我想它叫next。

next

另外，看看重做当前迭代的redo。

用一种更地道的方式来写伊恩·伯顿的回答:

(1..5).each do |x|
  next if x < 2
  puts x
end

打印:

  2
  3
  4
  5

使用next，它将绕过该条件，其余代码将正常工作。 下面我提供了完整的脚本和输出

class TestBreak
  puts " Enter the nmber"
  no= gets.to_i
  for i in 1..no
    if(i==5)
      next
    else 
      puts i
    end
  end
end

obj=TestBreak.new()

输出: 输入号码 10

1 2 3 4 6 7 8 9 10

是的，它叫next。

for i in 0..5
   if i < 2
     next
   end
   puts "Value of local variable is #{i}"
end

输出如下:

Value of local variable is 2
Value of local variable is 3
Value of local variable is 4
Value of local variable is 5
 => 0..5 

使用可以有条件地使用下一个

before = 0
"0;1;2;3".split(";").each.with_index do |now, i|
    next if i < 1
    puts "before it was #{before}, now it is #{now}"
    before = now
end

输出:

before it was 0, now it is 1
before it was 1, now it is 2
before it was 2, now it is 3