单选按钮(INPUT type="radio")的OnChange事件处理程序不能作为一个值工作

出于某种原因，最好的答案对我来说并不适用。

我通过实践改进了最佳答案

    var overlayType_radio = document.querySelectorAll('input[type=radio][name="radio_overlaytype"]');

原最佳答案用法:

      var rad = document.myForm.myRadios;

其他人保持不变，最后对我有用。

var overlayType_radio = document.querySelectorAll('input[type=radio][name="radio_overlaytype"]');
                              console.log('overlayType_radio', overlayType_radio)

                              var prev = null;
                              for (var i = 0; i < overlayType_radio.length; i++) {
                                  overlayType_radio[i].addEventListener('change', function() {
                                      (prev) ? console.log('radio prev value',prev.value): null;
                                      if (this !== prev) {
                                          prev = this;
                                      }
                                      console.log('radio now value ', this.value)
                                  });
                              }

html是:

<div id='overlay-div'>
                        <fieldset>
                                <legend> Overlay Type </legend>
                                
                                <p>
                                    <label>
                                      <input class='with-gap' id='overlayType_image' value='overlayType_image' name='radio_overlaytype' type='radio' checked/>
                                      <span>Image</span> 
                                    </label>
                                </p>

                                <p>
                                  <label>
                                    <input class='with-gap' id='overlayType_tiled_image' value='overlayType_tiled_image' name='radio_overlaytype' type='radio' disabled/>
                                    <span> Tiled Image</span>   
                                </p>

                                <p>
                                  <label>
                                    <input class='with-gap' id='overlayType_coordinated_tile' value='overlayType_coordinated_tile' name='radio_overlaytype' type='radio'  disabled/>
                                    <span> Coordinated Tile</span>  
                                </p>

                                <p>
                                  <label>
                                    <input class='with-gap' id='overlayType_none' value='overlayType_none' name='radio_overlaytype' type='radio'/>
                                    <span> None </span>            
                                  </p>

                                  
                          </fieldset>
                       </div>

点击这里

https://jsfiddle.net/hoogw/jetmkn02/1/

2020-10-15 17:23:20

这对我很有用

<input ID="TIPO_INST-0" Name="TIPO_INST" Type="Radio" value="UNAM" onchange="convenio_unam();">UNAM

<script type="text/javascript">
            function convenio_unam(){
                if(this.document.getElementById('TIPO_INST-0').checked){
                    $("#convenio_unam").hide();
                }else{
                    $("#convenio_unam").show(); 
                }                               
            }
</script>

2018-10-26 23:50:51

Yes there is no change event for currently selected radio button. But problem is when each radio button is taken as a separate element. Instead a radio group should be considered a single element like select. So change event is triggered for that group. If it is a select element we never worry about each option in it, but take only the selected option. We store the current value in a variable which will become the previous value, when a new option is selected. Similarly you have to use a separate variable for storing value of checked radio button.

如果您想要识别前一个单选按钮，则必须循环鼠标按下事件。

var radios = document.getElementsByName("myRadios");
var val;
for(var i = 0; i < radios.length; i++){
    if(radios[i].checked){
        val = radios[i].value;
    }
}

请看这个:http://jsfiddle.net/diode/tywx6/2/

2012-01-12 17:43:02

这是最简单和最有效的函数，只需添加尽可能多的按钮到checked = false，并使每个单选按钮的onclick事件调用此函数。为每个收音机指定一个唯一的号码按钮

function AdjustRadios(which) 
{
    if(which==1)
         document.getElementById("rdpPrivate").checked=false;
    else if(which==2)
         document.getElementById("rdbPublic").checked=false;
}

2015-12-03 01:54:54