我有以下YAML:

paths:
  patha: /path/to/root/a
  pathb: /path/to/root/b
  pathc: /path/to/root/c

我如何“正常化”它,通过从三个路径中删除/path/到/root/,并将其作为自己的设置,类似于:

paths:
  root: /path/to/root/
  patha: *root* + a
  pathb: *root* + b
  pathc: *root* + c

显然这是无效的,我瞎编的。真正的语法是什么?这能做到吗?


当前回答

另一种方法是简单地使用另一个字段。

paths:
  root_path: &root
     val: /path/to/root/
  patha: &a
    root_path: *root
    rel_path: a
  pathb: &b
    root_path: *root
    rel_path: b
  pathc: &c
    root_path: *root
    rel_path: c

其他回答

我已经创建了一个库,在Packagist上可用,执行这个函数: https://packagist.org/packages/grasmash/yaml-expander

YAML文件示例:

type: book
book:
  title: Dune
  author: Frank Herbert
  copyright: ${book.author} 1965
  protaganist: ${characters.0.name}
  media:
    - hardcover
characters:
  - name: Paul Atreides
    occupation: Kwisatz Haderach
    aliases:
      - Usul
      - Muad'Dib
      - The Preacher
  - name: Duncan Idaho
    occupation: Swordmaster
summary: ${book.title} by ${book.author}
product-name: ${${type}.title}

例子逻辑:

// Parse a yaml string directly, expanding internal property references.
$yaml_string = file_get_contents("dune.yml");
$expanded = \Grasmash\YamlExpander\Expander::parse($yaml_string);
print_r($expanded);

结果数组:

array (
  'type' => 'book',
  'book' => 
  array (
    'title' => 'Dune',
    'author' => 'Frank Herbert',
    'copyright' => 'Frank Herbert 1965',
    'protaganist' => 'Paul Atreides',
    'media' => 
    array (
      0 => 'hardcover',
    ),
  ),
  'characters' => 
  array (
    0 => 
    array (
      'name' => 'Paul Atreides',
      'occupation' => 'Kwisatz Haderach',
      'aliases' => 
      array (
        0 => 'Usul',
        1 => 'Muad\'Dib',
        2 => 'The Preacher',
      ),
    ),
    1 => 
    array (
      'name' => 'Duncan Idaho',
      'occupation' => 'Swordmaster',
    ),
  ),
  'summary' => 'Dune by Frank Herbert',
);

YML定义:

dir:
  default: /home/data/in/
  proj1: ${dir.default}p1
  proj2: ${dir.default}p2
  proj3: ${dir.default}p3 

在百里叶的某个地方

<p th:utext='${@environment.getProperty("dir.default")}' />
<p th:utext='${@environment.getProperty("dir.proj1")}' /> 

输出: / home /数据/ in / / home /数据/ in / p1

您的示例无效只是因为您选择了一个保留字符作为标量的开头。如果你用其他非保留字符替换*(我倾向于使用非ascii字符,因为它们很少被用作某些规范的一部分),你最终会得到完全合法的YAML:

paths:
  root: /path/to/root/
  patha: ♦root♦ + a
  pathb: ♦root♦ + b
  pathc: ♦root♦ + c

这将加载到解析器使用的语言中映射的标准表示形式中,并且不会神奇地展开任何内容。 为此,使用本地默认的对象类型,如下面的Python程序所示:

# coding: utf-8

from __future__ import print_function

import ruamel.yaml as yaml

class Paths:
    def __init__(self):
        self.d = {}

    def __repr__(self):
        return repr(self.d).replace('ordereddict', 'Paths')

    @staticmethod
    def __yaml_in__(loader, data):
        result = Paths()
        loader.construct_mapping(data, result.d)
        return result

    @staticmethod
    def __yaml_out__(dumper, self):
        return dumper.represent_mapping('!Paths', self.d)

    def __getitem__(self, key):
        res = self.d[key]
        return self.expand(res)

    def expand(self, res):
        try:
            before, rest = res.split(u'♦', 1)
            kw, rest = rest.split(u'♦ +', 1)
            rest = rest.lstrip() # strip any spaces after "+"
            # the lookup will throw the correct keyerror if kw is not found
            # recursive call expand() on the tail if there are multiple
            # parts to replace
            return before + self.d[kw] + self.expand(rest)
        except ValueError:
            return res

yaml_str = """\
paths: !Paths
  root: /path/to/root/
  patha: ♦root♦ + a
  pathb: ♦root♦ + b
  pathc: ♦root♦ + c
"""

loader = yaml.RoundTripLoader
loader.add_constructor('!Paths', Paths.__yaml_in__)

paths = yaml.load(yaml_str, Loader=yaml.RoundTripLoader)['paths']

for k in ['root', 'pathc']:
    print(u'{} -> {}'.format(k, paths[k]))

这将打印:

root -> /path/to/root/
pathc -> /path/to/root/c

展开是动态完成的,并处理嵌套定义,但必须注意不要调用无限递归。

通过指定转储器,你可以从加载的数据中转储原始的YAML,因为动态扩展:

dumper = yaml.RoundTripDumper
dumper.add_representer(Paths, Paths.__yaml_out__)
print(yaml.dump(paths, Dumper=dumper, allow_unicode=True))

这将改变映射键的顺序。如果你有这个问题的话 成就自我。d一个commenttedmap(从ruame .yaml.comments.py导入)

我用Python编写了自己的库来扩展从目录中加载的变量,其层次结构如下:

/root
 |
 +- /proj1
     |
     +- config.yaml
     |
     +- /proj2
         |
         +- config.yaml
         |
         ... and so on ...

这里的关键区别是,扩展必须在所有配置完成后才应用。Yaml文件被加载,其中来自下一个文件的变量可以覆盖来自前一个文件的变量,所以伪代码应该是这样的:

env = YamlEnv()
env.load('/root/proj1/config.yaml')
env.load('/root/proj1/proj2/config.yaml')
...
env.expand()

作为一个附加选项,xonsh脚本可以将结果变量导出到环境变量中(请参阅yaml_update_global_vars函数)。

脚本:

https://sourceforge.net/p/tacklelib/tacklelib/HEAD/tree/trunk/python/cmdoplib/cmdoplib.yaml.xsh https://sourceforge.net/p/tacklelib/tacklelib/HEAD/tree/trunk/python/tacklelib/tacklelib.yaml.py

优点:

简单,不支持递归和嵌套变量 可以将未定义的变量替换为占位符(${MYUNDEFINEDVAR} -> *$/{MYUNDEFINEDVAR}) 可以从环境变量(${env:MYVAR} ${env:MYVAR:path}可以替换所有的\\ to / in路径变量

缺点:

不支持嵌套变量,因此不能展开嵌套字典中的值(例如${MYSCOPE. xml)。MYVAR}未实现) 不检测展开递归,包括递归后的占位符放

另一种方法是简单地使用另一个字段。

paths:
  root_path: &root
     val: /path/to/root/
  patha: &a
    root_path: *root
    rel_path: a
  pathb: &b
    root_path: *root
    rel_path: b
  pathc: &c
    root_path: *root
    rel_path: c