我正在从事的项目(Node.js)意味着对文件系统的大量操作(复制、读取、写入等)。

哪种方法是最快的?


当前回答

使用标准的内置方式fs.copyFile:

const fs = require('fs');

// File destination.txt will be created or overwritten by default.
fs.copyFile('source.txt', 'destination.txt', (err) => {
  if (err) throw err;
  console.log('source.txt was copied to destination.txt');
});

如果你必须支持老版本的Node.js -下面是你如何在不支持fs.copyFile的版本中做到这一点:

const fs = require('fs');
fs.createReadStream('test.log').pipe(fs.createWriteStream('newLog.log'));

其他回答

使用标准的内置方式fs.copyFile:

const fs = require('fs');

// File destination.txt will be created or overwritten by default.
fs.copyFile('source.txt', 'destination.txt', (err) => {
  if (err) throw err;
  console.log('source.txt was copied to destination.txt');
});

如果你必须支持老版本的Node.js -下面是你如何在不支持fs.copyFile的版本中做到这一点:

const fs = require('fs');
fs.createReadStream('test.log').pipe(fs.createWriteStream('newLog.log'));
   const fs = require("fs");
   fs.copyFileSync("filepath1", "filepath2"); //fs.copyFileSync("file1.txt", "file2.txt");

这是我个人用来复制一个文件和替换另一个文件使用Node.js:)

相同的机制,但这增加了错误处理:

function copyFile(source, target, cb) {
  var cbCalled = false;

  var rd = fs.createReadStream(source);
  rd.on("error", function(err) {
    done(err);
  });
  var wr = fs.createWriteStream(target);
  wr.on("error", function(err) {
    done(err);
  });
  wr.on("close", function(ex) {
    done();
  });
  rd.pipe(wr);

  function done(err) {
    if (!cbCalled) {
      cb(err);
      cbCalled = true;
    }
  }
}

通常避免异步文件操作是很好的。以下是一个简短的(即没有错误处理)同步示例:

var fs = require('fs');
fs.writeFileSync(targetFile, fs.readFileSync(sourceFile));

迈克的解决方案,但承诺:

const FileSystem = require('fs');

exports.copyFile = function copyFile(source, target) {
    return new Promise((resolve,reject) => {
        const rd = FileSystem.createReadStream(source);
        rd.on('error', err => reject(err));
        const wr = FileSystem.createWriteStream(target);
        wr.on('error', err => reject(err));
        wr.on('close', () => resolve());
        rd.pipe(wr);
    });
};