你可以让它跳转到相同的页面而不指定url:

window.open('?','_self');

   Just Try in button.

   <button onclick="location.reload();location.href='url_name'" 
   id="myButton" class="btn request-callback" >Explore More</button>

   Using href 

  <a href="#" class="know_how" onclick="location.reload();location.href='url_name'">Know More</a> 

用这个:

location.href = "http://example.com";

使用_self打开当前标签页中的url

const autoOpenAlink = (url = ' ') => { 窗口。打开(url，“在同一个标签页中打开测试页面”); ｝ <一个 href = " https://cdn.xgqfrms.xyz/index.html " 目标= " _self” onclick = " autoOpenAlink(“https://cdn.xgqfrms.xyz/index.html”)" > 在当前标签页中使用' _self '打开url < / >

在新标签页中使用_blank打开url

const autoOpenAlink = (url = ``) => { window.open(url, "open testing page in a new tab page"); } // ❌ The error is caused by a `StackOverflow` limitation // js:18 Blocked opening 'https://cdn.xgqfrms.xyz/index.html' in a new window because the request was made in a sandboxed frame whose 'allow-popups' permission is not set. <a href="https://cdn.xgqfrms.xyz/index.html" target="_blank" onclick="autoOpenAlink('https://cdn.xgqfrms.xyz/index.html')"> open url in a new tab page using `_blank` </a>

refs

根据MDN的文档，你只需要给新窗口/标签一个名字。

https://developer.mozilla.org/en-US/docs/Web/API/Window/open#Syntax

你可以让它跳转到相同的页面而不指定url:

window.open('?','_self');

在html 5中，你可以使用历史API。

history.pushState({
  prevUrl: window.location.href

}, 'Next page', 'http://localhost/x/next_page');
history.go();

然后在下一页中，您可以像这样访问状态对象

let url = history.state.prevUrl;
if (url) {
  console.log('user come from: '+ url)
}