是否有一个Python函数将从字符串中删除空白(空格和制表符)?
所以给定的输入" \t example string\t "变成了"example string"
是否有一个Python函数将从字符串中删除空白(空格和制表符)?
所以给定的输入" \t example string\t "变成了"example string"
当前回答
一般来说,我使用的方法如下:
>>> myStr = "Hi\n Stack Over \r flow!"
>>> charList = [u"\u005Cn",u"\u005Cr",u"\u005Ct"]
>>> import re
>>> for i in charList:
myStr = re.sub(i, r"", myStr)
>>> myStr
'Hi Stack Over flow'
注意:这只用于删除“\n”,“\r”和“\t”。它不会删除额外的空格。
其他回答
前导空格和尾随空格:
s = ' foo \t '
print s.strip() # prints "foo"
否则,正则表达式工作:
import re
pat = re.compile(r'\s+')
s = ' \t foo \t bar \t '
print pat.sub('', s) # prints "foobar"
something = "\t please_ \t remove_ all_ \n\n\n\nwhitespaces\n\t "
something = "".join(something.split())
输出:
please_remove_all_whitespaces
将Le Droid的评论添加到答案中。 用空格隔开:
something = "\t please \t remove all extra \n\n\n\nwhitespaces\n\t "
something = " ".join(something.split())
输出:
请删除所有额外的空格
#how to trim a multi line string or a file
s=""" line one
\tline two\t
line three """
#line1 starts with a space, #2 starts and ends with a tab, #3 ends with a space.
s1=s.splitlines()
print s1
[' line one', '\tline two\t', 'line three ']
print [i.strip() for i in s1]
['line one', 'line two', 'line three']
#more details:
#we could also have used a forloop from the begining:
for line in s.splitlines():
line=line.strip()
process(line)
#we could also be reading a file line by line.. e.g. my_file=open(filename), or with open(filename) as myfile:
for line in my_file:
line=line.strip()
process(line)
#moot point: note splitlines() removed the newline characters, we can keep them by passing True:
#although split() will then remove them anyway..
s2=s.splitlines(True)
print s2
[' line one\n', '\tline two\t\n', 'line three ']
在Python中,trim方法被命名为strip:
str.strip() # trim
str.lstrip() # left trim
str.rstrip() # right trim
你也可以使用非常简单的基本函数:str.replace(),用于空格和制表符:
>>> whitespaces = " abcd ef gh ijkl "
>>> tabs = " abcde fgh ijkl"
>>> print whitespaces.replace(" ", "")
abcdefghijkl
>>> print tabs.replace(" ", "")
abcdefghijkl
简单易行。