我有一个包含目录名的文件:
my_list.txt:
/tmp
/var/tmp
如果目录名已经存在于文件中,我想在添加目录名之前检入Bash。
我有一个包含目录名的文件:
my_list.txt:
/tmp
/var/tmp
如果目录名已经存在于文件中,我想在添加目录名之前检入Bash。
当前回答
由于某种原因,@Thomas的解决方案对我不起作用,但我有更长的字符串和特殊字符和空格,所以我只是像这样更改参数:
if grep -Fxq 'string you want to find' "/path/to/file"; then
echo "Found"
else
echo "Not found"
fi
希望它能帮助到别人
其他回答
if grep -q "$Filename$" my_list.txt
then
echo "exist"
else
echo "not exist"
fi
由于某种原因,@Thomas的解决方案对我不起作用,但我有更长的字符串和特殊字符和空格,所以我只是像这样更改参数:
if grep -Fxq 'string you want to find' "/path/to/file"; then
echo "Found"
else
echo "Not found"
fi
希望它能帮助到别人
关于以下解决方案:
grep -Fxq "$FILENAME" my_list.txt
如果你想知道(像我一样)-Fxq在通俗英语中是什么意思:
F:影响PATTERN的解释方式(固定字符串而不是正则表达式) x:匹配整行 问:嘘……最小的印刷
从男子档案中可以看出:
-F, --fixed-strings
Interpret PATTERN as a list of fixed strings, separated by newlines, any of which is to be matched.
(-F is specified by POSIX.)
-x, --line-regexp
Select only those matches that exactly match the whole line. (-x is specified by POSIX.)
-q, --quiet, --silent
Quiet; do not write anything to standard output. Exit immediately with zero status if any match is
found, even if an error was detected. Also see the -s or --no-messages option. (-q is specified by
POSIX.)
grep -Fxq "String to be found" | ls -a
Grep将帮助您检查内容 ls将列出所有的文件
与其他答案略有相似,但没有分叉,条目可以包含空格
contains() {
[[ " ${list[@]} " =~ " ${1} " ]] && echo 'contains' || echo 'does not contain'
}
IFS=$'\r\n' list=($(<my_list.txt))
对于my_list。txt
/tmp
/var/tmp
/Users/usr/dir with spaces
这些测试
contains '/tmp'
contains '/bin'
contains '/var/tmp'
contains '/Users/usr/dir with spaces'
contains 'dir with spaces'
返回
exists
does not exist
exists
exists
does not exist