相反，你会收到回调onRequestPermissionsResult()作为PERMISSION_DENIED当你再次请求权限时，而落在shouldShowRequestPermissionRationale()的错误条件下

来自Android文档:

When the system asks the user to grant a permission, the user has the option of telling the system not to ask for that permission again. In that case, any time an app uses requestPermissions() to ask for that permission again, the system immediately denies the request. The system calls your onRequestPermissionsResult() callback method and passes PERMISSION_DENIED, the same way it would if the user had explicitly rejected your request again. This means that when you call requestPermissions(), you cannot assume that any direct interaction with the user has taken place.

开发者预览2对应用程序请求权限的方式进行了一些更改(参见http://developer.android.com/preview/support.html#preview2-notes)。

第一个对话框现在看起来像这样:

没有“永不再次显示”复选框(不像开发人员预览1)。如果用户拒绝权限，如果权限是必不可少的应用程序，它可以显示另一个对话框来解释应用程序请求该权限的原因，例如:

如果用户再次拒绝，应用程序应该关闭(如果它绝对需要该权限)或继续运行有限的功能。如果用户重新考虑(并选择重试)，则再次请求权限。这次的提示符是这样的:

第二次显示“永不再问”复选框。如果用户再次拒绝并且勾选复选框，就不会再发生任何事情。 是否勾选复选框可以通过使用Activity.shouldShowRequestPermissionRationale(String)来确定，例如:

if (shouldShowRequestPermissionRationale(Manifest.permission.WRITE_CONTACTS)) {...

这就是Android文档所说的(https://developer.android.com/training/permissions/requesting.html):

To help find the situations where you need to provide extra explanation, the system provides the Activity.shouldShowRequestPermissionRationale(String) method. This method returns true if the app has requested this permission previously and the user denied the request. That indicates that you should probably explain to the user why you need the permission. If the user turned down the permission request in the past and chose the Don't ask again option in the permission request system dialog, this method returns false. The method also returns false if the device policy prohibits the app from having that permission.

要知道用户是否拒绝了“never ask again”，你可以再次检查你的onRequestPermissionsResult中的shouldShowRequestPermissionRationale方法，当用户没有授予权限时。

@Override
public void onRequestPermissionsResult(int requestCode, String[] permissions, int[] grantResults) {
    if (requestCode == REQUEST_PERMISSION) {
        // for each permission check if the user granted/denied them
        // you may want to group the rationale in a single dialog,
        // this is just an example
        for (int i = 0, len = permissions.length; i < len; i++) {
            String permission = permissions[i];
            if (grantResults[i] == PackageManager.PERMISSION_DENIED) {
            // user rejected the permission
                boolean showRationale = shouldShowRequestPermissionRationale( permission );
                if (! showRationale) {
                    // user also CHECKED "never ask again"
                    // you can either enable some fall back,
                    // disable features of your app
                    // or open another dialog explaining
                    // again the permission and directing to
                    // the app setting
                } else if (Manifest.permission.WRITE_CONTACTS.equals(permission)) {
                    showRationale(permission, R.string.permission_denied_contacts);
                    // user did NOT check "never ask again"
                    // this is a good place to explain the user
                    // why you need the permission and ask if he wants
                    // to accept it (the rationale)
                } else if ( /* possibly check more permissions...*/ ) {
                }
            }
        }
    }
}

你可以用下面的代码打开你的应用程序设置:

Intent intent = new Intent(Settings.ACTION_APPLICATION_DETAILS_SETTINGS);
Uri uri = Uri.fromParts("package", getPackageName(), null);
intent.setData(uri);
startActivityForResult(intent, REQUEST_PERMISSION_SETTING);

无法将用户直接发送到授权页面。

我还想知道用户是否选择了“never ask again”。我已经实现了一个“几乎解决方案”与一个丑陋的旗帜，但在我告诉你如何，我将告诉你我的动机:

I would like to offer the permission referring functionality initially. If the user uses it and has no rights, he/she gets the either the 1th dialog from above or both the 2nd and 3rd. When the user has chosen 'Never ask again' I would like to disable the functionality and to display it differently. - My action is triggered by a spinner text entry, I would also like to add '(Permission revoked)' to the label text displayed. This shows to the user: 'There is functionality but I cannot use it, due to my permission settings.' However, this does not seem to be possible, as I cannot check whether or not 'Never ask again' has been chosen.

I came to a solution I can live with by having my functionality always enabled with an active permission check. I am showing a Toast message in onRequestPermissionsResult() in case of a negative response but only if I have not shown my custom rationale popup. So if the user has chosen 'Never ask again' he gets a toast message only. If the user is reluctant to chose 'never ask again' he gets only the custom rationale and the permission request popup by the operation system but not toast, as three notifications in a row would be too much pain.

在阅读了一些答案后，我发现了许多冗长而令人困惑的答案 我的结论是

if (!ActivityCompat.shouldShowRequestPermissionRationale(this,Manifest.permission.READ_EXTERNAL_STORAGE))
                Toast.makeText(this, "permanently denied", Toast.LENGTH_SHORT).show();

你可以听漂亮。

侦听器

interface PermissionListener {
    fun onNeedPermission()
    fun onPermissionPreviouslyDenied(numberDenyPermission: Int)
    fun onPermissionDisabledPermanently(numberDenyPermission: Int)
    fun onPermissionGranted()
}

MainClass的权限

class PermissionUtil {

    private val PREFS_FILENAME = "permission"
    private val TAG = "PermissionUtil"

    private fun shouldAskPermission(context: Context, permission: String): Boolean {
        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
            val permissionResult = ActivityCompat.checkSelfPermission(context, permission)
            if (permissionResult != PackageManager.PERMISSION_GRANTED) {
                return true
            }
        }
        return false
    }

    fun checkPermission(context: Context, permission: String, listener: PermissionListener) {

        Log.i(TAG, "CheckPermission for $permission")

        if (shouldAskPermission(context, permission)) {

            // Load history permission
            val sharedPreference = context.getSharedPreferences(PREFS_FILENAME, 0)
            val numberShowPermissionDialog = sharedPreference.getInt(permission, 0)

            if (numberShowPermissionDialog == 0) {

                (context as? Activity)?.let {
                    if (ActivityCompat.shouldShowRequestPermissionRationale(it, permission)) {
                        Log.e(TAG, "User has denied permission but not permanently")
                        listener.onPermissionPreviouslyDenied(numberShowPermissionDialog)
                    } else {
                        Log.e(TAG, "Permission denied permanently.")
                        listener.onPermissionDisabledPermanently(numberShowPermissionDialog)
                    }
                } ?: kotlin.run {
                    listener.onNeedPermission()
                }

            } else {
                // Is FirstTime
                listener.onNeedPermission()
            }


            // Save history permission
            sharedPreference.edit().putInt(permission, numberShowPermissionDialog + 1).apply()


        } else {
            listener.onPermissionGranted()
        }

    }
}

以这种方式使用

      PermissionUtil().checkPermission(this, Manifest.permission.ACCESS_FINE_LOCATION,
                object : PermissionListener {
                    override fun onNeedPermission() {
                        log("---------------------->onNeedPermission")

//                            ActivityCompat.requestPermissions(this@SplashActivity,
//                                    Array(1) { Manifest.permission.ACCESS_FINE_LOCATION },
//                                    118)

                    }

                    override fun onPermissionPreviouslyDenied(numberDenyPermission: Int) {
                        log("---------------------->onPermissionPreviouslyDenied")
                    }

                    override fun onPermissionDisabledPermanently(numberDenyPermission: Int) {
                        log("---------------------->onPermissionDisabled")
                    }

                    override fun onPermissionGranted() {
                        log("---------------------->onPermissionGranted")
                    }

                })

在activity或fragmnet中覆盖onRequestPermissionsResult

override fun onRequestPermissionsResult(requestCode: Int, permissions: Array<out String>, grantResults: IntArray) {
 if (requestCode == 118) {
        if (permissions[0] == Manifest.permission.ACCESS_FINE_LOCATION && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
            getLastLocationInMap()
        }
        }
    }

一旦用户标记了“不要再问”，该问题就不能再次显示。 但是可以向用户解释，他之前拒绝了权限，必须在设置中授予权限。并参考他的设置，使用以下代码:

@Override
public void onRequestPermissionsResult(int permsRequestCode, String[] permissions, int[] grantResults) {

    if (grantResults.length > 0
            && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
        // now, you have permission go ahead
        // TODO: something

    } else {

        if (ActivityCompat.shouldShowRequestPermissionRationale(MainActivity.this,
                Manifest.permission.READ_CALL_LOG)) {
            // now, user has denied permission (but not permanently!)

        } else {

            // now, user has denied permission permanently!

            Snackbar snackbar = Snackbar.make(findViewById(android.R.id.content), "You have previously declined this permission.\n" +
                "You must approve this permission in \"Permissions\" in the app settings on your device.", Snackbar.LENGTH_LONG).setAction("Settings", new View.OnClickListener() {
            @Override
            public void onClick(View view) {

                startActivity(new Intent(android.provider.Settings.ACTION_APPLICATION_DETAILS_SETTINGS, Uri.parse("package:" + BuildConfig.APPLICATION_ID)));

            }
        });
        View snackbarView = snackbar.getView();
        TextView textView = (TextView) snackbarView.findViewById(android.support.design.R.id.snackbar_text);
        textView.setMaxLines(5);  //Or as much as you need
        snackbar.show();

        }

    }
    return;
}