在c#中将字符串转换为枚举值的最佳方法是什么?

我有一个包含枚举值的HTML选择标记。当页面被发布时,我想获取值(将以字符串的形式)并将其转换为相应的枚举值。

在理想的情况下,我可以这样做:

StatusEnum MyStatus = StatusEnum.Parse("Active");

但这不是有效的代码。


当前回答

public static T ParseEnum<T>(string value)            //function declaration  
{
    return (T) Enum.Parse(typeof(T), value);
}

Importance imp = EnumUtil.ParseEnum<Importance>("Active");   //function call

==================== 一个完整的程序 ====================

using System;

class Program
{
    enum PetType
    {
    None,
    Cat = 1,
    Dog = 2
    }

    static void Main()
    {

    // Possible user input:
    string value = "Dog";

    // Try to convert the string to an enum:
    PetType pet = (PetType)Enum.Parse(typeof(PetType), value);

    // See if the conversion succeeded:
    if (pet == PetType.Dog)
    {
        Console.WriteLine("Equals dog.");
    }
    }
}
-------------
Output

Equals dog.

其他回答

使用TryParse的超级简单代码:

var value = "Active";

StatusEnum status;
if (!Enum.TryParse<StatusEnum>(value, out status))
    status = StatusEnum.Unknown;

你现在可以使用扩展方法了:

public static T ToEnum<T>(this string value, bool ignoreCase = true)
{
    return (T) Enum.Parse(typeof (T), value, ignoreCase);
}

你可以通过下面的代码调用它们(在这里,FilterType是一个枚举类型):

FilterType filterType = type.ToEnum<FilterType>();

如果属性名与你想要调用它的名称不同(即语言差异),你可以这样做:

MyType.cs

using System;
using System.Runtime.Serialization;
using Newtonsoft.Json;
using Newtonsoft.Json.Converters;

[JsonConverter(typeof(StringEnumConverter))]
public enum MyType
{
    [EnumMember(Value = "person")]
    Person,
    [EnumMember(Value = "annan_deltagare")]
    OtherPerson,
    [EnumMember(Value = "regel")]
    Rule,
}

EnumExtensions.cs

using System;
using Newtonsoft.Json;
using Newtonsoft.Json.Converters;

public static class EnumExtensions
{
    public static TEnum ToEnum<TEnum>(this string value) where TEnum : Enum
    {
        var jsonString = $"'{value.ToLower()}'";
        return JsonConvert.DeserializeObject<TEnum>(jsonString, new StringEnumConverter());
    }

    public static bool EqualsTo<TEnum>(this string strA, TEnum enumB) where TEnum : Enum
    {
        TEnum enumA;
        try
        {
            enumA = strA.ToEnum<TEnum>();
        }
        catch
        {
            return false;
        }
        return enumA.Equals(enumB);
    }
}

Program.cs

public class Program
{
    static public void Main(String[] args) 
    { 
        var myString = "annan_deltagare";
        var myType = myString.ToEnum<MyType>();
        var isEqual = myString.EqualsTo(MyType.OtherPerson);
        //Output: true
    }     
}

我喜欢扩展方法的解决方案。

namespace System
{
    public static class StringExtensions
    {

        public static bool TryParseAsEnum<T>(this string value, out T output) where T : struct
        {
            T result;

            var isEnum = Enum.TryParse(value, out result);

            output = isEnum ? result : default(T);

            return isEnum;
        }
    }
}

下面是我的测试实现。

using static Microsoft.VisualStudio.TestTools.UnitTesting.Assert;
using static System.Console;

private enum Countries
    {
        NorthAmerica,
        Europe,
        Rusia,
        Brasil,
        China,
        Asia,
        Australia
    }

   [TestMethod]
        public void StringExtensions_On_TryParseAsEnum()
        {
            var countryName = "Rusia";

            Countries country;
            var isCountry = countryName.TryParseAsEnum(out country);

            WriteLine(country);

            IsTrue(isCountry);
            AreEqual(Countries.Rusia, country);

            countryName = "Don't exist";

            isCountry = countryName.TryParseAsEnum(out country);

            WriteLine(country);

            IsFalse(isCountry);
            AreEqual(Countries.NorthAmerica, country); // the 1rst one in the enumeration
        }

我们不能假设输入是完全有效的,于是就用了@Keith的答案的变体:

public static TEnum ParseEnum<TEnum>(string value) where TEnum : struct
{
    TEnum tmp; 
    if (!Enum.TryParse<TEnum>(value, true, out tmp))
    {
        tmp = new TEnum();
    }
    return tmp;
}