试着翻译

>>> import string
>>> print '\t\r\n  hello \r\n world \t\r\n'

  hello 
 world  
>>> tr = string.maketrans(string.whitespace, ' '*len(string.whitespace))
>>> '\t\r\n  hello \r\n world \t\r\n'.translate(tr)
'     hello    world    '
>>> '\t\r\n  hello \r\n world \t\r\n'.translate(tr).replace(' ', '')
'helloworld'

如果使用Python 3:在打印语句中，以sep=""结束。这样就把所有的空格分开了。

例子:

txt="potatoes"
print("I love ",txt,"",sep="")

这将打印: 我喜欢土豆。

而不是: 我喜欢土豆。

在您的情况下，由于您将试图获得\t，执行sep="\t"

如果你想去掉字符串开头和结尾的空白，你可以这样做:

some_string = "    Hello,    world!\n    "
new_string = some_string.strip()
# new_string is now "Hello,    world!"

这很像Qt的QString::()方法，因为它删除了开头和结尾的空白，而只保留内部空白。

但是，如果你想使用Qt的QString::simplified()方法，它不仅删除开头和结尾的空白，而且还将所有连续的内部空白“压缩”为一个空格字符，你可以使用.split()和" "的组合。像这样加入:

some_string = "\t    Hello,  \n\t  world!\n    "
new_string = " ".join(some_string.split())
# new_string is now "Hello, world!"

在最后一个示例中，每个内部空格序列都被替换为单个空格，同时仍然将字符串的开头和结尾的空白删除。

#how to trim a multi line string or a file

s=""" line one
\tline two\t
line three """

#line1 starts with a space, #2 starts and ends with a tab, #3 ends with a space.

s1=s.splitlines()
print s1
[' line one', '\tline two\t', 'line three ']

print [i.strip() for i in s1]
['line one', 'line two', 'line three']




#more details:

#we could also have used a forloop from the begining:
for line in s.splitlines():
    line=line.strip()
    process(line)

#we could also be reading a file line by line.. e.g. my_file=open(filename), or with open(filename) as myfile:
for line in my_file:
    line=line.strip()
    process(line)

#moot point: note splitlines() removed the newline characters, we can keep them by passing True:
#although split() will then remove them anyway..
s2=s.splitlines(True)
print s2
[' line one\n', '\tline two\t\n', 'line three ']

在Python中，trim方法被命名为strip:

str.strip()  # trim
str.lstrip()  # left trim
str.rstrip()  # right trim

一般来说，我使用的方法如下:

>>> myStr = "Hi\n Stack Over \r flow!"
>>> charList = [u"\u005Cn",u"\u005Cr",u"\u005Ct"]
>>> import re
>>> for i in charList:
        myStr = re.sub(i, r"", myStr)

>>> myStr
'Hi Stack Over  flow'

注意:这只用于删除“\n”，“\r”和“\t”。它不会删除额外的空格。