我需要测试一个在浏览器中打开一个新选项卡的功能

openStatementsReport(contactIds) {
  window.open(`a_url_${contactIds}`);
}

我想模拟窗口的打开函数,这样我就可以验证正确的URL被传递给打开函数。

使用笑话,我不知道如何模拟窗口。我试着设置窗口。使用mock函数打开,但这种方式不起作用。下面是测试用例:

it('the correct URL is called', () => {
  window.open = jest.fn();
  statementService.openStatementsReport(111);
  expect(window.open).toBeCalled();
});

但是它给出了误差

expect(jest.fn())[.not].toBeCalled()

jest.fn() value must be a mock function or spy.
    Received:
      function: [Function anonymous]

我应该对测试用例做什么?


当前回答

我们也可以在setupTests中使用global来定义它:

// File 'setupTests.js'
global.open = jest.fn()

并在实际测试中使用global调用它:

// File 'yourtest.test.js'
it('the correct URL is called', () => {
    statementService.openStatementsReport(111);
    expect(global.open).toBeCalled();
});

其他回答

我们也可以在setupTests中使用global来定义它:

// File 'setupTests.js'
global.open = jest.fn()

并在实际测试中使用global调用它:

// File 'yourtest.test.js'
it('the correct URL is called', () => {
    statementService.openStatementsReport(111);
    expect(global.open).toBeCalled();
});

你可以试试这个:

import * as _Window from "jsdom/lib/jsdom/browser/Window";

window.open = jest.fn().mockImplementationOnce(() => {
    return new _Window({ parsingMode: "html" });
});

it("correct url is called", () => {
    statementService.openStatementsReport(111);
    expect(window.open).toHaveBeenCalled();
});

试一试:

let windowOpenSpy: jest.SpyInstance;
beforeEach(() => {
    windowOpenSpy = jest.spyOn(window, 'open');
});

it('should open window with dashboard url', () => {
    expect(windowOpenSpy).toBeCalledWith('your URL', '_blank');
});
const windowSpy = jest.spyOn(iFrame, "contentWindow", "get");
windowSpy.mockImplementation(() => ({
  location: {
    origin: "https://test.com",
    href: "href",
    hash: "hash"
  }
}));

在Jest配置中,添加setupFilesAfterEnv: ["./setupTests.js"],创建该文件,并添加您想要在测试之前运行的代码:

// setupTests.js
window.crypto = {
   .....
};

参考:setupFilesAfterEnv [array]