虽然我从来都不需要这样做,但我突然意识到用Python创建一个不可变对象可能有点棘手。你不能只是覆盖__setattr__,因为这样你甚至不能在__init__中设置属性。子类化一个元组是一个有效的技巧:

class Immutable(tuple):
    
    def __new__(cls, a, b):
        return tuple.__new__(cls, (a, b))

    @property
    def a(self):
        return self[0]
        
    @property
    def b(self):
        return self[1]

    def __str__(self):
        return "<Immutable {0}, {1}>".format(self.a, self.b)
    
    def __setattr__(self, *ignored):
        raise NotImplementedError

    def __delattr__(self, *ignored):
        raise NotImplementedError

但是你可以通过self[0]和self[1]访问a和b变量,这很烦人。

这在Pure Python中可行吗?如果不是,我该如何用C扩展来做呢?

(只能在python3中工作的答案是可以接受的)。

更新:

从Python 3.7开始,要使用的方法是使用@dataclass装饰器,参见最新接受的答案。


当前回答

你可以在init的最后一条语句中重写setAttr。那么你可以构建,但不能改变。显然,你仍然可以用usint对象重写。但在实践中,大多数语言都有某种形式的反射,因此不可变始终是一个有漏洞的抽象。不可变性更多的是防止客户端意外地违反对象的契约。我使用:

=============================

最初提供的解决方案是不正确的,这是基于使用这里的解决方案的评论而更新的

原来的解决方案是错误的,这是一种有趣的方式,所以它被包括在底部。

===============================

class ImmutablePair(object):

    __initialised = False # a class level variable that should always stay false.
    def __init__(self, a, b):
        try :
            self.a = a
            self.b = b
        finally:
            self.__initialised = True #an instance level variable

    def __setattr__(self, key, value):
        if self.__initialised:
            self._raise_error()
        else :
            super(ImmutablePair, self).__setattr__(key, value)

    def _raise_error(self, *args, **kw):
        raise NotImplementedError("Attempted To Modify Immutable Object")

if __name__ == "__main__":

    immutable_object = ImmutablePair(1,2)

    print immutable_object.a
    print immutable_object.b

    try :
        immutable_object.a = 3
    except Exception as e:
        print e

    print immutable_object.a
    print immutable_object.b

输出:

1
2
Attempted To Modify Immutable Object
1
2

======================================

最初的实现:

评论中指出,这实际上是行不通的,因为它阻止了在重写类setattr方法时创建多个对象,这意味着不能作为self创建第二个对象。A =将在第二次初始化时失败。

class ImmutablePair(object):

    def __init__(self, a, b):
        self.a = a
        self.b = b
        ImmutablePair.__setattr__ = self._raise_error

    def _raise_error(self, *args, **kw):
        raise NotImplementedError("Attempted To Modify Immutable Object")

其他回答

所以,我在写python 3的相关内容:

I)借助数据类装饰器并设置frozen=True。 我们可以在python中创建不可变对象。

为此需要从data classes lib导入data class,并需要设置frozen=True

ex.

从数据类导入数据类

@dataclass(frozen=True)
class Location:
    name: str
    longitude: float = 0.0
    latitude: float = 0.0

o/p:

>>> l = Location("Delhi", 112.345, 234.788)
>>> l.name
'Delhi'
>>> l.longitude
112.345
>>> l.latitude
234.788
>>> l.name = "Kolkata"
dataclasses.FrozenInstanceError: cannot assign to field 'name'
>>> 

来源:https://realpython.com/python-data-classes/

从Python 3.7开始,你可以在你的类中使用@dataclass装饰器,它将像结构体一样是不可变的!不过,它可能会也可能不会将__hash__()方法添加到类中。引用:

hash() is used by built-in hash(), and when objects are added to hashed collections such as dictionaries and sets. Having a hash() implies that instances of the class are immutable. Mutability is a complicated property that depends on the programmer’s intent, the existence and behavior of eq(), and the values of the eq and frozen flags in the dataclass() decorator. By default, dataclass() will not implicitly add a hash() method unless it is safe to do so. Neither will it add or change an existing explicitly defined hash() method. Setting the class attribute hash = None has a specific meaning to Python, as described in the hash() documentation. If hash() is not explicit defined, or if it is set to None, then dataclass() may add an implicit hash() method. Although not recommended, you can force dataclass() to create a hash() method with unsafe_hash=True. This might be the case if your class is logically immutable but can nonetheless be mutated. This is a specialized use case and should be considered carefully.

下面是上面链接的文档中的例子:

@dataclass
class InventoryItem:
    '''Class for keeping track of an item in inventory.'''
    name: str
    unit_price: float
    quantity_on_hand: int = 0

    def total_cost(self) -> float:
        return self.unit_price * self.quantity_on_hand

继承自以下Immutable类的类,在它们的__init__方法执行完成后,它们的实例也是不可变的。正如其他人指出的那样,因为它是纯python,所以没有什么可以阻止某人使用来自基对象和类型的特殊方法的突变,但这足以阻止任何人意外地突变类/实例。

它通过用元类劫持类创建过程来工作。

"""Subclasses of class Immutable are immutable after their __init__ has run, in
the sense that all special methods with mutation semantics (in-place operators,
setattr, etc.) are forbidden.

"""  

# Enumerate the mutating special methods
mutation_methods = set()
# Arithmetic methods with in-place operations
iarithmetic = '''add sub mul div mod divmod pow neg pos abs bool invert lshift
                 rshift and xor or floordiv truediv matmul'''.split()
for op in iarithmetic:
    mutation_methods.add('__i%s__' % op)
# Operations on instance components (attributes, items, slices)
for verb in ['set', 'del']:
    for component in '''attr item slice'''.split():
        mutation_methods.add('__%s%s__' % (verb, component))
# Operations on properties
mutation_methods.update(['__set__', '__delete__'])


def checked_call(_self, name, method, *args, **kwargs):
    """Calls special method method(*args, **kw) on self if mutable."""
    self = args[0] if isinstance(_self, object) else _self
    if not getattr(self, '__mutable__', True):
        # self told us it's immutable, so raise an error
        cname= (self if isinstance(self, type) else self.__class__).__name__
        raise TypeError('%s is immutable, %s disallowed' % (cname, name))
    return method(*args, **kwargs)


def method_wrapper(_self, name):
    "Wrap a special method to check for mutability."
    method = getattr(_self, name)
    def wrapper(*args, **kwargs):
        return checked_call(_self, name, method, *args, **kwargs)
    wrapper.__name__ = name
    wrapper.__doc__ = method.__doc__
    return wrapper


def wrap_mutating_methods(_self):
    "Place the wrapper methods on mutative special methods of _self"
    for name in mutation_methods:
        if hasattr(_self, name):
            method = method_wrapper(_self, name)
            type.__setattr__(_self, name, method)


def set_mutability(self, ismutable):
    "Set __mutable__ by using the unprotected __setattr__"
    b = _MetaImmutable if isinstance(self, type) else Immutable
    super(b, self).__setattr__('__mutable__', ismutable)


class _MetaImmutable(type):

    '''The metaclass of Immutable. Wraps __init__ methods via __call__.'''

    def __init__(cls, *args, **kwargs):
        # Make class mutable for wrapping special methods
        set_mutability(cls, True)
        wrap_mutating_methods(cls)
        # Disable mutability
        set_mutability(cls, False)

    def __call__(cls, *args, **kwargs):
        '''Make an immutable instance of cls'''
        self = cls.__new__(cls)
        # Make the instance mutable for initialization
        set_mutability(self, True)
        # Execute cls's custom initialization on this instance
        self.__init__(*args, **kwargs)
        # Disable mutability
        set_mutability(self, False)
        return self

    # Given a class T(metaclass=_MetaImmutable), mutative special methods which
    # already exist on _MetaImmutable (a basic type) cannot be over-ridden
    # programmatically during _MetaImmutable's instantiation of T, because the
    # first place python looks for a method on an object is on the object's
    # __class__, and T.__class__ is _MetaImmutable. The two extant special
    # methods on a basic type are __setattr__ and __delattr__, so those have to
    # be explicitly overridden here.

    def __setattr__(cls, name, value):
        checked_call(cls, '__setattr__', type.__setattr__, cls, name, value)

    def __delattr__(cls, name, value):
        checked_call(cls, '__delattr__', type.__delattr__, cls, name, value)


class Immutable(object):

    """Inherit from this class to make an immutable object.

    __init__ methods of subclasses are executed by _MetaImmutable.__call__,
    which enables mutability for the duration.

    """

    __metaclass__ = _MetaImmutable


class T(int, Immutable):  # Checks it works with multiple inheritance, too.

    "Class for testing immutability semantics"

    def __init__(self, b):
        self.b = b

    @classmethod
    def class_mutation(cls):
        cls.a = 5

    def instance_mutation(self):
        self.c = 1

    def __iadd__(self, o):
        pass

    def not_so_special_mutation(self):
        self +=1

def immutabilityTest(f, name):
    "Call f, which should try to mutate class T or T instance."
    try:
        f()
    except TypeError, e:
        assert 'T is immutable, %s disallowed' % name in e.args
    else:
        raise RuntimeError('Immutability failed!')

immutabilityTest(T.class_mutation, '__setattr__')
immutabilityTest(T(6).instance_mutation, '__setattr__')
immutabilityTest(T(6).not_so_special_mutation, '__iadd__')

这种方式不停止对象。__setattr__从工作,但我仍然发现它有用:

class A(object):

    def __new__(cls, children, *args, **kwargs):
        self = super(A, cls).__new__(cls)
        self._frozen = False  # allow mutation from here to end of  __init__
        # other stuff you need to do in __new__ goes here
        return self

    def __init__(self, *args, **kwargs):
        super(A, self).__init__()
        self._frozen = True  # prevent future mutation

    def __setattr__(self, name, value):
        # need to special case setting _frozen.
        if name != '_frozen' and self._frozen:
            raise TypeError('Instances are immutable.')
        else:
            super(A, self).__setattr__(name, value)

    def __delattr__(self, name):
        if self._frozen:
            raise TypeError('Instances are immutable.')
        else:
            super(A, self).__delattr__(name)

你可能需要根据用例重写更多的东西(比如__setitem__)。

你可以在init的最后一条语句中重写setAttr。那么你可以构建,但不能改变。显然,你仍然可以用usint对象重写。但在实践中,大多数语言都有某种形式的反射,因此不可变始终是一个有漏洞的抽象。不可变性更多的是防止客户端意外地违反对象的契约。我使用:

=============================

最初提供的解决方案是不正确的,这是基于使用这里的解决方案的评论而更新的

原来的解决方案是错误的,这是一种有趣的方式,所以它被包括在底部。

===============================

class ImmutablePair(object):

    __initialised = False # a class level variable that should always stay false.
    def __init__(self, a, b):
        try :
            self.a = a
            self.b = b
        finally:
            self.__initialised = True #an instance level variable

    def __setattr__(self, key, value):
        if self.__initialised:
            self._raise_error()
        else :
            super(ImmutablePair, self).__setattr__(key, value)

    def _raise_error(self, *args, **kw):
        raise NotImplementedError("Attempted To Modify Immutable Object")

if __name__ == "__main__":

    immutable_object = ImmutablePair(1,2)

    print immutable_object.a
    print immutable_object.b

    try :
        immutable_object.a = 3
    except Exception as e:
        print e

    print immutable_object.a
    print immutable_object.b

输出:

1
2
Attempted To Modify Immutable Object
1
2

======================================

最初的实现:

评论中指出,这实际上是行不通的,因为它阻止了在重写类setattr方法时创建多个对象,这意味着不能作为self创建第二个对象。A =将在第二次初始化时失败。

class ImmutablePair(object):

    def __init__(self, a, b):
        self.a = a
        self.b = b
        ImmutablePair.__setattr__ = self._raise_error

    def _raise_error(self, *args, **kw):
        raise NotImplementedError("Attempted To Modify Immutable Object")