我正在使用一些包含字符串的XML:

<node>This is a string</node>

我传递给节点的一些字符串将有&,#,$等字符:

<node>This is a string & so is this</node>

由于&,这是无效的。

我不能在CDATA中包装这些字符串,因为它们需要这样。我尝试寻找一个字符列表,这些字符不能放在XML节点中,而不能放在CDATA中。

有人能给我指个方向或者给我一份非法字符的列表吗?


当前回答

“XmlWriter和低ASCII字符”对我很有用

string code = Regex.Replace(item.Code, @"[\u0000-\u0008,\u000B,\u000C,\u000E-\u001F]", "");

其他回答

综上所述,文本中的有效字符为:

制表符,换行和换行。 除&和<外,所有非控制字符都有效。 如果使用]],则>无效。

XML规范的2.2节和2.4节详细给出了答案:

字符

合法字符包括制表符、回车符、换行符以及Unicode和ISO/IEC 10646的合法字符

字符数据

The ampersand character (&) and the left angle bracket (<) must not appear in their literal form, except when used as markup delimiters, or within a comment, a processing instruction, or a CDATA section. If they are needed elsewhere, they must be escaped using either numeric character references or the strings " & " and " < " respectively. The right angle bracket (>) may be represented using the string " > ", and must, for compatibility, be escaped using either " > " or a character reference when it appears in the string " ]]> " in content, when that string is not marking the end of a CDATA section.

对于Java人来说,Apache有一个实用程序类(StringEscapeUtils),它有一个帮助方法escapeXml,可以用来使用XML实体转义字符串中的字符。

唯一的非法字符是&,<和>(以及属性中的"或',这取决于使用哪个字符来分隔属性值:attr="必须使用"这里,' is allowed '和attr='必须使用&apos;在这里,“is allowed”)。

它们是用XML实体转义的,这里你需要&&。

实际上,您应该使用一个工具或库来为您编写XML,并为您抽象这类东西,这样您就不必担心了。

“XmlWriter和低ASCII字符”对我很有用

string code = Regex.Replace(item.Code, @"[\u0000-\u0008,\u000B,\u000C,\u000E-\u001F]", "");

在Woodstox XML处理器中,无效字符由以下代码分类:

if (c == 0) {
    throw new IOException("Invalid null character in text to output");
}
if (c < ' ' || (c >= 0x7F && c <= 0x9F)) {
    String msg = "Invalid white space character (0x" + Integer.toHexString(c) + ") in text to output";
    if (mXml11) {
        msg += " (can only be output using character entity)";
    }
    throw new IOException(msg);
}
if (c > 0x10FFFF) {
    throw new IOException("Illegal unicode character point (0x" + Integer.toHexString(c) + ") to output; max is 0x10FFFF as per RFC");
}
/*
 * Surrogate pair in non-quotable (not text or attribute value) content, and non-unicode encoding (ISO-8859-x,
 * Ascii)?
 */
if (c >= SURR1_FIRST && c <= SURR2_LAST) {
    throw new IOException("Illegal surrogate pair -- can only be output via character entities, which are not allowed in this content");
}
throw new IOException("Invalid XML character (0x"+Integer.toHexString(c)+") in text to output");

来自这里