我需要从字符串中删除所有特殊字符,标点符号和空格,以便我只有字母和数字。


当前回答

假设你想要使用正则表达式并且你想要/需要unicode - cognant 2。X代码是2to3-ready:

>>> import re
>>> rx = re.compile(u'[\W_]+', re.UNICODE)
>>> data = u''.join(unichr(i) for i in range(256))
>>> rx.sub(u'', data)
u'0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz\xaa\xb2 [snip] \xfe\xff'
>>>

其他回答

较短的方法:

import re
cleanString = re.sub('\W+','', string )

如果你想在单词和数字之间有空格,用''代替''

import re
my_string = """Strings are amongst the most popular data types in Python. We can create the strings by enclosing characters in quotes. Python treats single quotes the 

和双引号一样。”""

# if we need to count the word python that ends with or without ',' or '.' at end

count = 0
for i in text:
    if i.endswith("."):
        text[count] = re.sub("^([a-z]+)(.)?$", r"\1", i)
    count += 1
print("The count of Python : ", text.count("python"))

最通用的方法是使用unicodedata表的“类别”,它对每个字符进行分类。例如,下面的代码只过滤基于类别的可打印字符:

import unicodedata
# strip of crap characters (based on the Unicode database
# categorization:
# http://www.sql-und-xml.de/unicode-database/#kategorien

PRINTABLE = set(('Lu', 'Ll', 'Nd', 'Zs'))

def filter_non_printable(s):
    result = []
    ws_last = False
    for c in s:
        c = unicodedata.category(c) in PRINTABLE and c or u'#'
        result.append(c)
    return u''.join(result).replace(u'#', u' ')

查看上面给出的所有相关类别的URL。当然你也可以过滤 按标点符号分类。

import re
abc = "askhnl#$%askdjalsdk"
ddd = abc.replace("#$%","")
print (ddd)

你会看到你的结果是

'Askhnlaskdjalsdk

function regexFuntion(st) {
  const regx = /[^\w\s]/gi; // allow : [a-zA-Z0-9, space]
  st = st.replace(regx, ''); // remove all data without [a-zA-Z0-9, space]
  st = st.replace(/\s\s+/g, ' '); // remove multiple space

  return st;
}

console.log(regexFuntion('$Hello; # -world--78asdf+-===asdflkj******lkjasdfj67;'));
// Output: Hello world78asdfasdflkjlkjasdfj67