联合通常用于整数和浮点数的二进制表示之间的转换:

union
{
  int i;
  float f;
} u;

// Convert floating-point bits to integer:
u.f = 3.14159f;
printf("As integer: %08x\n", u.i);

尽管根据C标准，这在技术上是未定义的行为(您只应该阅读最近编写的字段)，但它将在几乎任何编译器中以定义良好的方式起作用。

联合有时也被用来实现C语言中的伪多态性，通过给一个结构一些标记来指示它包含什么类型的对象，然后将可能的类型联合在一起:

enum Type { INTS, FLOATS, DOUBLE };
struct S
{
  Type s_type;
  union
  {
    int s_ints[2];
    float s_floats[2];
    double s_double;
  };
};

void do_something(struct S *s)
{
  switch(s->s_type)
  {
    case INTS:  // do something with s->s_ints
      break;

    case FLOATS:  // do something with s->s_floats
      break;

    case DOUBLE:  // do something with s->s_double
      break;
  }
}

这使得struct S的大小只有12字节，而不是28字节。

联合在嵌入式编程或需要直接访问硬件/内存的情况下特别有用。这里有一个简单的例子:

typedef union
{
    struct {
        unsigned char byte1;
        unsigned char byte2;
        unsigned char byte3;
        unsigned char byte4;
    } bytes;
    unsigned int dword;
} HW_Register;
HW_Register reg;

然后，您可以按如下方式访问reg:

reg.dword = 0x12345678;
reg.bytes.byte3 = 4;

字节顺序和处理器体系结构当然很重要。

另一个有用的特性是位修饰符:

typedef union
{
    struct {
        unsigned char b1:1;
        unsigned char b2:1;
        unsigned char b3:1;
        unsigned char b4:1;
        unsigned char reserved:4;
    } bits;
    unsigned char byte;
} HW_RegisterB;
HW_RegisterB reg;

使用这段代码，您可以直接访问寄存器/内存地址中的单个位:

x = reg.bits.b2;

这里有一个来自我自己代码库的联合的例子(来自记忆和转述，所以可能不准确)。它被用来在我构建的解释器中存储语言元素。例如，以下代码:

set a to b times 7.

由以下语言元素组成:

[设置]符号 可变[a] 符号[到] 可变[b] 符号[时报] 康斯坦[7] 符号[。]

语言元素被定义为“#define”值，如下:

#define ELEM_SYM_SET        0
#define ELEM_SYM_TO         1
#define ELEM_SYM_TIMES      2
#define ELEM_SYM_FULLSTOP   3
#define ELEM_VARIABLE     100
#define ELEM_CONSTANT     101

下面的结构被用来存储每个元素:

typedef struct {
    int typ;
    union {
        char *str;
        int   val;
    }
} tElem;

然后，每个元素的大小是最大联合的大小(typ为4字节，联合为4字节，尽管这些是典型值，但实际大小取决于实现)。

为了创建一个“set”元素，你可以使用:

tElem e;
e.typ = ELEM_SYM_SET;

为了创建一个“variable[b]”元素，你可以使用:

tElem e;
e.typ = ELEM_VARIABLE;
e.str = strdup ("b");   // make sure you free this later

为了创建一个常量[7]元素，你可以使用:

tElem e;
e.typ = ELEM_CONSTANT;
e.val = 7;

你可以很容易地将其扩展为包含浮点数(float flt)或有理数(struct ratnl {int num;Int denom;})和其他类型。

基本前提是str和val在内存中不是连续的，它们实际上是重叠的，所以这是一种在同一块内存上获得不同视图的方法，如图所示，其中结构基于内存位置0x1010，整数和指针都是4字节:

       +-----------+
0x1010 |           |
0x1011 |    typ    |
0x1012 |           |
0x1013 |           |
       +-----+-----+
0x1014 |     |     |
0x1015 | str | val |
0x1016 |     |     |
0x1017 |     |     |
       +-----+-----+

如果只是在一个结构中，它看起来会是这样的:

       +-------+
0x1010 |       |
0x1011 |  typ  |
0x1012 |       |
0x1013 |       |
       +-------+
0x1014 |       |
0x1015 |  str  |
0x1016 |       |
0x1017 |       |
       +-------+
0x1018 |       |
0x1019 |  val  |
0x101A |       |
0x101B |       |
       +-------+

在C的早期版本中，所有结构声明都共享一组公共字段。考虑到:

struct x {int x_mode; int q; float x_f};
struct y {int y_mode; int q; int y_l};
struct z {int z_mode; char name[20];};

a compiler would essentially produce a table of structures' sizes (and possibly alignments), and a separate table of structures' members' names, types, and offsets. The compiler didn't keep track of which members belonged to which structures, and would allow two structures to have a member with the same name only if the type and offset matched (as with member q of struct x and struct y). If p was a pointer to any structure type, p->q would add the offset of "q" to pointer p and fetch an "int" from the resulting address.

Given the above semantics, it was possible to write a function that could perform some useful operations on multiple kinds of structure interchangeably, provided that all the fields used by the function lined up with useful fields within the structures in question. This was a useful feature, and changing C to validate members used for structure access against the types of the structures in question would have meant losing it in the absence of a means of having a structure that can contain multiple named fields at the same address. Adding "union" types to C helped fill that gap somewhat (though not, IMHO, as well as it should have been).

An essential part of unions' ability to fill that gap was the fact that a pointer to a union member could be converted into a pointer to any union containing that member, and a pointer to any union could be converted to a pointer to any member. While the C89 Standard didn't expressly say that casting a T* directly to a U* was equivalent to casting it to a pointer to any union type containing both T and U, and then casting that to U*, no defined behavior of the latter cast sequence would be affected by the union type used, and the Standard didn't specify any contrary semantics for a direct cast from T to U. Further, in cases where a function received a pointer of unknown origin, the behavior of writing an object via T*, converting the T* to a U*, and then reading the object via U* would be equivalent to writing a union via member of type T and reading as type U, which would be standard-defined in a few cases (e.g. when accessing Common Initial Sequence members) and Implementation-Defined (rather than Undefined) for the rest. While it was rare for programs to exploit the CIS guarantees with actual objects of union type, it was far more common to exploit the fact that pointers to objects of unknown origin had to behave like pointers to union members and have the behavioral guarantees associated therewith.

联合用于节省内存，特别是在内存有限的设备上使用，而内存是很重要的。 经验值:

union _Union{
  int a;
  double b;
  char c;
};

For example,let's say we need the above 3 data types(int,double,char) in a system where memory is limited.If we don't use "union",we need to define these 3 data types. In this case sizeof(a) + sizeof(b) + sizeof(c) memory space will be allocated.But if we use onion,only one memory space will be allocated according to the largest data t ype in these 3 data types.Because all variables in union structure will use the same memory space. Hence the memory space allocated accroding to the largest data type will be common space for all variables. For example:

union _Union{
int a;
double b;
char c;
};

int main() {
 union _Union uni;
 uni.a = 44;
 uni.b = 144.5;
 printf("a:%d\n",uni.a);
 printf("b:%lf\n",uni.b);
 return 0;
 }

输出是: 答:0 和b: 144.500000

为什么a是0 ?因为联合结构只有一个内存区域，而所有数据结构都共同使用它。最后一个赋值覆盖了旧值。 再举一个例子:

 union _Union{
    char name[15];
    int id;
};


int main(){
   union _Union uni;
   char choice;
   printf("YOu can enter name or id value.");
   printf("Do you want to enter the name(y or n):");
   scanf("%c",&choice);
   if(choice == 'Y' || choice == 'y'){
     printf("Enter name:");
     scanf("%s",uni.name);
     printf("\nName:%s",uni.name);
   }else{
     printf("Enter Id:");
     scanf("%d",&uni.id);
     printf("\nId:%d",uni.id);
   }
return 0;
}

注意:联合的大小是其最大字段的大小，因为必须保留足够的字节来存储大尺寸字段。

联合允许互斥的数据成员共享相同的内存。当内存比较稀缺时，例如在嵌入式系统中，这是非常重要的。

示例如下:

union {
   int a;
   int b;
   int c;
} myUnion;

这个联合将占用一个int值的空间，而不是3个独立的int值。如果用户设置了a的值，然后设置了b的值，它将覆盖a的值，因为它们都共享相同的内存位置。