我在寻找一个广义解。
考虑具有相同名称的2个无线电类型输入。当提交时，被选中的值决定随表单一起发送的值:
<input type="radio" name="myRadios" onchange="handleChange1();" value="1" />
<input type="radio" name="myRadios" onchange="handleChange2();" value="2" />
取消选择单选按钮时，更改事件不会触发。因此，如果值="1"的无线电已经被选中，而用户选择了第二个，则handleChange1()不会运行。这就出现了一个问题(至少对我来说)，因为我无法捕捉到这种去选择。
我想要的是一个变通的onChange事件的复选框组值，或者，一个onCheck事件，不仅检测单选按钮是选中的，而且当它是未选中的。
我相信你们中的一些人以前遇到过这个问题。有什么变通办法(或者理想情况下，什么是处理这个问题的正确方法)?我只是想捕捉变化事件，访问以前检查的收音机以及新检查的收音机。
注:
onClick似乎是一个更好的(跨浏览器的)事件来指示选中单选按钮，但它仍然不能解决未选中的问题。
我认为这是有意义的，为什么onChange复选框类型在这样的情况下工作，因为它改变了它提交的值，当你勾选或取消勾选它。我希望单选按钮表现得更像一个SELECT元素的onChange，但你能做什么…
将之前选中的radio存储在一个变量中:
http://jsfiddle.net/dsbonev/C5S4B/
HTML
<input type="radio" name="myRadios" value="1" /> 1
<input type="radio" name="myRadios" value="2" /> 2
<input type="radio" name="myRadios" value="3" /> 3
<input type="radio" name="myRadios" value="4" /> 4
<input type="radio" name="myRadios" value="5" /> 5
JS
var changeHandler = (function initChangeHandler() {
var previousCheckedRadio = null;
var result = function (event) {
var currentCheckedRadio = event.target;
var name = currentCheckedRadio.name;
if (name !== 'myRadios') return;
//using radio elements previousCheckedRadio and currentCheckedRadio
//storing radio element for using in future 'change' event handler
previousCheckedRadio = currentCheckedRadio;
};
return result;
})();
document.addEventListener('change', changeHandler, false);
Js示例代码
var changeHandler = (function initChangeHandler() {
var previousCheckedRadio = null;
function logInfo(info) {
if (!console || !console.log) return;
console.log(info);
}
function logPrevious(element) {
if (!element) return;
var message = element.value + ' was unchecked';
logInfo(message);
}
function logCurrent(element) {
if (!element) return;
var message = element.value + ' is checked';
logInfo(message);
}
var result = function (event) {
var currentCheckedRadio = event.target;
var name = currentCheckedRadio.name;
if (name !== 'myRadios') return;
logPrevious(previousCheckedRadio);
logCurrent(currentCheckedRadio);
previousCheckedRadio = currentCheckedRadio;
};
return result;
})();
document.addEventListener('change', changeHandler, false);
出于某种原因，最好的答案对我来说并不适用。
我通过实践改进了最佳答案
var overlayType_radio = document.querySelectorAll('input[type=radio][name="radio_overlaytype"]');
原最佳答案用法:
var rad = document.myForm.myRadios;
其他人保持不变，最后对我有用。
var overlayType_radio = document.querySelectorAll('input[type=radio][name="radio_overlaytype"]');
console.log('overlayType_radio', overlayType_radio)
var prev = null;
for (var i = 0; i < overlayType_radio.length; i++) {
overlayType_radio[i].addEventListener('change', function() {
(prev) ? console.log('radio prev value',prev.value): null;
if (this !== prev) {
prev = this;
}
console.log('radio now value ', this.value)
});
}
html是:
<div id='overlay-div'>
<fieldset>
<legend> Overlay Type </legend>
<p>
<label>
<input class='with-gap' id='overlayType_image' value='overlayType_image' name='radio_overlaytype' type='radio' checked/>
<span>Image</span>
</label>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_tiled_image' value='overlayType_tiled_image' name='radio_overlaytype' type='radio' disabled/>
<span> Tiled Image</span>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_coordinated_tile' value='overlayType_coordinated_tile' name='radio_overlaytype' type='radio' disabled/>
<span> Coordinated Tile</span>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_none' value='overlayType_none' name='radio_overlaytype' type='radio'/>
<span> None </span>
</p>
</fieldset>
</div>
var overlayType_radio = document.querySelectorAll('input[type=radio][name="radio_overlaytype"]');
console.log('overlayType_radio', overlayType_radio)
var prev = null;
for (var i = 0; i < overlayType_radio.length; i++) {
overlayType_radio[i].addEventListener('change', function() {
(prev) ? console.log('radio prev value',prev.value): null;
if (this !== prev) {
prev = this;
}
console.log('radio now value ', this.value)
});
}
<div id='overlay-div'>
<fieldset>
<legend> Overlay Type </legend>
<p>
<label>
<input class='with-gap' id='overlayType_image' value='overlayType_image' name='radio_overlaytype' type='radio' checked/>
<span>Image</span>
</label>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_tiled_image' value='overlayType_tiled_image' name='radio_overlaytype' type='radio' />
<span> Tiled Image</span>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_coordinated_tile' value='overlayType_coordinated_tile' name='radio_overlaytype' type='radio' />
<span> Coordinated Tile</span>
</p>
<p>
<label>
<input class='with-gap' id='overlayType_none' value='overlayType_none' name='radio_overlaytype' type='radio'/>
<span> None </span>
</p>
</fieldset>
</div>
点击这里
https://jsfiddle.net/hoogw/jetmkn02/1/
博士Tl;
'focusout'在'change'事件之前被分派-示例:
const radioName = 'radio';
// Add radios
document.body.innerHTML = `
<style>
input + label {
margin-left: 1rem;
}
</style>
<form action="#" name="example-form">
<fieldset>
${Array(5).fill(null, 0, 5).map((_, i) => {
const offsetId = i + 1;
const id = `radio-${offsetId}`;
return `<label for="${id}">Radio ${offsetId}</label>
<input type="radio" name="${radioName}" id="${id}" value="${offsetId}" />`;
}).join('\n')}
</fieldset>
</form>
`;
const {log} = console,
form = document.forms['example-form'];
form.addEventListener('submit', e => e.preventDefault());
form.addEventListener('change', e => {
const {target} = e;
if (target.matches(`[type="radio"][name="${radioName}"]`)) {
log(`[${e.type}]: "${target.id}" selected; Value: ${target.value}`);
}
});
form.addEventListener('focusout', e => {
const {target} = e,
soonToBePrevValue = target && target.form ?
target.form.elements[radioName].value : null;
if (!target.matches(`[type="radio"][name="${radioName}"]`) || !soonToBePrevValue) {
return;
}
// value, for '[name="radio"]', contained in form, will change after 'focusout' event
// has completed it's bubbling stage.
log(`[${e.type}]: previously selected radio value: ` +
`${soonToBePrevValue}`);
// log("Soon to be \"previous\" radio: ", target);
});
斯菲德尔
