使用模板字面量' ${}'可以返回一个包含许多值和变量的字符串

如:

var newCodes = function() {  
    var dCodes = fg.codecsCodes.rs;
    var dCodes2 = fg.codecsCodes2.rs;
    return `${dCodes}, ${dCodes2}`;
};

它既简短又简单。

几天前，我有类似的要求，从我创建的函数中获得多个返回值。

从许多返回值，我需要它只返回特定的值为一个给定的条件，然后其他返回值对应于其他条件。

以下是我如何做到这一点的例子:

功能:

function myTodayDate(){
    var today = new Date();
    var day = ["Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"];
    var month = ["January","February","March","April","May","June","July","August","September","October","November","December"];
    var myTodayObj = 
    {
        myDate : today.getDate(),
        myDay : day[today.getDay()],
        myMonth : month[today.getMonth()],
        year : today.getFullYear()
    }
    return myTodayObj;
}

从函数返回的对象获取所需的返回值:

var todayDate = myTodayDate().myDate;
var todayDay = myTodayDate().myDay;
var todayMonth = myTodayDate().myMonth;
var todayYear = myTodayDate().year;

回答这个问题的关键是分享以良好格式获取Date的方法。希望对你有所帮助:)

我建议使用最新的解构赋值(但要确保它在您的环境中得到支持)

var newCodes = function () {
    var dCodes = fg.codecsCodes.rs;
    var dCodes2 = fg.codecsCodes2.rs;
    return {firstCodes: dCodes, secondCodes: dCodes2};
};
var {firstCodes, secondCodes} = newCodes()

从ES6开始，你可以这样做

let newCodes = function() {  
    const dCodes = fg.codecsCodes.rs
    const dCodes2 = fg.codecsCodes2.rs
    return {dCodes, dCodes2}
};

let {dCodes, dCodes2} = newCodes()

返回表达式{dCodes, dCodes2}是属性值的简写，等价于这个{dCodes: dCodes, dCodes2: dCodes2}。

最后一行的赋值叫做对象析构赋值。它提取对象的属性值并将其赋值给同名变量。如果你想把返回值赋给不同名称的变量，你可以这样做let {dCodes: x, dCodes2: y} = newCodes()

function a(){
  var d = 2;
  var c = 3;
  var f = 4;
  return {d: d, c: c, f: f};
}

然后使用

const {d, c, f} = a();

新版本:

function a(){
  var d = 2;
  var c = 3;
  var f = 4;
  return {d, c, f}
}

我并不是在这里添加新内容，而是另一种替代方法。

 var newCodes = function() {
     var dCodes = fg.codecsCodes.rs;
     var dCodes2 = fg.codecsCodes2.rs;
     let [...val] = [dCodes,dCodes2];
     return [...val];
 };