayKeys !== null )
        {
            arrayKeys.unshift( key.substr( 0, key.search( /\[/ ) ) );  // prepend the first key to the list
            for ( let i = 0, count = arrayKeys.length, lastRun = count - 1; i < count; i++ )
            {
                let _key = arrayKeys[i];
                _key = _key.replace( "[", '' ).replace( "]", '' ); // Remove the brackets []
                if ( _key === '' )
                {
                    if ( ! Array.isArray( container ) )
                    {
                        container = [];
                    }

                    _key = container.length;
                }

                if ( ! (_key in container) ) // Create an object for the key if it doesn't exist
                {
                    if ( i !== lastRun && arrayKeys[i + 1] === '[]' )
                    {
                        container[_key] = [];
                    }
                    else
                    {
                        container[_key] = {};
                    }
                }

                if ( i !== lastRun ) // Until we're the last item, swap container with it's child
                {
                    container = container[_key];
                }

                key = _key;
            }
        }
        container[key] = value[1]; // finally assign the value
    }

    return postData;
}
$("#form input, #form select, #form textarea").each(function() {
 data[theFieldName] = theFieldValue;
});

除此之外,你可能想看看serialize();

$(form).serializeArray().reduce(function (obj, item) {
      if (obj[item.name]) {
           if ($.isArray(obj[item.name])) {
               obj[item.name].push(item.value);
           } else {
                var previousValue = obj[item.name];
                obj[item.name] = [previousValue, item.value];
           }
      } else {
           obj[item.name] = item.value;
      }

     return obj;
}, {});

它将修复问题:无法与多选择工作。