我有一个有两列的数据帧。第一列包含类别,如“第一”,“第二”,“第三”,第二列有数字,表示我从“类别”中看到特定组的次数。

例如:

Category     Frequency
First        10
First        15
First        5
Second       2
Third        14
Third        20
Second       3

我想按类别对数据进行排序,并将所有频率相加:

Category     Frequency
First        30
Second       5
Third        34

在R中怎么做呢?


当前回答

几年后,只是为了添加另一个简单的基本R解决方案,由于某种原因这里没有给出——xtabs

xtabs(Frequency ~ Category, df)
# Category
# First Second  Third 
#    30      5     34 

或者你想要回数据帧

as.data.frame(xtabs(Frequency ~ Category, df))
#   Category Freq
# 1    First   30
# 2   Second    5
# 3    Third   34

其他回答

你可以用函数群。sum来自包Rfast。

Category <- Rfast::as_integer(Category,result.sort=FALSE) # convert character to numeric. R's as.numeric produce NAs.
result <- Rfast::group.sum(Frequency,Category)
names(result) <- Rfast::Sort(unique(Category)
# 30 5 34

Rfast有许多组函数和组。和就是其中之一。

使用聚合:

aggregate(x$Frequency, by=list(Category=x$Category), FUN=sum)
  Category  x
1    First 30
2   Second  5
3    Third 34

在上面的例子中,可以在列表中指定多个维度。相同数据类型的多个聚合指标可以通过cbind合并:

aggregate(cbind(x$Frequency, x$Metric2, x$Metric3) ...

(嵌入@thelatemail评论),聚合也有一个公式界面

aggregate(Frequency ~ Category, x, sum)

或者,如果希望聚合多个列,可以使用。符号(也适用于一列)

aggregate(. ~ Category, x, sum)

或tapply:

tapply(x$Frequency, x$Category, FUN=sum)
 First Second  Third 
    30      5     34 

使用这些数据:

x <- data.frame(Category=factor(c("First", "First", "First", "Second",
                                      "Third", "Third", "Second")), 
                    Frequency=c(10,15,5,2,14,20,3))

从dplyr 1.0.0开始,可以使用across()函数:

df %>%
 group_by(Category) %>%
 summarise(across(Frequency, sum))

  Category Frequency
  <chr>        <int>
1 First           30
2 Second           5
3 Third           34

如果对多个变量感兴趣:

df %>%
 group_by(Category) %>%
 summarise(across(c(Frequency, Frequency2), sum))

  Category Frequency Frequency2
  <chr>        <int>      <int>
1 First           30         55
2 Second           5         29
3 Third           34        190

以及使用select helper来选择变量:

df %>%
 group_by(Category) %>%
 summarise(across(starts_with("Freq"), sum))

  Category Frequency Frequency2 Frequency3
  <chr>        <int>      <int>      <dbl>
1 First           30         55        110
2 Second           5         29         58
3 Third           34        190        380

样本数据:

df <- read.table(text = "Category Frequency Frequency2 Frequency3
                 1    First        10         10         20
                 2    First        15         30         60
                 3    First         5         15         30
                 4   Second         2          8         16
                 5    Third        14         70        140
                 6    Third        20        120        240
                 7   Second         3         21         42",
                 header = TRUE,
                 stringsAsFactors = FALSE)
library(tidyverse)

x <- data.frame(Category= c('First', 'First', 'First', 'Second', 'Third', 'Third', 'Second'), 
           Frequency = c(10, 15, 5, 2, 14, 20, 3))

count(x, Category, wt = Frequency)

另一种解决方案是在矩阵或数据帧中按组返回和,并且简短快速:

rowsum(x$Frequency, x$Category)