使用_self打开当前标签页中的url

const autoOpenAlink = (url = ' ') => { 窗口。打开(url，“在同一个标签页中打开测试页面”); ｝ <一个 href = " https://cdn.xgqfrms.xyz/index.html " 目标= " _self” onclick = " autoOpenAlink(“https://cdn.xgqfrms.xyz/index.html”)" > 在当前标签页中使用' _self '打开url < / >

在新标签页中使用_blank打开url

const autoOpenAlink = (url = ``) => { window.open(url, "open testing page in a new tab page"); } // ❌ The error is caused by a `StackOverflow` limitation // js:18 Blocked opening 'https://cdn.xgqfrms.xyz/index.html' in a new window because the request was made in a sandboxed frame whose 'allow-popups' permission is not set. <a href="https://cdn.xgqfrms.xyz/index.html" target="_blank" onclick="autoOpenAlink('https://cdn.xgqfrms.xyz/index.html')"> open url in a new tab page using `_blank` </a>

refs

根据MDN的文档，你只需要给新窗口/标签一个名字。

https://developer.mozilla.org/en-US/docs/Web/API/Window/open#Syntax

为了确保链接在同一个选项卡中打开，您应该使用window.location.replace()

请看下面的例子:

window.location.replace("http://www.w3schools.com");

来源:http://www.w3schools.com/jsref/met_loc_replace.asp

你一定要用window.open吗?如果使用window.location="http://example.com"呢?

在html 5中，你可以使用历史API。

history.pushState({
  prevUrl: window.location.href

}, 'Next page', 'http://localhost/x/next_page');
history.go();

然后在下一页中，您可以像这样访问状态对象

let url = history.state.prevUrl;
if (url) {
  console.log('user come from: '+ url)
}

像点击链接一样打开另一个url

window.location.href = "http://example.com";

窗口。Open (url, wndname, params)，它有三个参数。如果你不希望它在同一个窗口中打开，只需要设置一个不同的wndname。例如:

window.open(url1, "name1", params); // this open one window or tab
window.open(url1, "name2", params); // though url is same, but it'll open in another window(tab).

下面是关于window.open()的详细信息，你可以信任它! https://developer.mozilla.org/en/DOM/window.open

试试吧~~