如果你使用Kotlin，你可以像这样使用属性委托viewModels():

val viewModel: YourViewModel by viewModels()

来源:https://forums.bignerdranch.com/t/solution-to-deprecated-method-viewmodelproviders-of/16833

进口

弃用:

import androidx.lifecycle.ViewModelProviders;

To:

import androidx.lifecycle.ViewModelProvider;

使用

弃用:

ViewModelProviders.of(this, provider).get(VM::class.java)

To:

ViewModelProvider(this, provider).get(VM::class.java)

我使用生命周期扩展2.2.0版本:

implementation "androidx.lifecycle:lifecycle-extensions:2.2.0" 

它应该工作，使用ViewModelProvider构造函数。

// With ViewModelFactory   
val viewModel = ViewModelProvider(this, YourViewModelFactory).get(YourViewModel::class.java)


//Without ViewModelFactory
val viewModel = ViewModelProvider(this).get(YourViewModel::class.java)

2020/5/15更新

我发现了另一种优雅的方式来实现这一点，Android KTX可以帮助

implementation "androidx.fragment:fragment-ktx:1.2.4"
val viewmodel: MYViewModel by viewModels()
val viewmodel: MYViewModel by viewModels { myFactory } //With factory

裁判:https://developer.android.com/reference/kotlin/androidx/fragment/app/package-summary #视图模型

2020/06/25:修正了委托的大小写

当你使用dagger时，你将在构造函数中传递factory

  MobileViewModel mobileViewModel = new ViewModelProvider(this,providerFactory).get(MobileViewModel.class);

是的@Tarek，已经被弃用了。现在使用AndroidX:

val yourViewModel = ViewModelProvider.NewInstanceFactory().create(YourVideoModel::class.java)

如果你有这个实现

'implementation 'androidx.lifecycle:lifecycle-extensions:2.2.0'

试着使用 viewModel = MainViewModel()